/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 A \(5000-\mathrm{kg}\) open trai... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(5000-\mathrm{kg}\) open train car is rolling at a speed of \(20.0 \mathrm{~m} / \mathrm{s}\) when it begins to rain heavily and \(200 \mathrm{~kg}\) of water collects quickly in the car. If only the total mass has changed, what is the speed of the flooded train car? For simplicity, assume that all of the water collects at one instant, and that the train tracks are frictionless.

Short Answer

Expert verified
The speed of flooded train car is approximately 19.23 m/s.

Step by step solution

01

Understand Conservation of Linear Momentum

Linear momentum is conserved when no external forces act on a system. This means the total linear momentum before the collection of water will be equal to the total linear momentum after the collection of water. The linear momentum is obtained by the product of mass and velocity.
02

Calculate Initial Momentum

The initial momentum (before water collection) of the train is the product of its mass and velocity. In this case: Momentum_initial = Mass_train x Velocity_train = 5000 kg x 20 m/s = 100000 kg.m/s.
03

Find Total Mass after Water Collects

When the water collects in the train car, the total mass increases by the mass of the water, so: Mass_total = Mass_train + Mass_water = 5000 kg + 200 kg = 5200 kg.
04

Calculate Final Speed Using Conservation of Momentum

According to conservation of momentum, the momentum before the water collection equals the momentum after the water collection, thus: Momentum_initial = Momentum_final = Mass_total x Velocity_final. Divide both sides of the equation by Mass_total to solve for Velocity_final. Therefore, Velocity_final = Momentum_initial / Mass_total.
05

Insert Values and Solve for Final Speed

Substituting the given values in the Velocity_final equation: Velocity_final = 100000 kg.m/s / 5200 kg = 19.23 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Momentum
Linear momentum is a fundamental concept in physics that describes the motion of objects. It can be thought of as a measure of an object's tendency to move in a straight line. The linear momentum of an object is the product of its mass and velocity. This is expressed mathematically using the formula: \[ p = m \cdot v \] where \( p \) is the momentum, \( m \) is the mass, and \( v \) is the velocity.

In an isolated system, where no external forces are acting, the total linear momentum is conserved. This principle of conservation of momentum is especially useful in solving collision and interaction problems, such as the train car example, where the mass and velocity determine the changes in the system's motion.
Physics Problem Solving
Physics problem solving often involves identifying key principles that apply to a given situation and using them systematically. Let's break down the process used in the train car exercise:
  • **Understanding the problem:** Identify the objects involved and determine which principles apply, such as conservation of momentum.
  • **Setting up equations:** Use the principles to write equations that describe the situation. For example, equate initial and final momentum for conservation of momentum.
  • **Solving the equations:** Manipulate the equations algebraically or plug in known values to find the unknown quantity, such as the final speed in this exercise.
  • **Checking the solution:** Verify the results are reasonable based on known physical laws and the problem's context.
This methodical approach allows for the effective and efficient solution of a wide range of physics problems.
Frictionless Surfaces
In physics, a frictionless surface is an idealized concept where there is no resistance to movement between surfaces in contact. It allows for the simplification of problems by eliminating frictional forces, enabling the direct application of concepts like conservation of momentum.

In the train car problem, the tracks are considered frictionless, meaning the train can move without any loss of speed due to friction. This simplifies the calculations because we do not need to account for forces that would otherwise slow down the train. Without external forces acting on the train, the momentum of the system remains constant, thus purely influenced by changes in mass and velocity.
Mass-Velocity Relationship
The relation between mass and velocity is crucial in understanding how momentum changes when mass changes in a system. In the context of the open train car problem, we're dealing with the mass-velocity relationship because the train's velocity changes upon collecting additional mass from the rain.

When mass is added, velocity must adjust to conserve momentum. Initially, the train moves with a momentum of \(100000 \, \text{kg.m/s}\). After rain adds \(200 \, \text{kg}\) of mass, the system's total mass becomes \(5200 \, \text{kg}\). With no external forces, the linear momentum remains unchanged. To find the new velocity (\(v_f\)), use the conservation of momentum: \[ v_f = \frac{p}{m} = \frac{100000 \, \text{kg.m/s}}{5200 \, \text{kg}} \approx 19.23 \, \text{m/s} \] This calculation shows how added mass decreases velocity under momentum conservation, illustrating the mass-velocity relationship.

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Most popular questions from this chapter

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