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The force that acts on an object is given by \(\vec{F}=2.2 \hat{x}+4.5 \hat{y}\). Calculate the work done on the object when the force results in a displacement given by \(\vec{d}=12 \hat{x}+20 y\). (The multiplicative constants in both expressions carry SI units.)

Short Answer

Expert verified
The work done is 116.4 Joules.

Step by step solution

01

- Establish the Vectors

The force vector is given as \(\vec{F}=2.2 \hat{x}+4.5\hat{y}\) and the displacement vector is given as \(\vec{d}=12 \hat{x}+20 \hat{y}\).
02

- Dot Product

The work done is given by the dot product of the force vector \(\vec{F}\) and the displacement vector \(\vec{d}\). In the Cartesian coordinate system, the dot product of two vectors \(\vec{A}=A_x \hat{x}+A_y \hat{y}\) and \(\vec{B}=B_x \hat{x}+B_y \hat{y}\) is given by \(\vec{A}.\vec{B}=A_x B_x+A_y B_y\). So, substitute the values of \(\vec{F}\) and \(\vec{d}\) into the equation to get: Work = \(\vec{F}.\vec{d} = (2.2*12) + (4.5*20)\).
03

- Calculate Work

Calculate the work by carrying out the multiplication and summation. Work = \(26.4 + 90 = 116.4\) Joules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Calculus
Vector Calculus is an essential part of understanding forces and movements in physics. Vectors are mathematical objects used to represent quantities that have both a magnitude and a direction. In the case of forces and displacements, vectors allow us to quantify these physical phenomena comprehensively. When you have two or more vectors, Vector Calculus helps you perform mathematical operations like addition, subtraction, and multiplication on them.
For instance, if a force vector \( \vec{F} \) is acting on an object, and the object is displaced by a displacement vector \( \vec{d} \), using vectors becomes vital. You can find the effective force in specific directions, combine multiple vectors into a resultant vector, and calculate work done. Calculating work involves the dot product, which is a significant operation in Vector Calculus.
In this problem, we represented the force as \( \vec{F}=2.2 \hat{x}+4.5\hat{y} \) and the displacement as \( \vec{d}=12 \hat{x}+20 \hat{y} \). Recognizing these as vectors is crucial because it allows us to use Vector Calculus tools to compute work efficiently.
Dot Product
The Dot Product of two vectors is a critical concept. It bridges geometry and algebra, providing a way to multiply two vectors and get a scalar. A scalar is a single number, having magnitude but no direction. To calculate the Dot Product of two vectors, you multiply their corresponding components and add those products together.
For vectors \( \vec{A}=A_x \hat{x}+A_y \hat{y} \) and \( \vec{B}=B_x \hat{x}+B_y \hat{y} \), the formula for their Dot Product is \( \vec{A} \cdot \vec{B} = A_x B_x + A_y B_y \). This operation simplifies working with vectors and is used to calculate the work done by a force when it causes displacement.
In our problem, we use the dot product of the force \( \vec{F}=2.2 \hat{x}+4.5\hat{y} \) and displacement \( \vec{d}=12 \hat{x}+20 \hat{y} \) to compute work. Substituting their components into the dot product gives us \( \vec{F} \cdot \vec{d} = (2.2 \times 12) + (4.5 \times 20) = 116.4 \) Joules. This shows how efficiently the force transfers energy to move the object.
Physics Problems
Physics Problems often involve understanding the physical principles and applying mathematical techniques to find a solution. These problems require a good grasp of both concepts and calculations. In tasks like calculating work done, they demand knowledge of Vector Calculus and the Dot Product.
Solving physics problems helps in visualizing scenarios and applying the right methods to solve them. Once we identify the given and required data, we use mathematical tools to bridge the gap between them.
In this exercise, you first need to recognize the given vectors and their components. Then, by applying the dot product, a core vector calculus technique, you determine the amount of energy or work done as a result of the force applied. By calculating \( 116.4 \) Joules of work, we understand how force translates into energy. Engaging with physics problems enhances problem-solving skills, fostering the ability to apply science in practical settings.

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Most popular questions from this chapter

The potential energy of an electron in an atom is given approximately by \(U(r)=a / r^{6}-b / r^{12}\), where \(a\) and \(b\) are positive constants. Find the force \(F(r)\) exerted on the electron. Hint: The relationship between force and potential, Equation 6-23, can be written \(F(r)=-d U / d r\). (b) Find the units of the two constants, \(a\) and \(b\).

Your roommate lifts a cement block and carries it across the room. Is the net work done by her on the block positive, negative, or zero? Explain your answer.

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