/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 Calc Determine the following ind... [FREE SOLUTION] | 91Ó°ÊÓ

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Calc Determine the following indefinite integrals (ignore any integration constants): (a) \(\int 6 t d t\) (b) \(\int\left(5 t^{4}+3 t^{2}+2 t\right) d t\)

Short Answer

Expert verified
The solution for the integral \( \int 6 t dt\) is \(3t^{2}\) and the solution for the integral \( \int(5 t^{4}+3 t^{2}+2 t) dt\) is \(t^{5} + t^{3} + t^{2}\).

Step by step solution

01

Simple Integration

Start with the first integral \(\int 6 t dt\). Use the power rule to perform the integration process: apply \(t^{(m+1)}/(m+1)\) with m=1 in this case. After integrating, the solution is \(6 * t^{(1+1)}/(1+1) = 3t^{2}\)
02

Integrating Polynomial Function

Next, consider the integral \(\int(5 t^{4}+3 t^{2}+2 t) dt\). Begin by applying the rule to each term separately. The result is \(5 * t^{(4+1)}/(4+1) + 3 * t^{(2+1)}/(2+1) + 2 * t^{(1+1)}/(1+1) = t^{5} + t^{3} + t^{2}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indefinite Integrals
When you hear the term "indefinite integrals," think of finding the antiderivative. It's like unraveling the original function that was differentiated. Unlike definite integrals, which focus on finding the area under a curve within a certain interval, indefinite integrals do not have specified boundaries.
They are often represented as \( \int f(x) \, dx \) and include a constant of integration (usually "C"), even though we're told to ignore it for this exercise. This constant accounts for any vertical shift in the function's graph, since differentiation of a constant is zero.
To grasp this concept, just remember that the process of integration is the reverse of differentiation, where derivatives highlight rate of change, integration accumulates quantities over a domain.
Integration Power Rule
The integration power rule is an essential tool in calculus that helps in finding antiderivatives, especially for polynomials. It's a simplified way to integrate functions of the form \( t^m \), where \( m \) is a constant exponent.
According to this rule, the integral of a term like \( t^m \) is \( \int t^m \, dt = \frac{t^{m+1}}{m+1} + C \). This formula lets you raise the power of \( t \) by 1, and then divide by the new exponent. Make sure \( m eq -1 \) because the formula doesn't work for this case, as integrating \( t^{-1} \) leads to a natural logarithm.
For example, integrating \( 6t \), where \( m = 1 \), gives \( \frac{6t^{1+1}}{1+1} = 3t^2 \). This straightforward application of the power rule turns complex polynomial expressions into manageable terms.
Polynomial Integration
Polynomial integration involves applying the integration power rule to each term of a polynomial separately. This technique makes it easy to solve integrals of the form \( \int(ax^n + bx^m + cx^l) \, dx \).
For instance, in the example \( \int(5t^4 + 3t^2 + 2t) \, dt \), each term is integrated individually:
  • \(5t^4\) becomes \(\frac{5t^{4+1}}{4+1} = t^5 \)
  • \(3t^2\) becomes \(\frac{3t^{2+1}}{2+1} = t^3 \)
  • \(2t\) becomes \(\frac{2t^{1+1}}{1+1} = t^2 \)
Simply integrate each term one by one using the power rule, then combine the results.
Polynomial integration is a fundamental skill that not only simplifies solving integrals but also enhances understanding of how different terms within a function contribute to its antiderivative. Remember to always add a constant \( C \) at the end, unless specified otherwise, to account for all possible antiderivatives.

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