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What must a jogger's average speed be in order to travel \(13 \mathrm{~km}\) in \(3.25 \mathrm{~h}\) ?

Short Answer

Expert verified
The jogger's average speed must be 4.0 km/h.

Step by step solution

01

Identify the formula for average speed

The formula to find the average speed is speed = total distance / total time.
02

Substitute the distances and the time into the formula

Substitute the values into the formula. This gives us speed = \(13 \mathrm{~km}\) / \(3.25 \mathrm{~h}\).
03

Perform the calculation

Divide the total distance by the total time. This results in 4.0 km/h.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Distance and Time Relationship
To comprehend the concept of average speed, we must first grasp the connection between distance and time. In any physical scenario involving motion, distance represents how far an object has traveled, while time is the duration taken for this journey. The relationship between these two can be captured through the formula for speed:

  • Speed = Distance / Time
When distance increases and time stays constant, speed also increases, because you are covering more ground in the same time period. Conversely, if time increases while distance remains the same, speed decreases, as it takes longer to cover that distance.

Understanding this relationship is crucial because it forms the basis for the average speed calculation. For a jogger covering 13 kilometers in 3.25 hours, this relationship allows us to determine the jogger's average speed—essentially how fast, on average, they need to move to cover that distance in the given time.
Physics Problem-Solving Techniques
Solving physics problems often involves a clear and systematic approach. It's important to start by identifying what you're trying to find and which formula or principle applies. For instance, in the problem of finding the average speed of a jogger, we needed the formula:

  • Speed = Distance / Time
Next, physics problems typically require substituting known values into the formula. For our calculation, we plugged in the distance (13 km) and the time (3.25 hours) into the speed formula. This is a familiar step in problem-solving, where organizing and substituting data is key.

Lastly, performing arithmetic accurately is crucial. This ensures the correct solution is derived from your substitution. Here, dividing 13 km by 3.25 hours gave us an average speed of 4.0 km/h. Such disciplined problem-solving can be applied to a wide variety of physics problems, beyond just measuring speed.
Mastering Units and Conversion
A critical aspect of solving physics problems comfortably involves understanding units and their conversions. For speed calculations, it's essential to ensure the units for distance and time are compatible. Generally, speed is expressed with distance per unit of time, such as kilometers per hour (km/h).

In our exercise, distance was already in kilometers and time in hours—conveniently corresponding to common practice for speed units. If they had not matched—for instance, if given in meters and seconds—conversion would be necessary:
  • 1 kilometer = 1000 meters
  • 1 hour = 60 minutes = 3600 seconds
To ensure accuracy in your calculations, being adept at converting these units is vital. Failing to do so can lead to significantly erroneous results. It's one of the fundamental skills when approaching physics problems, ensuring all values are measured or converted into appropriate and consistent units.

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Most popular questions from this chapter

\- Kevin completes his morning workout at the pool. He swims \(4000 \mathrm{~m}\) (80 laps in the 50 -m-long pool) in \(1 \mathrm{~h}\). (a) What is the average velocity of Kevin during his workout? (b) What is his average speed? (c) With a burst of speed, Kevin swims one \(25-\mathrm{m}\) stretch in \(9.27\) s. What is Kevin's average speed over those \(25 \mathrm{~m}\) ? SSM

A swimmer completes a \(50-\mathrm{m}\) lap in \(100 \mathrm{~s}\). Estimate his speed in \(\mathrm{km} / \mathrm{h}\). SSM

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\- Wes and Lindsay stand on the roof of a building. Wes leans over the edge and drops an apple. Lindsay waits \(1.25 \mathrm{~s}\) after Wes releases his fruit and throws an orange straight down at \(28 \mathrm{~m} / \mathrm{s}\). Both pieces of fruit hit the ground simultaneously. Calculate the common height from which the fruits were released. Ignore the effects of air resistance.

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