/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 An engine doing work takes in \(... [FREE SOLUTION] | 91Ó°ÊÓ

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An engine doing work takes in \(10 \mathrm{~kJ}\) and exhausts \(6 \mathrm{~kJ}\). What is the efficiency of the engine? SSM

Short Answer

Expert verified
The efficiency of the engine is 40%.

Step by step solution

01

Determine the input and output energy

We are given the total input energy, which is 10 kJ, and the waste energy, which is 6 kJ. The useful output energy is the difference between these two, so it's \(10 \mathrm{~kJ} - 6 \mathrm{~kJ} = 4 \mathrm{~kJ}\).
02

Calculate the efficiency

Efficiency is the ratio of the useful output energy to the total input energy, usually expressed as a percentage. We can calculate it using the formula \(\frac{Output}{Input} \times 100 = \) efficiency. Substituting the values we found in Step 1, we get \(\frac{4 \mathrm{~kJ}}{10 \mathrm{~kJ}} \times 100 = 40 \% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Engine Efficiency
Engine efficiency measures how effectively an engine converts input energy into useful work. It is a paramount concept in thermodynamics as it helps us judge the performance of any engine. To calculate efficiency:
  • We compare the useful output energy with the input energy.
  • The formula is: \( \text{Efficiency} = \left( \frac{\text{Output Energy}}{\text{Input Energy}} \right) \times 100\% \).
In the problem, the engine's input energy was 10 kJ, and 4 kJ was converted into useful work (after 6 kJ was lost as waste). This leads to an efficiency of:\[\left( \frac{4 \text{ kJ}}{10 \text{ kJ}} \right) \times 100 = 40\%\]This tells us that only 40% of the energy is being used for productive tasks, while 60% is lost. Understanding this can lead to improvements in design to increase efficiency.
Energy Conversion
Energy conversion is a fundamental process in any engine operation, where multiple forms of energy are involved. In most engines, chemical energy (usually from fuel) is converted into mechanical energy to perform work. However, not all input energy gets converted efficiently. Some forms can be:
  • Thermal energy lost as heat
  • Sound energy
  • Light energy
The goal is to maximize the conversion of input energy to the desired form, usually mechanical. The exercise highlighted this through the engine turning 4 kJ of the original 10 kJ input into useful work. This means despite losses, a certain portion is effectively converted. Understanding energy conversion processes is vital for enhancing engine performance and deciding which energy conversions are beneficial.
Energy Conservation
Energy conservation is a powerful principle stating that energy in a closed system remains constant. It neither vanishes nor appears out of nowhere but transforms from one form to another.
In engines, while applying this principle, we account for all energies involved—including wasted energies—which are not contributing to useful work. If an engine takes in 10 kJ of energy and exhausts 6 kJ, energy conservation tells us that the remaining 4 kJ is what has been efficiently harnessed.
  • Energy cannot be created or destroyed; it only changes forms.
  • It's essential to trace all energy changes to understand an engine's efficiency fully.
In practice, an understanding of energy conservation aids engineers and scientists in diagnosing inefficiencies and developing strategies to reduce energy loss. This case study serves as a simple illustration of balancing input and output energy to analyze efficiency.

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Most popular questions from this chapter

A gas contained in a cylinder that has a piston is kept at a constant pressure of \(2.8 \times 10^{5} \mathrm{~Pa}\). The gas expands from \(0.5 \mathrm{~m}^{3}\) to \(1.5 \mathrm{~m}^{3}\) when \(300 \mathrm{~kJ}\) of heat is added to the cylinder. What is the change in internal energy of the gas?

A sample of \(0.2 \mathrm{~mol}\) of an ideal gas at \(320 \mathrm{~K}\) undergoes an isothermal expansion from \(2 \mathrm{~L}\) to \(8 \mathrm{~L}\). (a) Draw the \(P V\) diagram (with appropriate units) for the process. (b) Calculate the work done for the 6-L change in volume. (c) Calculate the heat lost or gained by the gas. (d) Calculate the change in internal energy of the gas.

An ideal gas is contained in a cylinder of fixed length and diameter. Eighty joules of heat is added while the piston is held in place. The work done by the gas on the walls of the cylinder is A. \(80 \mathrm{~J}\) B. \(0 \mathrm{~J}\) C. less than \(80 \mathrm{~J}\) D. more than \(80 \mathrm{~J}\) E. not specified by the information given.

A heat engine works in a cycle between reservoirs at \(273 \mathrm{~K}\) and \(490 \mathrm{~K}\). In each cycle the engine absorbs \(1250 \mathrm{~J}\) of heat from the high temperature reservoir and does \(475 \mathrm{~J}\) of work. (a) What is its efficiency? (b) What is the change in entropy of the universe when the engine goes through one complete cycle? (c) How much energy becomes unavailable for doing work when the engine goes through one complete cycle?

A certain engine has a second-law efficiency of \(85.0 \%\). During each cycle, it absorbs \(480 \mathrm{~J}\) of heat from a reservoir at \(300^{\circ} \mathrm{C}\) and dumps \(300 \mathrm{~J}\) of heat to a coldtemperature reservoir. (a) What is the temperature of the cold reservoir? (b) How much more work could be done by a Carnot engine working between the same two reservoirs and extracting the same \(480 \mathrm{~J}\) of heat in each cycle?

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