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Convert the following remperatures and comment on any physical significance of each: A. \(0^{\circ} \mathrm{C}=\) B. \(212{ }^{\circ} \mathrm{F}=\) C. \(273 \mathrm{~K}=\) D. \(68^{\circ} \mathrm{F}=\)

Short Answer

Expert verified
The conversions yield \(0^{\circ} C = 32^{\circ} F = 273.15 K\), \(212^{\circ} F = 100^{\circ} C = 373.15 K\), \(273 K = -0.15^{\circ} C = 31.73^{\circ} F\) and \(68^{\circ} F = 20^{\circ} C = 293.15 K\). They hold some physical significance such as: \(0^{\circ} C\) is the freezing point of water, \(212^{\circ}F\) is the boiling point of water and \(273 K\) is absolute zero, the lowest possible temperature.

Step by step solution

01

Conversion of temperature from degrees Celsius to Fahrenheit and Kelvin

To convert \(0^{\circ} C\) to Fahrenheit, use the formula \( F = C * \frac{9}{5} + 32 \), substituting \(C = 0\) gives \( F = 0 * \frac{9}{5} + 32 = 32^{\circ}F\). To convert to Kelvin, use the formula \( K = C + 273.15 \), substituting \(C = 0\) gives \(K = 273.15 \) Kelvin.
02

Conversion of temperature from Fahrenheit to Celsius and Kelvin

To convert \(212^{\circ} F\) to Celsius, we use \( C = (F - 32) * \frac{5}{9} \). Substituting \(F = 212\), we have \( C = (212 - 32) * \frac{5}{9} = 100^{\circ}C \). And for Kelvin, we first convert Fahrenheit to Celsius then add 273.15. Thus, K = 100 + 273.15 = 373.15 Kelvin.
03

Conversion of temperature from Kelvin to Celsius and Fahrenheit

For Kelvin to Celsius, we subtract 273.15 from the Kelvin temperature, i.e., \( C = K - 273.15 \). Substituting \( K = 273 \), we find \( C = 273 - 273.15 = -0.15^{\circ}C \). To find Fahrenheit, we then convert this Celsius temperature to Fahrenheit using the formula \( F = C * \frac{9}{5} + 32 \). So \( F = -0.15 * \frac{9}{5} + 32 = 31.73^{\circ}F \).
04

Conversion of another temperature from Fahrenheit to Celsius and Kelvin

To Convert \(68^{\circ} F\) to Celsius, we use \( C = (F - 32) * \frac{5}{9} \), so \( C = (68 - 32) * \frac{5}{9} = 20^{\circ}C \). And to find Kelvin, we convert this Celsius temperature to Kelvin, so \( K = C + 273.15 = 20 + 273.15 = 293.15 \) Kelvin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Celsius to Fahrenheit conversion
When converting from Celsius to Fahrenheit, we use the formula \( F = C \times \frac{9}{5} + 32 \). This formula transforms temperatures from the metric scale of Celsius to the more commonly used Fahrenheit scale in the United States. For instance, if we take \(0^{\circ}C\), which is the freezing point of water, applying our formula gives us \(32^{\circ}F\). This step showcases one of the most pivotal temperature values, as it marks a transition from water freezing to being above freezing in many scientific and daily contexts.

Converting Celsius to Fahrenheit is crucial not only in everyday usage but also in scientific analyses where different standards are employed for temperature measurement across various regions and histories.
Fahrenheit to Celsius conversion
To convert temperatures from Fahrenheit to Celsius, we use the formula \( C = (F - 32) \times \frac{5}{9} \). This conversion is essential for translating temperatures from the predominantly American Fahrenheit scale into the internationally used Celsius scale. For example, consider the boiling point of water at \(212^{\circ}F\). Using our conversion formula, we find it equals to \(100^{\circ}C\), highlighting an important scientific constant.

This conversion helps in understanding and comparing temperature data in scientific studies and everyday scenarios where Celsius is the preferred measure, especially in areas like Europe and most of the world.
Kelvin to Celsius conversion
The Kelvin scale is significant in scientific contexts as it begins at absolute zero, the theoretical coldest temperature possible where particles have minimal thermal motion. To convert temperatures from Kelvin to Celsius, we simply subtract \(273.15\) from the given Kelvin temperature. For example, a temperature of \(273 K\) would convert to \(-0.15^{\circ}C\).

This conversion underscores the Kelvin scale's role in science and engineering, particularly in disciplines like physics and chemistry where precise thermal measurements are crucial. Kelvin provides an absolute reference point that supports understanding and refining scientific studies.
Physical significance of temperature scales
Temperature scales like Celsius, Fahrenheit, and Kelvin are pivotal in everyday and scientific life. Each has its defining characteristics and applications. Celsius is widely used due to its simplistic alignment with water's physical state changes—freezing and boiling. Fahrenheit offers a more granular scale often preferred for meteorological temperature readings in places like the U.S.

Kelvin, on the other hand, is indispensable in scientific settings because it starts at absolute zero, where theoretical cessation of all thermal activity occurs. This scale assists scientists in thermodynamics and other fields requiring accurate thermal readings.
  • Celsius: Easy to understand, water-focused scale used globally for weather, cooking, and non-scientific purposes.
  • Fahrenheit: Offers detailed incremental changes, preferred in regions for specific applications involving human and weather-related temperatures.
  • Kelvin: Integral in scientific disciplines requiring baseline zero for thermal calculations.
Understanding these scales helps one appreciate differing regional preferences and the critical nature of precise temperature measurements in science and daily life.

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Most popular questions from this chapter

A sperical container is constructed from steel and has a radius of \(2 \mathrm{~m}\) at \(15^{\circ} \mathrm{C}\). The container sits in the Sun all day and its temperature rises to \(38^{\circ} \mathrm{C}\). The container is initially filled completely with water, but it is not sealed. Describe what will happen to the water after the temperature increase.

You wish to heat \(250 \mathrm{~g}\) of water to make a hor cup of coffee. If the water starts at \(20^{\circ} \mathrm{C}\) and you want your coffee to be \(95^{\circ} \mathrm{C}\), calculate the minimum amount of heat required. SSM

State the zeroth law of thermodynamics and explain how it is used in physics.

Suppose a person who lives in a house next to a busy urban freeway attempts to "harness" the sound energy from the nonstop traffic to heat the water in his home. He places a transducer on his roof, "carches" the sound waves, and converts the sound waves into an clectrical signal that warms a cistern of water. However, after running the system for 7 days, the \(5 \mathrm{~kg}\) of water increases in temperature by only \(0.01{ }^{\circ} \mathrm{C}\) ! Assuming \(100 \%\) transfer efficiency, calculate the acoustic power "caught" by the transducer. SSM

Biology A \(1.88 \mathrm{~m}\) (6 ft \(2 \mathrm{in}\).) man has a mass of \(80 \mathrm{~kg}\), a body surface area of \(2.1 \mathrm{~m}^{2}\) and a skin temperature of \(30{ }^{\circ} \mathrm{C}\). Normally \(80 \%\) of the food calories he consumes go to heat, the rest going to mechanical energy. To keep his body's temperature constant, how many food calories should he eat per day if he is in a room at \(20^{\circ} \mathrm{C}\) and he loses heat only through radiation? Does the answer seem reasonable? His emissivity \(\varepsilon\) is 1 because his body radiates almost entirely nonvisible infrared energy, which is not affected by skin pigment. (Careful! His body at \(30^{\circ} \mathrm{C}\) radiates into the air at \(20^{\circ} \mathrm{C}\), but the air also radiates back into his body. The net rate of radiation is \(P_{\text {nat }}=P_{\text {bodr }}-P_{\text {air }-\text { ) SSM }}\)

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