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Derive an approximate formula for the area expansion \((\Delta A)\) that a sheet of material undergoes as the temperature changes from \(T_{\mathrm{i}}\) to \(T_{\mathrm{f}}\). Assume the linear coefficient of expansion is \(\alpha\) for the material.

Short Answer

Expert verified
The formula for the approximate area expansion \(\Delta A\) of a material due to a change in temperature from \(T_{\mathrm{i}}\) to \(T_{\mathrm{f}}\) with a linear coefficient of expansion \(\alpha\) is \( \Delta A = 2 \alpha L^2 \Delta T \).

Step by step solution

01

Understanding the relationship between linear and area expansion

The formula for linear expansion is given by \( \Delta L = \alpha L \Delta T \), where \(\Delta L\) is the change in length, \(L\) is the original length, \(\alpha\) is the linear coefficient of thermal expansion, and \(\Delta T\) is the change in temperature. For area expansion, the formula is similar, but we need to account for expansion in two perpendicular dimensions. Thus, the area change is the square of the length change.
02

Derive area expansion formula

Noting the relationship between linear expansion and area expansion, the area expansion formula can be written as \( \Delta A = 2 \alpha A \Delta T \), where \(\Delta A\) is the change in area and \(A\) is the original area.
03

Substituting original area into area expansion formula

The original area \(A\) can be written as \(L^2\), where \(L\) is the original length of the side. Therefore, the area expansion formula can be rewritten as \( \Delta A = 2 \alpha L^2 \Delta T \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Coefficient of Expansion
The linear coefficient of expansion, denoted as \( \alpha \), is a crucial parameter in understanding how materials respond to temperature changes. When a material is heated or cooled, it tends to expand or contract, respectively. The coefficient of expansion quantifies how much the material will change per degree change in temperature.

If you imagine a rod with an original length \( L \), as the temperature increases by \( \Delta T \), its new length after expansion will be slightly longer. The change in length \( \Delta L \) is provided by the formula:
  • \( \Delta L = \alpha L \Delta T \)
This formula tells us that the change in length is proportional to the original length and the change in temperature, which is scaled by the linear coefficient \( \alpha \). It's important because different materials have different coefficients, meaning they expand at different rates even under the same temperature change. This is why \( \alpha \) is often a critical factor in engineering, where precision fits are necessary.
Temperature Change
Temperature change \( \Delta T \) is a straightforward but very significant concept when discussing thermal expansion. It refers to the difference between the final temperature \( T_{\mathrm{f}} \) and the initial temperature \( T_{\mathrm{i}} \). The equation for this is:
  • \( \Delta T = T_{\mathrm{f}} - T_{\mathrm{i}} \)
This change is essential in determining how much expansion or contraction a material will undergo. A larger \( \Delta T \) generally results in a more considerable expansion or contraction.

While the concept itself is simple, its impact is profound. In practical applications, even a small temperature change can cause significant expansion in large structures like bridges or buildings. This is why temperature variations must be carefully accounted for in construction and design processes.
Area Expansion
Area expansion is similar to linear expansion but involves the increase in size of a two-dimensional surface, such as the face of a metal sheet. When the temperature of such a material increases, the changes occur not just in one direction but across the entire surface.

The formula for area expansion is derived from understanding that each side of the area expands linearly. Hence, the area change \( \Delta A \) for a material with an original area \( A \) is given by:
  • \( \Delta A = 2 \alpha A \Delta T \)
This means that the area expands approximately twice as much as you might expect from just a single dimension because it involves two directions of expansion. Each direction accounts for a linear coefficient, resulting in a doubling effect.

This double effect is critical to keep in mind, especially in design and manufacturing, where precise dimensions are necessary. A small oversight in estimating area expansion can lead to significant alterations in product specifications.

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Most popular questions from this chapter

The phrase "temperature measures kinetic energy" is somewhat difficult to understand and can be seen as contradictory. Give a few reasons why the explanation actually makes sense and a few reasons why it seems contradictory.

The highest temperature ever recorded on Earth is \(56.7^{\circ} \mathrm{C}\), in Death Valley, \(\mathrm{CA}\) in 1913 . The lowest temperature on record is \(-89.2{ }^{\circ} \mathrm{C}\), measured at Vostok Research Station in Antarctica in 1983. Convert these extreme temperatures to \({ }^{\circ} \mathrm{F}\) and kelvin.

A 50 -g calorimeter cup made from aluminum contains \(100 \mathrm{~g}\) of water. Both the aluminum and the water are at \(25^{\circ} \mathrm{C}\). A \(300-\mathrm{g}\) cube of some unknown metal is heated to \(150{ }^{\circ} \mathrm{C}\) and placed into the calorimeter; the final equilibrium temperature for the water, aluminum and metal sample is \(41^{\circ} \mathrm{C}\). Calculate the specific heat of the unknown metal and make a guess as to its composätion.

Why are some sidewalks often formed in small segments, separated by a small gap berween the segments?

Two objects that have different sizes, masses, and temperatures come into close contact wirh each other. Thermal energy is transferred A. from the larger object to the smaller object. B. from the object that has more mass to the one that has less mass. C. from the object that has the higher temperature to the object that has the lower temperature. D. from the object that has the lower temperature to the object that has the higher temperature. E. back and forth between the rwo objects until they come to equilibrium.

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