/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 The second-order differential eq... [FREE SOLUTION] | 91Ó°ÊÓ

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The second-order differential equation that describes simple harmonic motion can be written as follows: $$ \frac{d^{2} x}{d t^{2}}+\omega^{2} x=0 $$ Determine, by differentiating, which of the following functions will satisfy the equation (assume \(A\) and \(\omega\) are constants): (a) \(x(t)=A \cos (\omega t)\), (b) \(x(t)=A \sin (\omega t)\), (c) \(x(t)=A \cos (\omega t)+A \sin (\omega t)\), (d) \(x(t)=A e^{\omega t}\), (e) \(x(t)=\) \(A e^{+\omega t}+A e^{-\omega t}\), (f) \(x(t)=A e^{i \omega t}\), (g) \(x(t)=A e^{+i \omega t}+A e^{-i \omega t}\).

Short Answer

Expert verified
The functions that satisfy the given second-order differential equation are (a) \(x(t)=A \cos (\omega t)\), (b) \(x(t)=A \sin (\omega t)\), (c) \(x(t)=A \cos (\omega t)+A \sin (\omega t)\), and (f) \(x(t)=A e^{i \omega t}\).

Step by step solution

01

Differentiate function (a)

Consider function \(x(t)=A \cos (\omega t)\). The first derivative is \(x'(t) = -A \omega \sin (\omega t)\) and the second derivative \(x''(t) = -A \omega^2 \cos (\omega t)\). Plugging these into the equation we find that the equation holds true, so function (a) satisfies the differential equation.
02

Differentiate function (b)

Consider function \(x(t)=A \sin (\omega t)\). The first derivative is \(x'(t) = A \omega \cos (\omega t)\) and the second derivative \(x''(t) = -A \omega^2 \sin (\omega t)\). Substituting these into the equation we find that the equation also holds true, so function (b) satisfies the differential equation.
03

Differentiate function (c)

Function (c), \(x(t)=A \cos (\omega t)+A \sin (\omega t)\), can be treated as the sum of functions (a) and (b). Since both function (a) and (b) satisfy the differential equation, their sum will also satisfy the equation.
04

Differentiate function (d)

For function (d), \(x(t)=A e^{\omega t}\), the first derivative is \(x'(t) = A \omega e^{\omega t}\) and the second derivative \(x''(t) = A \omega^2 e^{\omega t}\). Substituting these into the equation we can see that the differential equation is not satisfied, so function (d) does not satisfy the given differential equation.
05

Differentiate function (e)

When we deal with function (e), \(x(t)= A e^{+\omega t}+A e^{-\omega t}\), we find that neither the sum nor the individual terms satisfy the second order differential equation.
06

Differentiate function (f)

For function (f), \(x(t)=A e^{i \omega t}\), we find that this function also satisfies the second order differential equation.
07

Differentiate function (g)

Lastly for function (g), \(x(t)=A e^{+i \omega t}+A e^{-i \omega t}\), we again find that neither the sum nor the individual terms satisfy the second order differential equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Second-Order Differential Equation
A second-order differential equation is a type of equation that involves the second derivative of a function as its highest derivative. In the context of simple harmonic motion, the equation \( \frac{d^{2} x}{d t^{2}} + \omega^{2} x = 0 \) represents such an equation. This equation predicts how a system will evolve over time when it is subject to restoring forces that are proportional to the displacement. The solution to this equation gives the position \( x(t) \) of the system at any time \( t \). The constant \( \omega \) is known as the angular frequency, and it is a measure of how quickly the oscillations occur.
Running through all the possible functions, we can check which ones satisfy the equation by differentiating them twice and substituting back into the equation. If both sides equal zero, the function is a valid solution.
Solutions to Differential Equations
To solve a second-order differential equation, we typically look for functions that, when differentiated twice, satisfy the equation. For simple harmonic motion, trigonometric functions like sine and cosine are commonly used. For example, the function \( x(t) = A \cos(\omega t) \) has a first derivative \( x'(t) = -A\omega \sin(\omega t) \) and a second derivative \( x''(t) = -A\omega^2 \cos(\omega t) \). Substituting these derivatives back into the original differential equation confirms that it satisfies the equation, making \( x(t) = A \cos(\omega t) \) a valid solution.
Similarly, the function \( x(t) = A \sin(\omega t) \) also fits as a solution, as does their linear combination \( x(t) = A \cos(\omega t) + A \sin(\omega t) \), highlighting the superposition principle. However, other functions like exponential ones do not satisfy the equation unless they are specifically complex exponentials, which can sometimes cover trigonometric functions due to Euler's formula.
Harmonic Functions
Harmonic functions are special functions widely used to describe periodic oscillations. In the realm of simple harmonic motion, they typically appear in the form of sine and cosine functions. These functions inherently possess the periodic nature needed to describe oscillations as they repeat their values in a regular pattern over time.
In this exercise, functions like \( x(t) = A \cos(\omega t) \) and \( x(t) = A \sin(\omega t) \) are harmonic functions. Both are solutions to the differential equation for simple harmonic motion. Their characteristic pattern of oscillation without damping is essential for modeling systems like springs and pendulums in ideal conditions.
Understanding harmonic functions and their properties allows us to apply them effectively in systems exhibiting periodic behavior, enabling predictions and analyses of their motions.

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Most popular questions from this chapter

In addition to sine and cosine, many other mathematical functions are periodic and satisfy the basic differential equation for simple harmonic motion. Show that the function \(x(t)=A(\sin \omega t+\cos \omega t)\) satisfies the simple harmonic motion equation.

A \(60\)-cm-long thin rod of copper has a radius \(r\) of \(0.4 \mathrm{~cm}\) (the density of copper is \(8.92 \mathrm{~g} / \mathrm{cm}^{3}\) ). The rod is suspended from a thin wire that is welded to the exact center of the copper rod. The wire is also made of copper and has a length of \(20 \mathrm{~cm}\) and a cross-sectional diameter of \(1 \mathrm{~mm}\). The rod is displaced from the equilibrium position and the torque on the thin wire causes it to twist the rod back and forth in harmonic motion. This is a torsion pendulum (Figure 12-33). The torque acts on the rod according to following equation: $$ \tau=-K \theta $$ where \(\tau\) is the torque, \(K\) is the torsional constant for wire and equal to \(\pi G r^{4} / 2 l, G\) is the modulus of rigidity for copper and equal to \(45 \mathrm{GPa}, l\) is the length, and \(\theta\) is the angular displacement from equilibrium. Calculate the period of the harmonic motion.

The potential energy of a simple harmonic oscillator is given by \(U=\frac{1}{2} k x^{2}\). (a) If \(x(t)=A \sin \omega t\), plot the potential energy versus time for three full periods of motion. (b) Derive an expression for the velocity, \(v(t)\), and (c) add the plot of the kinetic energy, \(K=\frac{1}{2} m v^{2}\), to your graph. SSM

An object-spring system undergoes simple harmonic motion. If the mass of the object is doubled, what will happen to the period of the motion? SSM A. The period will increase. B. The period will decrease by an unknown amount. C. The period will not change. D. The period will decrease by a factor of 2 . E. The period will decrease by a factor of 4 .

Explain the difference between a simple pendulum and a physical pendulum.

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