/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 What is the net force on an airp... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is the net force on an airplane window of area \(1000 \mathrm{~cm}^{2}\) if the pressure inside the cabin is \(0.95 \mathrm{~atm}\) and the pressure outside is \(0.85 \mathrm{~atm}\) ? SSM

Short Answer

Expert verified
To solve this problem, convert the area and pressure to standard units and calculate the difference in pressure. Then, apply the formula \(F = \Delta P \times A\) to find the net force.

Step by step solution

01

Interpretation

In the problem, it is given that the area of the airplane window is \(1000 \mathrm{~cm}^{2}\), the pressure inside is \(0.95 \mathrm{~atm}\) and the pressure outside is \(0.85 \mathrm{~atm}\). Convert the given area to \(\mathrm{m}^{2}\) (since standard unit is \(m^2\), not \(cm^2\)) and both pressure values to \(\mathrm{Pascal} (Pa)\) units.
02

Conversion

1 \(\mathrm{cm}^{2} = 0.0001 \mathrm{m}^{2}\) and 1 \(\mathrm{atm} = 1.013 \times 10^{5} \mathrm{Pa}\). Substituting these values, the area \(A = 1000\) \(\mathrm{~cm}^{2}\) becomes \(A = 1000 \times 0.0001 = 0.1 \mathrm{m}^{2}\). The pressure inside becomes \(P_{in} = 0.95 \times 1.013 \times 10^{5} \mathrm{~Pa}\) and the pressure outside becomes \(P_{out} = 0.85 \times 1.013 \times 10^{5} \mathrm{~Pa}\).
03

Find difference in pressure

The difference in pressure can be calculated as \(\Delta P = P_{in} - P_{out}\).
04

Calculate the net force

Use the formula \(F = \Delta P \times A\) to calculate the net force on the window. Substitute the values of \(\Delta P\) and \(A\) obtained from Steps 2 and 3 into this formula and compute the value of force \(F\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pressure Conversion
In physics, pressure is a measure of the force applied over an area. When solving scientific problems, consistent units are crucial. Generally, pressure measurements may initially be given in units such as atmospheres (atm). However, it's often required to convert these to Pascals (Pa) for calculations. To perform a pressure conversion, one must know the factor:
  • 1 atm = 1.013 × 105 Pa.
If we have a pressure inside an airplane cabin of 0.95 atm, converting it to Pascals requires multiplying by 1.013 × 105 Pa. Therefore, 0.95 atm becomes:\[P_{in} = 0.95 imes 1.013 imes 10^{5} \, \mathrm{Pa}\]Similarly, for the outside pressure of 0.85 atm:\[P_{out} = 0.85 imes 1.013 imes 10^{5} \, \mathrm{Pa}\]Making these conversions ensures calculations can be consistent and accurate.
Net Force Calculation
Calculating the net force involves understanding how different pressures exert force over a given area. The concept of net force is derived from the pressure difference acting on an object. First, determine the difference in pressure, known as \(\Delta P\), between two points such as inside and outside of an airplane cabin:\[\Delta P = P_{in} - P_{out}\]Net force, \( F \), on a surface is then calculated by multiplying this pressure difference by the area \( A \) over which it acts:\[F = \Delta P \times A\]Once the difference in pressure is determined using previously converted values, it can be plugged into the equation above to find the net force. This explains how changes in pressure affect the force experienced by structures like airplane windows.
Unit Conversion
Converting units is essential in physics for proper calculation and comparison. It's important to change areas like in this problem from square centimeters (\(\mathrm{cm}^2\)) to square meters (\(\mathrm{m}^2\)) because the standard unit of area in the International System of Units (SI) is square meters. Understanding unit conversion involves knowing simple but significant conversion factors:
  • 1 \(\mathrm{cm}^2 = 0.0001 \, \mathrm{m}^2\).
For an area given as 1000 \(\mathrm{cm}^2\), conversion to square meters is simply:\[A = 1000 \, \mathrm{cm}^2 \times 0.0001 \, \mathrm{m}^2/\mathrm{cm}^2 = 0.1 \, \mathrm{m}^2\]Conversions make it possible to handle calculations accurately, ensuring all units are compatible during the operation. Without proper unit conversion, the results could be incorrect, leading to misinterpretation of the physical situation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

•eCalc Determine the mass of a sphere of radius \(R\) that has a density that varies with distance from the center given by \(\rho(r)=\rho_{0}(1-r / R)\), where \(\rho_{0}\) is a constant. For this problem, \(0

Two identically shaped containers in the shape of a truncated cone are placed on a table, but one is inverted such that the small end is resting on the table. The containers are filled with the same height of water. The pressure at the bottom of each container is the same. However, the weight of the water in each container is different. Explain why this statement is correct.

Biology Blood takes about \(1.50 \mathrm{~s}\) to pass through a \(2.00\)-mm-long capillary. If the diameter of the capillary is \(5.00 \mu \mathrm{m}\) and the pressure drop is \(2.60 \mathrm{kPa}\), calculate the viscosity of blood. Assume laminar flow. SSM

Medical Blood pressure is normally expressed as the ratio of the systolic pressure (when the heart just ejects blood) to the diastolic pressure (when the heart is relaxed). The measurement is made at the level of the heart (usually at the middle of the upper arm), and the pressures are given in millimeters of mercury, although the units are not usually written. Normal blood pressure is typically \(120 / 80\). How would you write normal blood pressure if the units of pressure used were (a) pascals, (b) atmospheres, or (c) pounds per square inch (lb/in. \({ }^{2}\), psi)? (d) Is the blood pressure, as typically stated, the absolute pressure or the gauge pressure? Explain your answer. SSM

An object floats in water with \(5 / 8\) of its volume submerged. The ratio of the density of the object to that of water is A. \(8 / 5\). B. \(5 / 8\). C. \(1 / 2\). D. \(2 / 1\). E. \(3 / 8\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.