/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 The shell theorem tells us that ... [FREE SOLUTION] | 91Ó°ÊÓ

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The shell theorem tells us that a hollow sphere exerts zero gravitational force on an object inside it. Why does a marble placed inside a hollow sphere that rests on the surface of Earth experience a nonzero net force?

Short Answer

Expert verified
The marble experiences a nonzero net force inside a hollow sphere resting on Earth because, even though the sphere exerts no gravitational force due to the shell theorem, the marble is still influenced by Earth's gravity, which pulls the marble towards its center.

Step by step solution

01

Understand the shell theorem

The shell theorem assures a hollow sphere exerts zero gravitational force on an object located inside it. It occurs because the vector sum of the gravitational forces exerted by each particle in the sphere cancels out, leaving a net force of zero inside the sphere.
02

Identify other forces playing a role

When considering the setting where the hollow sphere rests on the Earth's surface, it's crucial to recognise that the marble isn't just influenced by the gravity of the hollow sphere, but also by Earth's gravitational force.
03

Understand the effect of Earth's gravity

Earth's gravity pulls all objects towards its center with a force proportional to their mass. Since the marble has mass, it experiences a gravitational pull towards the Earth, offering it a nonzero net force even when it is inside the hollow sphere.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is a fundamental interaction between two masses. It's the force by which objects with mass attract each other. The strength of this force is dictated by their masses and the distance separating them, as per Newton's Law of Universal Gravitation. This law can be expressed mathematically as \( F = \frac{G \, m_1 \, m_2}{r^2} \). In this equation, \( F \) is the gravitational force, \( G \) is the gravitational constant, \( m_1 \) and \( m_2 \) are the masses, and \( r \) is the distance between the centers of the two masses.
Through this understanding, we can see why gravitational force is crucial in exploring the interactions between planets, stars, and galaxies. But it also affects objects on Earth, like when you drop a book and watch it fall to the floor.
Hollow Sphere
A hollow sphere is a three-dimensional shape that is empty inside, like a beach ball or a shell. According to the shell theorem, a hollow sphere exerts no gravitational force on an object located inside it. This happens because the gravitational forces from all parts of the shell cancel each other out.
Imagine standing inside a hollow sphere. Every small portion of the sphere's shell pulls you equally in different directions. Because of these equal pulls, the net effect is zero, and thus, you experience no gravitational force from the sphere itself. This is an interesting result of how geometry and gravity interact with empty spaces.
Net Force
Net force refers to the total force acting on an object when all individual forces are considered. It’s like summing up all the pushes and pulls an object experiences. If two people are pushing a box from opposite sides with equal strength, the net force is zero, and the box stays put.
In our scenario with the marble inside the hollow sphere on Earth's surface, the gravitational force from the hollow sphere is zero because of the shell theorem. However, Earth’s gravity is another force impacting the marble. These forces must be combined to determine the net force on the marble. Here, the net force isn't zero because Earth's gravitational pull remains active. This is why the marble still experiences motion or a tendency to move when inside the hollow sphere.
Earth's Gravity
Earth's gravity plays a significant role in the forces we experience daily. It pulls objects towards the center of the Earth and is responsible for what we commonly refer to as "weight." The force of gravity is approximately \( 9.81 \, \text{m/s}^2 \) near the Earth's surface. This means for every kilogram of mass, Earth pulls with a force of 9.81 Newtons.
In the given exercise, even when the marble is inside the hollow sphere, Earth's gravity continues to act on it. This gravitational force doesn't stop or change because the marble is within another object. It is Earth’s gravity that ensures the marble has a non-zero net force and is pulled towards the ground, irrespective of the hollow sphere’s presence.

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Most popular questions from this chapter

Which is larger, the Sun's pull on Earth or Earth's pull on Sun? A. The Sun's pull on Earth is larger. B. Earth's pull on the Sun is larger. C. They pull on each other equally. D. The Sun's pull on Earth is twice as large as Earth's pull on the much larger Sun. E. There is no pull or force between Earth and the Sun.

How much energy would be required to move the Moon from its present orbit around Earth to a location that is twice as far away? Assume the Moon's orbit around Earth is nearly circular and has a radius of \(3.84 \times\) \(10^{8} \mathrm{~m}\), and that the Moon's orbital period is \(27.3\) days.

Earth moves faster in its orbit around the Sun during the winter in the Northern Hemisphere than it does during the summer in the Northern Hemisphere. Is Earth closer to the Sun during the Northern Hemisphere's winter or during the Northern Hemisphere's summer? Explain your answer.

The highest point on Earth is Mount Everest at \(8850 \mathrm{~m}\) above sea level. (a) Determine the acceleration due to gravity at that elevation. (b) What fractional change in the acceleration due to gravity would you find between Mount Everest and the Dead Sea (the lowest elevation on Earth at \(400 \mathrm{~m}\) below sea level)?

According to Newton's universal law of gravitation, \(\overrightarrow{\boldsymbol{F}}=-\frac{G m_{1} m_{2}}{r^{2}} \hat{r}\), if the distance \(r\) is doubled, the force is A. four times as much as the original value. B. twice as much as the original value. C. the same as the original value. D. one-half of the original value. E. one-fourth of the original value.

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