/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 The period \(T\) of a simple pen... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The period \(T\) of a simple pendulum, the time for one complete oscillation, is given by \(T=2 \pi \sqrt{(L / g)}\), where \(L\) is the length of the pendulum and \(g\) is the acceleration due to gravity. Show that the dimensions in the equation are consistent.

Short Answer

Expert verified
The dimensions on both sides of the equation are [T], hence they are consistent

Step by step solution

01

Identify the dimensions

Identify the dimensions of each quantity: \(T\) represents time and so has a dimension of [T] (capital T stands for time). \(L\) stands for length, so it has dimension of [L] (capital L stands for length) and \(g\) is acceleration due to gravity which has dimensions of [LT^-2]. The constant 2Ï€ is dimensionless, so it doesn't contribute to the dimensions.
02

Substitute the dimensions into the equation

Substitute the dimensions into the equation \(T=2 \pi \sqrt{(L / g)}\) to get [T] = \(\sqrt{[L] / [LT^-2]}\). The term within the square root becomes [T^2]
03

Solve the square root

If you square root [T^2], it will give [T] as dimension.
04

Confirm dimensional consistency

Now confirm that both sides of the equation have the same dimension, so [T] = [T]. Hence, the dimensions in the equation are consistent

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Pendulum
The simple pendulum is a classic topic often introduced in physics education. A simple pendulum consists of a mass, known as the "bob," which is attached to the end of a string or rod, and is allowed to swing back and forth. This is a classic motion under the influence of gravity and is a fundamental example in teaching the principles of oscillatory motion.

In physics, simple pendulums help illustrate harmonic motion. This is because the restoring force acting to bring the pendulum back to its equilibrium is proportional to the displacement. Such systems, when set into motion under the force of gravity, will exhibit a periodic, or repeating, motion. Understanding the simple pendulum is thus crucial for anyone learning about waves and oscillations.

Key characteristics of a simple pendulum include:
  • The motion is influenced primarily by gravity.
  • The movement is periodic, meaning it repeats in equal time intervals.
  • It moves in a symmetrical path around an equilibrium point.
Pendulum Period
The period of a pendulum refers to the time required for it to complete one full back-and-forth swing. For a simple pendulum, the period is expressed by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} \]where:
  • \(T\) is the period of the pendulum, measured in seconds.
  • \(L\) represents the length of the pendulum, which extends from the pivot to the center of mass of the bob.
  • \(g\) is the acceleration due to gravity, with a standard value of approximately 9.81 m/s² on Earth's surface.
An important aspect of the pendulum's period is that it is independent of its mass and the amplitude of its swing, given small angular displacements. This means that a heavier object or a higher swing will not alter the period, which is a surprising yet fascinating part of pendulum physics.
Physics Education
Physics education often uses simple pendulums to teach key concepts in classical mechanics. Learning about pendulums offers practical insights into topics such as energy conservation, harmonic motion, and dimensional analysis.

For students, working with pendulums provides foundational experience in experimental methods. They learn to measure periods, length, and use equations to infer properties of motion. This hands-on experience reinforces the understanding of abstract theoretical concepts they encounter in textbooks.

Moreover, simple pendulums serve as an accessible experiment for introducing dimensional analysis. By analyzing the units in equations like the pendulum period equation, students comprehend how different physical quantities relate and interact in a dimensional and algebraic sense.
Gravity and Acceleration
Gravity and acceleration are crucial elements in understanding the motion of a simple pendulum. Acceleration due to gravity, denoted as \( g \), is the force pulling objects towards the Earth's center, and it is a fundamental constant in the pendulum period equation.Gravity ensures the pendulum's periodic motion. It acts as the restoring force, striving to return the pendulum bob to its lowest point in the arc. The expression \( g \) specifically signifies gravitation's role in influencing the pendulum's motion by determining the speed at which the pendulum accelerates as it swings.

Key points about gravity and its effect on pendulum motion include:
  • The greater the acceleration due to gravity, the faster the pendulum swings.
  • On celestial bodies with different gravity than Earth, the pendulum's period will be different.
Understanding these principles underlines the importance of gravity in everyday occurrences and helps illuminate its role in broader physical theories.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The motion of a vibrating system is described by \(y(x, t)=A_{0} e^{-\alpha t} \sin (k x-\omega t)\). Find the SI units for \(k\), \(\omega\), and \(\alpha\).

The body mass index (BMI) estimates the amount of fat in a person's body. It is defined as the person's mass \(m\) in kg divided by the square of the person's height \(h\) in m. (a) Write the formula for BMI in terms of \(m\) and \(h\). (b) In the United States, most people measure weight in pounds and height in feet and inches. Show that with weight \(W\) in pounds and height \(h\) in inches, the BMI formula is BMI \(=703 \mathrm{~W} / h^{2}\). (c) A person with a BMI between \(25.0\) and \(30.0\) is considered overweight. If a person is \(5^{\prime} 11^{\prime \prime}\) tall, for what range of mass will he be considered overweight?

\(\$ Medical Express each quantity in the standard SI units requested. (a) An adult should have no more than \)2500 \mathrm{mg}\( of sodium per day. What is the limit in \)\mathrm{kg}\( ? (b) A \)240-\mathrm{mL}\( cup of whole milk contains \)35 \mathrm{mg}\( of cholesterol. Express the cholesterol concentration in the milk in \)\mathrm{kg} / \mathrm{m}^{3}\( and in \)\mathrm{mg} / \mathrm{mL}\(. (c) A typical human cell is about \)10 \mu \mathrm{m}\( in diameter, modeled as a sphere. Express its volume in cubic meters. (d) A low-strength aspirin tablet (sometimes called a "baby aspirin") contains \)81 \mathrm{mg}\( of the active ingredient. How many kg of the active ingredient does a 100 -tablet bottle of baby aspirin contain? (e) The average flow rate of urine out of the kidneys is typically \)1.2 \mathrm{~mL} / \mathrm{min}\(. Express the rate in \)\mathrm{m}^{3} / \mathrm{s}\(. (f) The density of blood proteins is about \)1.4 \mathrm{~g} / \mathrm{cm}^{3}\(. Express the density in \)\mathrm{kg} / \mathrm{m}^{3}$.

You hire a printer to print concert tickets. He delivers them in circular rolls labeled as 1000 tickets each. You want to check the number of tickets in each roll without counting thousands of tickets. You decide to do it by measuring the diameter of the rolls. If the tickets are 2 in long and \(0.22 \mathrm{~mm}\) thick and are rolled on a core \(3 \mathrm{~cm}\) in diameter, what should be the diameter of a roll of 1000 tickets?

One nanosecond is A. \(10^{-15} \mathrm{~s}\) B. \(10^{-6} \mathrm{~s}\) C. \(10^{-9} \mathrm{~s}\) D. \(10^{-3} \mathrm{~s}\) E. \(10^{9} \mathrm{~s}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.