/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 Determine the circumference of a... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine the circumference of a path that follows a great arc at a latitude of 45° around a spherical planet that has radius R of 5000 km (Figure 1-8).

Short Answer

Expert verified
The circumference of the path that follows a great arc at a latitude of 45° around the planet is approximately 22,360 km.

Step by step solution

01

Determine the radius of the circle at the given latitude

The circle's radius can be found using the relationship between the radius R of the sphere and the given latitude. Since the latitude is 45°, the radius of the circle on the surface of the sphere at this latitude is \( R \cos(45°) = R \cos(π/4) = R/\sqrt{2} \), where R is the radius of the planet, which is 5000 km in our case.
02

Calculate the circumference of the circle

The formula for the circumference of a circle is \( 2 \pi r \). Here r is the radius of the circle that we determined in step 1, which is \( R/\sqrt{2} \). Substitute r into the formula to get \( 2 \pi (R/\sqrt{2}) \).
03

Final calculation

Plug in the value of R, 5000 km, into the equation: \( 2 \pi (5000/\sqrt{2}) \). Use your calculator to find the numerical answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Great circle
A great circle on the surface of a sphere is any circle that divides the sphere into two equal halves. Think of it as the largest possible circle that can be drawn on a sphere. The Earth's equator is a prime example of a great circle.
- Each point on a great circle is equidistant from the center of the sphere.
- Great circles are important in navigation and aviation, as the shortest path between two points on the surface of a sphere lies along a great circle.
In the context of our exercise, understanding a great circle helps in visualizing the path followed around the sphere. However, as we move to latitudes other than the equator, like the 45° in this case, the path is no longer a great circle. Instead, it is a smaller circle that has a different radius.
Latitude
Latitude is a measure of how far north or south a point is on the surface of a sphere relative to the equator.
- Lines of latitude run parallel to the equator and are measured in degrees.
- The equator is at 0°, the North Pole is at 90°N, and the South Pole is at 90°S.
In the exercise, the 45° latitude tells us that we're dealing with a circle that runs parallel to the equator, halfway between the equator and the pole.
This affects the calculation of the path's circumference because it changes the radius we use from that of the full sphere to a smaller circle at this given latitude.
Spherical geometry
Spherical geometry is the study of geometric shapes on the surface of a sphere, which is fundamentally different from the flat surfaces studied in Euclidean geometry.
- In spherical geometry, the angles of a triangle can add up to more than 180°.
- Straight lines are not truly 'straight' but are portions of great circles.
Our exercise makes use of spherical geometry concepts since we're dealing with a path on the surface of a sphere (the planet). The determination of the circle's radius at a specific latitude uses the understanding of how spherical surfaces behave, showcasing the importance of spherical geometry in real-world applications.
Trigonometry
Trigonometry is a branch of mathematics dealing primarily with angles and the relationships between them in triangles.
- In spherical scenarios, it helps calculate distances and angles on spheres.
In our problem, trigonometry is used to determine the radius of the circle at a latitude of 45° using the cosine function: \[ r = R \cos(45°) \]where \( R \) is the radius of the sphere.
By applying this trigonometric function, we find the radius of the smaller circle parallel to the equator. This radius is crucial for determining the circumference of the circle, demonstrating the powerful application of trigonometry beyond simple triangle problems.

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