/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 A line charge density \(\lambda\... [FREE SOLUTION] | 91Ó°ÊÓ

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A line charge density \(\lambda\) is put onto the nonconducting rim of a wheel of radius \(R\), which is then suspended horizontally, so that to rotate (the spokes are made of some non conducting material - wood, may be). In the central region up to radius a , there is a uniform magnetic field \(B_{0}\), pointing up. Now someone turns the field off. The moment of inertia of the loop along with the spokes is \(I\). (i) Find the angular speed of the wheel after \(B_{0}\) is switched off. (ii) Does the angular speed depend upon the rate at which the magnetic field is cut off. (iii) Explain the origin of the angular speed.

Short Answer

Expert verified
(i) \( \omega = \frac{\lambda B_0 a^2}{I} \). (ii) No, \( \omega \) is independent of the cutoff rate. (iii) It's due to the induced torque from changing magnetic flux.

Step by step solution

01

Understand the problem

We have a non-conducting wheel with charge density \( \lambda \) distributed on its rim of radius \( R \). It is placed in a magnetic field \( B_0 \) in its central region. When the field is turned off, we need to find the effects on the wheel's rotation.
02

Apply Faraday's Law of Induction

When the magnetic field \( B_0 \) is turned off, a change in magnetic flux induces an electromotive force (EMF) around the rim of the wheel. Faraday's Law states that the induced EMF \( \varepsilon \) is given by the negative rate of change of the magnetic flux: \( \varepsilon = -\frac{d\Phi}{dt} \).
03

Calculate Magnetic Flux Change

The magnetic flux \( \Phi \) is given by \( \Phi = B_0 \pi a^2 \) for a circle of radius \( a \), where \( a < R \). The change in flux \( \Delta \Phi \) is \( -B_0 \pi a^2 \) as \( B_0 \) goes from \( B_0 \) to 0.
04

Calculate Induced EMF

The induced EMF is \( \varepsilon = B_0 \pi a^2 / \Delta t \), assuming the field is turned off over a period \( \Delta t \).
05

Find Induced Current and Torque

The induced current \( I = \frac{\varepsilon}{R} \), where \( R \) is the resistance of the wheel's rim. The torque \( \tau = I_1 BR \), where \( I_1 \) is the current flowing through the rim. Since torque \( \tau = R \frac{dL}{dt} \), and \( L = I \omega \) (angular momentum), \( \tau \) induces an angular speed \( \omega \), making use of \( \tau = I \alpha \).
06

Relate Torque to Angular Speed

Using the relationship \( \tau = I \alpha \), where \( \alpha \) is the angular acceleration, solve for \( \omega \) knowing \( \alpha = \frac{\Delta \omega}{\Delta t} \) and \( L = I \omega \), leading to a formula for \( \omega \).
07

Solve Part (i)

Use the expressions derived to find the specific angular speed \( \omega \) after the magnetic field is turned off. The rate of EMF drop and current interplay with moment of inertia will yield the final formula.
08

Address Part (ii)

Explain whether the angular speed \( \omega \) depends on the rate at which \( B_0 \) is cut off by noting that \( \omega \) is independent of \( \Delta t \) since the change in flux is constant.
09

Explain the Physics - Part (iii)

The origin of the angular speed is attributed to the change in angular momentum of the rim's charged distribution due to the changed magnetic environment as \( B_0 \) is turned off.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Speed
Angular speed is a measure of how fast an object rotates or revolves around an axis. In this exercise, we're interested in the angular speed of a charged wheel when subjected to changes in a magnetic field. Angular speed, often represented by the Greek letter \( \omega \), is a crucial concept in understanding rotational dynamics.

When the magnetic field is switched off, it effects a change in the angular momentum of the wheel, resulting in a new angular speed. This occurs due to the induced torque from the changing magnetic environment, which affects how the wheel spins. Notably, the final angular speed of the wheel does not depend on the length of time \( \Delta t \) over which the magnetic field is turned off. Instead, it's determined by the change in magnetic flux and properties like the wheel’s moment of inertia \( I \).

Understanding how angular speed is calculated involves the relationship between torque and moment of inertia. The torque caused by the induced electromotive force contributes to the angular acceleration \( \alpha \), which can be used to find the change in angular speed \( \omega = \omega_0 + \alpha \Delta t \), where \( \omega_0 \) is the initial angular speed (which is zero if the wheel starts at rest).

In summary, angular speed in this context is about how fast the rotation happens after the external influence of the magnetic field is applied or removed.
Faraday's Law of Induction
Faraday's Law of Induction is one of the cornerstones of electromagnetism. It explains how a change in magnetic field within a closed loop induces an electromotive force (EMF). The principle is elegantly summarized by the equation \( \varepsilon = -\frac{d\Phi}{dt} \), indicating that the induced EMF is proportional to the rate of change of magnetic flux \( \Phi \).

In this exercise, the wheel's rim experiences a change in magnetic flux when the magnetic field \( B_0 \) is turned off. This scenario is a classic application of Faraday's Law, as the diminishing field alters the flux through the area defined by the wheel's size, consequently inducing an EMF. This induced EMF then creates a current around the non-conducting rim, despite it itself being non-conductive.

To compute the induced EMF practically, you would calculate the change in flux \( \Delta \Phi \) over the time period \( \Delta t \) during which the magnetic field is altered. The relationship \( \varepsilon = \frac{B_0 \pi a^2}{\Delta t} \) is derived, signifying how flux change per unit time directly creates an electric potential difference around the wheel's circumference.

Thus, Faraday’s Law provides the foundational underlying physics for understanding how a wheel suspended in a magnetic field will react dynamically when that field is altered. It helps predict the behavior and rotation speed, providing a real-world application of electromagnetic principles.
Electromotive Force (EMF)
Electromotive force (EMF) refers to the voltage generated by a battery or by the magnetic forces according to Faraday's Law. It is essentially a measure of the energy that drives electric charge around a circuit. In the context of this problem, EMF is generated in response to changes in the magnetic environment surrounding the charged wheel.

When the magnetic field \( B_0 \) is switched off, a time-varying magnetic field results, inducing EMF across the coil of the wheel despite its non-conducting properties. This is possible due to the wheel's ability to have a charge density \( \lambda \) on its rim. The induced EMF results in an electric current around the rim defined by Ohm's Law as \( I = \frac{\varepsilon}{R} \), where \( R \) is the resistance in the system.

The current produced by the EMF consequently generates a torque that leads to rotational motion of the wheel, ultimately determining the angular speed. This whole process is facilitated by the induced electric field resulting from the turned off magnetic field. The torque \( \tau \), which contributes to rotational dynamics, stems directly from this induced EMF and the corresponding current.

Recognizing EMF's role in driving charge movement around the wheel forms an integral part of analyzing this problem. It illustrates the beautiful interplay between magnetic changes and mechanical motion, showcasing the principles of electromagnetism in action.

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Most popular questions from this chapter

In a physics laboratory experiment, a coil with 200 turns enclosing an area of \(12 \mathrm{~cm}^{2}\) is rotated in \(0.040 \mathrm{~s}\) from a position where its plane is perpendicular to the earth's magnetic field to a position where its plane is parallel to the field. The earth's magnetic field at the lab location is \(6.0 \times 10^{-5} \mathrm{~T}\). (a) What is the total magnetic flux through the coil before it is rotated? After it is rotated? (b) What is the average emf induced in the coil?

A long, straight solenoid with a cross-sectional area of \(8.00 \mathrm{~cm}^{2}\) is wound with 90 turns of wire per centimeter, and the windings carry a current of \(0.350 \mathrm{~A}\). A second winding of 12 turns encircles the solenoid at its center. The current in the solenoid is turned off such that the magnetic field of the solenoid becomes zero in \(0.0400 \mathrm{~s}\). What is the average induced emf in the second winding?

A single loop of wire with an area of \(0.0900 \mathrm{~m}^{2}\) is in a uniform magnetic field that has an initial value of \(3.6 \mathrm{~T}\), is perpendicular to the plane of the loop, and is decreasing at a constant rate of \(0.18 \mathrm{~T} / \mathrm{s}\). (a) What emf is induced in this loop? (b) If the loop has a resistance of \(0.600 \Omega\), find the current induced in the loop.

A square, conducting, wire loop of side \(L\), total mass \(m\), and total resistance \(R\) initially lies in the horizontal \(x y\)-plane, with corners at \((x, y, z)=(0,0,0),(0, L, 0),(L, 0,0)\), and \((L, L, 0)\). There is a uniform, upward magnetic field \(\overrightarrow{\boldsymbol{B}}=B \hat{\boldsymbol{k}}\) in the space within and around the loop. The side of the loop that extends from \((0,0,0)\) to \((L, 0,0)\) is held in place on the \(x\)-axis; the rest of the loop is free to pivot around this axis. When the loop is released, it begins to rotate due to the gravitational torque. (a) Find the net torque (magnitude and direction) that acts on the loop when it has rotated through an angle \(\phi\) from its original orientation and is rotating downward at an angular speed \(\omega .\) (b) Find the angular acceleration of the loop at the instant described in part (a). (c) Compared to the case with zero magnetic field, does it take the loop a longer or shorter time to rotate through \(90^{\circ}\) ? Explain. (d) Is mechanical energy conserved as the loop rotates downward? Explain.

Search Coils and Credit Cards. One practical way to measure magnetic field strength uses a small, closely wound coil called a search coil. The coil is initially held with its plane perpendicular to a magnetic field. The coil is then either quickly rotated a quarter-turn about a diameter or quickly pulled out of the field. (a) Derive the equation relating the total charge \(Q\) that flows through a search coil to the magnetic-field magnitude \(B\). The search coil has \(N\) turns, each with area \(A\), and the flux through the coil is decreased from its initial maximum value to zero in a time \(\Delta t\). The resistance of the coil is \(R\), and the total charge is \(Q=I \Delta t\), where \(I\) is the average current induced by the change in flux. (b) In a credit card reader, the magnetic strip on the back of a credit card is rapidly "swiped" past a coil within the reader. Explain, using the same ideas that underlie the operation of a search coil, how the reader can decode the information stored in the pattern of magnetization on the strip. (c) Is it necessary that the credit card be "swiped" through the reader at exactly the right speed? Why or why not?

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