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A ring of diameter \(8.00 \mathrm{~cm}\) is fixed in place and carries a charge of \(+5.00 \mu \mathrm{C}\) uniformly spread over its circumference. (a) How much work does it take to move a tiny \(+3 \mu \mathrm{C}\) charged ball of mass \(1.50 \mathrm{~g}\) from very far away to the center of the ring? (b) Is it necessary to take a path along the axis of the ring? Why? (c) If the ball is slightly displaced from the center of the ring, what will it do and what is the maximum speed it will reach?

Short Answer

Expert verified
(a) 3.37 J of work is needed. (b) No, the path doesn't matter. (c) It remains stationary at equilibrium unless disturbed.

Step by step solution

01

Understand the Basic Concept

This problem involves a uniform ring charge creating an electric field, which affects the work needed to move another charged object into its center. The integral of the electric field over the distance gives the work done.
02

Calculating the electric potential at the center

The potential (\( V \) ) at the center of a charged ring can be calculated by using the formula \[ V = \frac{k \, Q}{R} \] where \( R \) is the radius of the ring (\( 4.00 \, \text{cm} = 0.04 \, \text{m} \)), \( Q \) is the charge of the ring (\( +5.00 \, \mu \text{C} = 5.00 \, \times 10^{-6} \, \text{C} \)), and \( k = 8.99 \times 10^{9} \, \text{Nm}^{2} \text{C}^{-2} \) is Coulomb's constant. Substituting the values, we find \( V \).
03

Calculate the work done to bring the charge to the center

The work done (\( W \)) to move a charge \( q \) from infinity to a point with potential \( V \) is given by \[ W = q \cdot V \]. Here, \( q = +3 \, \mu \text{C} = 3 \times 10^{-6} \, \text{C} \). Use the potential calculated in Step 2 to find \( W \).
04

Evaluate the path independence

The work done on any charge in an electric field is path independent if the field is conservative, which holds for electric fields around stationary charges. It's only dependent on the initial and final positions.
05

Analyze motion when displaced

If the ball is displaced slightly from the center of a ring, it will experience no net electric force because the electric potential is constant at the region's center. Instead, any motion would stem from gravitational effects needing more examination. Assuming slight displacement doesn't significantly shift equilibrium, calculate max speed using conservation of mechanical energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work Energy Principle
The Work Energy Principle is a crucial concept in physics that links the work done on an object to its energy change. In this context, we're considering an electric charge being moved within an electric field. The principle states that when work is done on an object, its energy changes either due to changes in motion or position.
The work done, usually calculated as the force applied times the distance moved, results in an energy change, often transforming potential energy into kinetic energy and vice versa. For a charged particle moving in an electric field, this principle helps us understand how electric potential energy is gained or lost.
  • Work ( \( W \)) is given by: \[ W = q \cdot V \]
  • Where \( q \) is the charge and \( V \) is the electric potential the charge moves through.
This relationship allows us to compute the energy dynamics involved in moving a charge from a region with one electric potential to another, especially from infinity (where the potential is generally zero) to a point where potential exists, for instance, at the center of a charged ring.
Electric Field
Electric fields are the regions around charged objects where other charges experience a force. This invisible force field, so to speak, is a fundamental concept that explains how static electricity influences objects at a distance.
When a charge is brought into an electric field, it experiences a force according to Coulomb's law, which depends on the amount of charge and the strength of the field. In this exercise, the charged ring creates an electric field where another charge can interact.
The calculations show that the electric field itself can be described as the force per charge. The work to move a charge in this field is independent of path taken if the field is conservative, as in stationary charge systems like our ring:
  • An electric field ( \( E \)) can be viewed as the gradient of electric potential ( \( V \)).
  • This means that moving within this field is directly tied to changes in electric potential energy.
Understanding how electric fields work allows you to predict the effects of electrostatic forces, crucial for calculating how and where energy is stored or transferred in systems.
Conservation of Energy
The principle of Conservation of Energy is a cornerstone in physics, stating that energy in a closed system remains constant. Energy cannot be created or destroyed; it only changes form. In the context of this exercise, we use this principle to determine the movement and speed of the charged ball.
When the ball is initially moved to the center of the ring, potential energy is transformed to kinetic energy should it be slightly displaced. Since the electric potential is constant at the center, the analysis shifts to potential energy being converted to kinetic energy due to gravitational effects as the ball moves:
  • The total mechanical energy ( \( E_m \)) is a sum of potential and kinetic energy.
  • For a displaced charge, the maximum speed corresponds to the minimum potential energy.
This principle ensures that, despite the absence of net force due to electric field reflections at the center, energy constraints can still predict the motion outcome. Through conservation laws, one can calculate the energy state transformations as the ball completes its movement, thus determining speeds accurately.

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Most popular questions from this chapter

* Three point charges, which initially are infinitely far apart, are placed at the corners of an equilateral triangle with sides \(d\). Two of the point charges are identical and have charge \(q\). If zero net work is required to place the three charges at the corners of the triangle, what must the value of the third charge be?

CP Two large, parallel conducting plates carrying opposite charges of equal magnitude are separated by \(2.20 \mathrm{~cm} .\) (a) If the surface charge density for each plate has magnitude \(47.0 \mathrm{nC} / \mathrm{m}^{2}\), what is the magnitude of \(\overrightarrow{\boldsymbol{E}}\) in the region between the plates? (b) What is the potential difference between the two plates? (c) If the separation between the plates is doubled while the surface charge density is kept constant at the value in part (a), what happens to the magnitude of the electric field and to the potential difference?

* (a) Calculate the potential energy of a system of two small spheres, one carrying a charge of \(2.00 \mu \mathrm{C}\) and the other a charge of \(-3.50 \mu \mathrm{C}\), with their centers separated by a distance of \(0.250 \mathrm{~m}\). Assume zero potential energy when the charges are infinitely separated. (b) Suppose that one of the spheres is held in place and the other sphere, which has a mass of \(1.50 \mathrm{~g}\), is shot away from it. What minimum initial speed would the moving sphere need in order to escape completely from the attraction of the fixed sphere? (To escape, the moving sphere would have to reach a velocity of zero when it was infinitely distant from the fixed sphere.)

Self-Energy of a Sphere of Charge. A solid sphere of radius \(R\) contains a total charge \(Q\) distributed uniformly throughout its volume. Find the energy needed to assemble this charge by bringing infinitesimal charges from far away. This energy is called the "self-energy" of the charge distribution. (Hint: After you have assembled a charge \(q\) in a sphere of radius \(r\), how much energy would it take to add a spherical shell of thickness \(d r\) having charge \(d q ?\) Then integrate to get the total energy.)

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