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Observing Jupiter. You are asked to design a space telescope for earth orbit. When Jupiter is \(6 \times 10^{8} \mathrm{~km}\) away, the telescope is to resolve, by Rayleigh's criterion, features on Jupiter that are \(240 \mathrm{~km}\) apart. What minimum-diameter mirror is required? Assume a wavelength of \(500 \mathrm{~nm}\).

Short Answer

Expert verified
The minimum-diameter mirror required is 1.525 meters.

Step by step solution

01

Understanding the Rayleigh Criterion

The Rayleigh criterion for a circular aperture is given by \( \theta = 1.22 \frac{\lambda}{D} \), where \( \theta \) is the resolving angle in radians, \( \lambda \) is the wavelength of light, and \( D \) is the diameter of the telescope's primary mirror. The smaller the angle \( \theta \), the higher the resolution of the telescope.
02

Calculate the Resolving Angle from Distance

The resolving angle \( \theta \) can be approximated by \( \theta \approx \frac{s}{L} \) for small angles, where \( s \) is the separation of objects (240 km) and \( L \) is the distance to the objects (\(6 \times 10^8\ km\)). Thus, \( \theta = \frac{240}{6 \times 10^8} \approx 4 \times 10^{-7} \ rad \).
03

Relate Wavelength and Diameter

Using the Rayleigh formula \( \theta = 1.22 \frac{\lambda}{D} \), set \( \theta = 4 \times 10^{-7} \), \( \lambda = 500 \ nm = 500 \times 10^{-9} \ m \). Substitute to find \( D \):\[ 4 \times 10^{-7} = 1.22 \frac{500 \times 10^{-9}}{D} \]Solve for \( D \).
04

Solving for Minimum Diameter

Rearrange the equation to solve for \( D \):\[ D = \frac{1.22 \times 500 \times 10^{-9}}{4 \times 10^{-7}} \]Calculate \( D \):\[ D \approx \frac{610 \times 10^{-9}}{4 \times 10^{-7}} = 1.525 \ meters \]
05

Conclusion

A telescope with a mirror diameter of at least 1.525 meters is required to resolve features 240 km apart on Jupiter when it is \(6 \times 10^{8} \ km\) away.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resolving Power of Telescope
The resolving power of a telescope is its ability to distinguish between two close objects in space. This is crucial when observing distant planets like Jupiter, where specific features need to be discerned. The Rayleigh criterion provides a way to calculate this resolving capability. According to this criterion, the minimum angle that can be resolved by a telescope is given by the equation: \[ \theta = 1.22 \frac{\lambda}{D} \]where:
  • \( \theta \) is the angular resolution in radians.
  • \( \lambda \) is the wavelength of light used, in meters.
  • \( D \) is the diameter of the telescope's mirror, also in meters.
To resolve the fine details of distant celestial bodies, a telescope with a high resolving power and large mirror diameter is essential. This function of resolving power defines how sharp the image of Jupiter's features would be when separated by a known distance, such as 240 km, as in our exercise. This capability hinges on the Rayleigh criterion, which is pivotal in astronomical observations.
Minimum Diameter of Telescope Mirror
Determining the minimum diameter of a telescope mirror for a specific resolution involves using the Rayleigh criterion. An observation mission with Jupiter, positioned at a distance of \(6 \times 10^{8} \ km\), requires distinguishing features 240 km apart. To achieve this, the equation becomes:\[ D = \frac{1.22 \times \lambda}{\theta} \]Given the data:
  • The wavelength \( \lambda \) is 500 nm, which is \(500 \times 10^{-9} \ m\).
  • The resolving angle \( \theta \) derived from the distance and separation is \(4 \times 10^{-7} \ rad\).
Substitute these values into the equation to find:\[ D = \frac{1.22 \times 500 \times 10^{-9}}{4 \times 10^{-7}} \approx 1.525 \ m \]This calculation shows that a space telescope needs a primary mirror that is at least 1.525 meters in diameter to resolve features on Jupiter at the given parameters. This measurements ensure that the telescope can capture clear, separated images of the specified object distances.
Wavelength of Light in Resolution Calculations
Wavelength plays a significant role in calculating a telescope's resolution using the Rayleigh criterion. In the context of spatial observation, particularly with celestial objects, different wavelengths can affect the resolving power of a telescope.The formula \( \theta = 1.22 \frac{\lambda}{D} \) highlights the direct relationship between wavelength and resolution. Here:
  • Shorter wavelengths (like blue light) tend to provide better resolution because the resolving angle \( \theta \) becomes smaller.
  • Longer wavelengths (such as red light) increase the resolving angle, thereby reducing resolution.
  • For our scenario with a wavelength of 500 nm (a green light), this wavelength offers a balanced range typical for many optical observations.
The choice of wavelength directly impacts the required diameter of the mirror for specific resolution capabilities. Thus, understanding this relationship is crucial for design considerations where precise imaging of planets and distant stars is a priority. By selecting a proper wavelength, astronomers can optimize their telescopes to obtain the most detailed and accurate visual data.

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Most popular questions from this chapter

Photography. A wildlife photographer uses a moderate telephoto lens of focal length \(135 \mathrm{~mm}\) and maximum aperture \(f / 4.00\) to photograph a bear that is \(11.5 \mathrm{~m}\) away. Assume the wavelength is \(550 \mathrm{~nm}\). (a) What is the width of the smallest feature on the bear that this lens can resolve if it is opened to its maximum aperture? (b) If, to gain depth of field, the photographer stops the lens down to \(f / 22.0\), what would be the width of the smallest resolvable feature on the bear?

An astronaut in the space shuttle can just resolve two point sources on earth that are \(65.0 \mathrm{~m}\) apart. Assume that the resolution is diffraction limited and use Rayleigh's criterion. What is the astronaut's altitude above the earth? Treat his eye as a circular aperture with a diameter of \(4.00 \mathrm{~mm}\) (the diameter of his pupil), and take the wavelength of the light to be \(550 \mathrm{~nm}\). Ignore the effect of fluid in the eye.

In a YDSE apparatus, two identical slits are separated by \(1 \mathrm{~mm}\) and distance between slits and screen is \(1 \mathrm{~m}\). The wavelength of light used is \(6000 \AA\). Find the minimum distance between two points on the screen having \(75 \%\) intensity of the maximum intensity.

A hair is placed at one edge between two flat galss plates. When this arrangement is illuminated with yellow light of wavelength \(\lambda=600 \mathrm{~nm}\), a total of 121 dark bands are counted starting at the contact point between the plates, and ending at the hair. How thick is the hair?

Two satellites at an altitude of \(1400 \mathrm{~km}\) are separated by 28 \(\mathrm{km}\). If they broadcast \(3.6-\mathrm{cm}\) microwaves, what minimum receiving-dish diameter is needed to resolve (by Rayleigh's criterion) the two transmissions?

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