Chapter 16: Problem 12
Observing Jupiter. You are asked to design a space telescope for earth orbit. When Jupiter is \(6 \times 10^{8} \mathrm{~km}\) away, the telescope is to resolve, by Rayleigh's criterion, features on Jupiter that are \(240 \mathrm{~km}\) apart. What minimum-diameter mirror is required? Assume a wavelength of \(500 \mathrm{~nm}\).
Short Answer
Step by step solution
Understanding the Rayleigh Criterion
Calculate the Resolving Angle from Distance
Relate Wavelength and Diameter
Solving for Minimum Diameter
Conclusion
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Resolving Power of Telescope
- \( \theta \) is the angular resolution in radians.
- \( \lambda \) is the wavelength of light used, in meters.
- \( D \) is the diameter of the telescope's mirror, also in meters.
Minimum Diameter of Telescope Mirror
- The wavelength \( \lambda \) is 500 nm, which is \(500 \times 10^{-9} \ m\).
- The resolving angle \( \theta \) derived from the distance and separation is \(4 \times 10^{-7} \ rad\).
Wavelength of Light in Resolution Calculations
- Shorter wavelengths (like blue light) tend to provide better resolution because the resolving angle \( \theta \) becomes smaller.
- Longer wavelengths (such as red light) increase the resolving angle, thereby reducing resolution.
- For our scenario with a wavelength of 500 nm (a green light), this wavelength offers a balanced range typical for many optical observations.