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A satellite \(575 \mathrm{~km}\) above the earth's surface transmits sinusoidal electromagnetic waves of frequency \(92.4 \mathrm{MHz}\) uniformly in all directions, with a power of \(25.0 \mathrm{~kW}\). (a) What is the intensity of these waves as they reach a receiver at the surface of the earth directly below the satellite? (b) What are the amplitudes of the electric and magnetic fields at the receiver? (c) If the receiver has a totally absorbing panel measuring \(15.0 \mathrm{~cm}\) by \(40.0 \mathrm{~cm}\) oriented with its plane perpendicular to the direction the waves travel, what average force do these waves exert on the panel? Is this force large enough to cause significant effects?

Short Answer

Expert verified
(a) The intensity is approximately \(4.12 \times 10^{-9} \text{ W/m}^2\). (b) Electric and magnetic field amplitudes are \(1.24 \text{ V/m}\) and \(4.13 \times 10^{-9} \text{ T}\) respectively. (c) The average force is \(8.24 \times 10^{-19} \text{ N}\), which is negligible.

Step by step solution

01

Calculate the Distance from Satellite to Receiver

The satellite is located above the Earth's surface at a distance of 575 km. The Earth's radius is approximately 6371 km. Therefore, the total distance from the satellite to the receiver on the Earth's surface is given by:\[R = 6371 ext{ km} + 575 ext{ km} = 6946 ext{ km}.\] Convert this distance to meters:\[R = 6946 imes 10^3 ext{ m} = 6946000 ext{ m}.\]
02

Calculate the Intensity of the Waves

The intensity of the waves at a distance \( R \) from the source is given by the formula:\[I = \frac{P}{4\pi R^2},\]where \( P = 25.0 ext{ kW} = 25000 ext{ W} \) is the power output of the satellite. Substitute the values:\[I = \frac{25000}{4\pi (6946000)^2} \approx 4.12 \times 10^{-9} ext{ W/m}^2.\]
03

Determine the Amplitudes of Electric and Magnetic Fields

The relationship between the intensity \( I \), the electric field amplitude \( E \), and the magnetic field amplitude \( B \) is given by:\[I = \frac{c\varepsilon_0 E^2}{2},\]\[I = \frac{cB^2}{2\mu_0},\]where \( c \approx 3 \times 10^8 ext{ m/s} \) is the speed of light, \( \varepsilon_0 = 8.85 \times 10^{-12} ext{ F/m} \) is the permittivity of free space, and \( \mu_0 = 4\pi \times 10^{-7} ext{ Tm/A} \) is the permeability of free space.First, solve for \( E \):\[E = \sqrt{\frac{2I}{c\varepsilon_0}} = \sqrt{\frac{2 \times 4.12 \times 10^{-9}}{3 \times 10^8 \times 8.85 \times 10^{-12}}} \approx 1.24 \text{ V/m}.\]Then, solve for \( B \):\[B = \frac{E}{c} = \frac{1.24}{3 \times 10^8} \approx 4.13 \times 10^{-9} \text{ T}.\]
04

Calculate the Average Force Exerted on the Receiver Panel

The radiation pressure \( P_r \) exerted by the electromagnetic waves on an absorbing surface is given by:\[P_r = \frac{I}{c}.\]The force \( F \) exerted on a surface area \( A \) is then given by:\[F = P_r \cdot A = \frac{I}{c} \cdot A.\]Given \( A = 0.15 ext{ m} \times 0.40 ext{ m} = 0.06 ext{ m}^2 \), substitute the known values to find the force:\[F = \frac{4.12 \times 10^{-9}}{3 \times 10^8} \times 0.06 \approx 8.24 \times 10^{-19} ext{ N}.\]
05

Evaluate the Significance of the Force

The average force calculated in the previous step is very small, approximately \( 8.24 \times 10^{-19} ext{ N} \). This is an extremely tiny force and would not cause any significant effects on the receiver or its environment.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Wave Transmission
The concept of electromagnetic wave transmission is fundamental in understanding how energy travels from a satellite to the Earth. Electromagnetic waves are disturbances that propagate through space and consist of oscillating electric and magnetic fields. These waves do not require a medium; hence, they can travel through the vacuum of space.
In the given exercise, the satellite emits electromagnetic waves uniformly in all directions. This is known as isotropic radiation, meaning the energy is distributed evenly over the surface of a sphere surrounding the source. Understanding this distribution is crucial in calculating the intensity, which relates to the power spread over an area. The distance from the satellite to the Earth significantly affects the intensity, as a greater distance means the energy is spread over a larger area.
By determining the sphere's surface area over which the wave's power spreads, one can calculate the intensity of the waves reaching the Earth. This is important for ensuring the effective transmission and reception of signals or data.
Electric and Magnetic Fields
Electric and magnetic fields are integral components of electromagnetic waves. These fields are perpendicular to each other and the direction in which the wave travels. The electric field (E) and the magnetic field (B) can be calculated from the intensity of the wave.
To find the amplitude of the electric field, we use the relationship between intensity and electric field amplitude: \[I = \frac{c \varepsilon_0 E^2}{2} \], where \(c\)is the speed of light and \(\varepsilon_0\)is the permittivity of free space.
This equation shows that the electric field amplitude is related to the intensity of the wave and the constants of the medium through which it passes. Solving for E helps us to understand how powerful the oscillations of the electric field are as the waves reach the receiver.
Similarly, the amplitude of the magnetic field is found through the relationship \(B = \frac{E}{c}\), establishing a direct connection between electric and magnetic fields. These calculations demonstrate how energy is distributed in the wave through its electric and magnetic components.
Radiation Pressure
When electromagnetic waves strike a surface, they exert a pressure known as radiation pressure. This phenomenon occurs because the waves carry momentum and can transfer this momentum to an object. The exercise highlights that radiation pressure is given by the equation:\[P_r = \frac{I}{c}\], where \(I\)is the intensity of the wave and \(c\)is the speed of light.
Understanding radiation pressure helps in estimating the force that electromagnetic waves can exert on a surface. Despite being a small force, especially in scenarios involving space transmission, radiation pressure plays an essential role in scientific disciplines such as solar sails for spacecraft propulsion.
In the specific scenario provided, the intensity is quite low, leading to an almost negligible radiation pressure on the receiver panel. This negligible pressure is consistent with realistic expectations in satellite communication, where large forces are neither anticipated nor needed.
Force Exerted by Waves
The force exerted by electromagnetic waves on an absorbing surface, like a receiver panel, is calculated by considering radiation pressure and the area of the surface. Using the formula:\[F = P_r \cdot A = \frac{I}{c} \cdot A\], you can determine the average force.
This force depends on the intensity of the waves and the area they impact. In our exercise, with the given low intensity and relatively small area, the resulting force is minuscule, about \(8.24 \times 10^{-19} \text{ N}\). Such a small force is imperceptible and does not affect the receiving apparatus's functionality.
While this force isn't significant in everyday technology applications, understanding it is crucial in specialized fields and precise scientific calculations where wave interactions with materials are relevant.

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Most popular questions from this chapter

A small helium-neon laser emits red visible light with a power of \(4.60 \mathrm{~mW}\) in a beam that has a diameter of \(2.50 \mathrm{~mm}\). (a) What are the amplitudes of the electric and magnetic fields of the light? (b) What are the average energy densities associated with the electric field and with the magnetic field? (c) What is the total energy contained in a \(1.00-\mathrm{m}\) length of the beam?

Television Broadcasting. Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of \(316 \mathrm{~kW}\). Assume that the wave spreads out uniformly into a hemisphere above the ground. At a home \(5.00 \mathrm{~km}\) away from the antenna, (a) what average pressure does this wave exert on a totally reflecting surface, (b) what are the amplitudes of the electric and magnetic fields of the wave, and (c) what is the average density of the energy this wave carries? (d) For the energy density in part (c), what percentage is due to the electric field and what percentage is due to the magnetic field?

A sinusoidal electromagnetic wave having a magnetic field of amplitude \(1.25 \mu \mathrm{T}\) and a wavelength of \(432 \mathrm{~nm}\) is traveling in the \(+x\)-direction through empty space. (a) What is the frequency of this wave? (b) What is the amplitude of the associated electric field? (c) Write the equations for the electric and magnetic fields as functions of \(x\) and \(t\) in the form of Eqs. (12.17).

A source of sinusoidal electromagnetic waves radiates uniformly in all directions. At \(10.0 \mathrm{~m}\) from this source, the amplitude of the electric field is measured to be \(1.50 \mathrm{~N} / \mathrm{C}\). What is the electric-field amplitude at a distance of \(20.0 \mathrm{~cm}\) from the source?

Flashlight to the Rescue. You are the sole crew member of the interplanetary spaceship \(T: 1339\) Vorga, which makes regular cargo runs between the earth and the mining colonies in the asteroid belt. You are working outside the ship one day while at a distance of \(2.0 \mathrm{AU}\) from the sun. [1 AU (astronomical unit) is the average distance from the earth to the sun, \(149,600,000 \mathrm{~km} .]\) Unfortunately, you lose contact with the ship's hull and begin to drift away into space. You use your spacesuit's rockets to try to push yourself back toward the ship, but they run out of fuel and stop working before you can return to the ship. You find yourself in an awkward position, floating \(16.0 \mathrm{~m}\) from the spaceship with zero velocity relative to it. Fortunately, you are carrying a 200-W flashlight. You turn on the flashlight and use its beam as a "light rocket" to push yourself back toward the ship. (a) If you, your spacesuit, and the flashlight have a combined mass of \(150 \mathrm{~kg}\), how long will it take you to get back to the ship? (b) Is there another way you could use the flashlight to accomplish the same job of returning you to the ship?

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