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A \(0.250-H\) inductor carries a time-varying current given by the expression \(i=(124 \mathrm{~mA}) \cos [(240 \pi / \mathrm{s}) t]\). (a) Find an expression for the induced emf as a function of time. Graph the current and induced emf as functions of time for \(t=0\) to \(t=\frac{1}{60} \mathrm{~s}\). (b) What is the maximum emf? What is the current when the induced emf is a maximum? (c) What is the maximum current? What is the induced emf when the current is a maximum?

Short Answer

Expert verified
Maximum emf is 23.40 V at zero current. Maximum current is 0.124 A at zero emf.

Step by step solution

01

Understanding the components

The problem provides us with a time-varying current through an inductor, given by the expression \(i(t) = (124 \text{ mA}) \cos[(240\pi / \text{s}) t]\). Note that the inductance is \(0.250\,\text{H}\). Our task is to find the expression for the induced emf. According to Faraday’s law, the induced emf across an inductor is related to the rate of change of current through it.
02

Expression for induced emf

The induced emf \( \varepsilon (t) \) in an inductor is given by \( \varepsilon (t) = -L \frac{di}{dt} \), where \(L\) is the inductance. First, calculate \( \frac{di}{dt} \):The current is \(i(t) = 0.124 \cos(240\pi t)\). The derivative is: \( \frac{di}{dt} = \frac{d}{dt}(0.124 \cos(240\pi t)) = -0.124 \cdot (240\pi) \sin(240\pi t) \).Thus, \( \frac{di}{dt} = -29.76\pi \sin(240\pi t)\).Substitute into the emf formula: \( \varepsilon (t) = -0.250 \cdot (-29.76\pi) \sin(240\pi t) = 7.44\pi \sin(240\pi t) \). This is the expression for the induced emf.
03

Graph the current and induced emf

To graph the current \(i(t)\) and induced emf \(\varepsilon (t)\) for \(t\) from 0 to \(\frac{1}{60}\ \text{s}\), note that the sin and cos functions have a periodicity.- The current graph is a cosine wave with an amplitude of 0.124 A and frequency determined by \(240\pi\) rad/s.- The emf graph is a sine wave with an amplitude \(7.44\pi\), which corresponds to \(23.40\) V, with the same frequency modeled by \(240\pi\) rad/s.
04

Finding maximum values

The maximum emf occurs when \(\sin(240\pi t) = \pm 1\). Therefore, the maximum induced emf is \(7.44\pi\), which evaluates to \(23.40\) V. At these points, \(\cos(240\pi t) = 0\), implying the current is zero.The maximum current occurs when \(\cos(240\pi t) = \pm 1\), which means it reaches its peak at \(\pm 0.124\) A. At the maximum current, \(\sin(240\pi t) = 0\), leading to zero induced emf.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law is a fundamental principle in electromagnetism that describes how a changing magnetic field can induce voltage, or electromotive force (emf), in a circuit. This is a key concept in understanding how inductors work. An inductor, such as the one in the original exercise, generates an induced emf when there is a change in current flowing through it.

According to the law, the magnitude of the induced emf is proportional to the rate of change of the magnetic flux. In mathematical terms, for an inductor with inductance \(L\), the induced emf \(\varepsilon(t)\) is expressed as:

\[ \varepsilon(t) = -L \frac{di}{dt} \]

The negative sign indicates Lenz's Law, showing that the induced emf acts in a direction to oppose the change in current that created it. This is crucial for various applications like transformers and electrical generators.

In the given exercise, applying Faraday’s Law helps us find the expression for \(\varepsilon(t)\) based on \(\frac{di}{dt}\), the rate of change of current.
Time-varying Current
A time-varying current is one that changes its magnitude and direction with respect to time. In mathematical expressions, this current is often represented in terms of sinusoidal functions such as sine or cosine.

For example, the exercise discusses a current given by:

\( i(t) = (124 \text{ mA}) \cos[(240\pi / \text{s}) t] \)

Here, the amplitude of the current is 124 mA, and it oscillates at an angular frequency of \(240\pi\) rad/s. This means the current completes \(120\) cycles per second\((60\text{ Hz})\) as the term \(\frac{240\pi}{2\pi}\) gives the frequency in Hertz.

Time-varying currents like these are vital in AC circuit analysis and are commonly encountered in electrical engineering and physics.

Understanding how this type of current influences an inductor, leads to the calculation of a time-dependent induced emf, as the rate of change of this current directly affects the emf generation.
Maxima and Minima of Functions
Maxima and minima of functions refer to the highest or lowest points a function reaches, respectively. Finding these points is particularly important in understanding the behavior of oscillating functions, like those describing time-varying currents.

In the exercise, the cosine current function \( i(t) = (124 \text{ mA}) \cos[(240\pi / \text{s}) t] \) reaches its maximum value when \( \cos[(240\pi / \text{s}) t] = \pm 1 \). This is because the maximum of the cosine function is 1, hence the current reaches \( \pm 124 \text{ mA} \).

Similarly, the sine function describing induced emf \( \varepsilon(t) = 7.44\pi \sin[(240\pi / \text{s}) t] \) reaches its maximum when \( \sin[(240\pi / \text{s}) t] = \pm 1 \). This results in a maximum emf of approximately \(23.40 \text{ V} \).

Determining these maxima and minima is crucial in engineering and physics as it helps identify the peak behaviors of functions, which is essential for optimizing circuit performance and other practical applications.

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Most popular questions from this chapter

A \(6 \mu \mathrm{F}\) capacitor is initially charged to a potential of \(16.0 \mathrm{~V} .\) It is then connected in series with \(0.6 \mathrm{mH}\) inductor. (a) What is the total energy stored in this circuit? (b) What is the maximum current in the inductor? What is the charge on the capacitor plates at the instant the current in the inductor is maximal?

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