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It has been proposed to use large inductors as energy storage devices. (a) How much electrical energy is converted to light and thermal energy by a 200-W light bulb in one day? (b) If the amount of energy calculated in part (a) is stored in an inductor in which the current is \(80.0 \mathrm{~A}\), what is the inductance?

Short Answer

Expert verified
The energy converted is 17,280,000 J; the inductance is 5400 H.

Step by step solution

01

Calculate Energy Consumed by Light Bulb

First, calculate the amount of energy consumed by a 200-W light bulb in one day. Power (P) is given by 200 Watts, and we need to find energy over time (t) where the time is one day or 24 hours. Use the formula for energy: \[ E = P \times t \]. Substituting the values, \[ E = 200 \text{ W} \times 24 \times 3600 \text{ s} \],because there are 3600 seconds in an hour. Calculate to find the energy in joules.
02

Energy Computation

Perform the calculation from the previous step:\[ E = 200 \times 24 \times 3600 = 17,280,000 \text{ J} \].This is the electrical energy converted to light and thermal energy in one day.
03

Relate Energy to Inductor Parameters

The energy stored in an inductor is given by the formula \[ E = \frac{1}{2} L I^2 \], where \( E \) is the energy, \( L \) is the inductance, and \( I \) is the current through the inductor. From part (a), we have \( E = 17,280,000 \text{ J} \) and \( I = 80.0 \text{ A} \). Use this information to solve for \( L \):\[ L = \frac{2E}{I^2} \].
04

Solve for Inductance

Substitute the calculated energy and the given current into the formula:\[ L = \frac{2 \times 17,280,000}{80.0^2} = \frac{34,560,000}{6400} \].Simplify to find the value of inductance:\[ L = 5400 \text{ H} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrical Energy Calculation
Electrical energy calculation is essential for understanding the energy consumption of electrical devices. Let's take a 200-Watt light bulb as an example. The power of 200 Watts indicates how much energy the bulb uses every second. To calculate the total energy consumed by the bulb over a specific period, we use the formula: \[ E = P \times t \]where:
  • \(E\) is the energy in joules (J),
  • \(P\) is the power in watts (W), and
  • \(t\) is the time in seconds (s).
For a full day, which consists of 24 hours, the time must be converted to seconds by multiplying the hours by 3600 (the number of seconds in an hour).Consequently, the energy consumed by this bulb in one day is:\[E = 200 \text{ W} \times 24 \times 3600 \text{ s} = 17,280,000 \text{ J}\]This calculated energy shows how much electrical energy is converted to light and heat by the bulb in a single day.
Inductance Calculation
Inductance is a fundamental property of an inductor that determines how well it can store energy. When you have calculated the energy stored in an inductor, you can use this information to find the inductance.The energy stored in an inductor is determined by the formula:\[ E = \frac{1}{2} L I^2 \]Here:
  • \(E\) is the energy stored (in joules),
  • \(L\) is the inductance (in henries), and
  • \(I\) is the current flowing through the inductor (in amperes).
To find the inductance \(L\), rearrange the formula:\[ L = \frac{2E}{I^2} \]Given an energy \(E = 17,280,000 \text{ J}\) and a current \(I = 80.0 \text{ A}\), substitute these values into the formula:\[ L = \frac{2 \times 17,280,000}{80.0^2} = 5400 \text{ H} \]This tells us that the inductance required to store the same amount of energy as consumed by the light bulb is 5400 henries.
Power and Energy Relationship
Understanding the relationship between power and energy is crucial for analyzing electrical systems. Power (\(P\)) refers to the rate at which energy (\(E\)) is consumed or converted. Essentially, power quantifies how quickly energy is used. This relationship can be expressed mathematically as:\[ E = P \times t \]where:
  • \(E\) is energy,
  • \(P\) is power, and
  • \(t\) is time.
In practical terms, if you know the power rating of a device and how long it operates, you can calculate the energy consumption. For example, if a device operates at 200 Watts and runs for an entire day, it consumes 17,280,000 joules of energy, as demonstrated with the light bulb example.Furthermore, this relationship is vital for designing efficient energy storage systems, like inductors. These systems need to align their power and energy capacities to effectively store and release energy without waste. Understanding this balance ensures energy is utilized efficiently, benefiting both cost and environmental impact.

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Most popular questions from this chapter

A \(10.0\)-cm-long solenoid of diameter \(0.400 \mathrm{~cm}\) is wound uniformly with 800 turns. A second coil with 50 turns is wound around the solenoid at its center. What is the mutual inductance of the combination of the two coils?

In a proton accelerator used in elementary particle physics experiments, the trajectories of protons are controlled by bending magnets that produce a magnetic field of \(4.4 \mathrm{~T}\). What is the magnetic-field energy in a \(10.0-\mathrm{cm}^{3}\) volume of space where \(B=4.80 \mathrm{~T}\) ?

An inductor used in a dc power supply has an inductance of \(12.0 \mathrm{H}\) and a resistance of \(180 \Omega\). It carries a current of \(0.300 \mathrm{~A}\). (a) What is the energy stored in the magnetic field? (b) At what rate is thermal energy developed in the inductor? (c) Does your answer to part (b) mean that the magnetic-field energy is decreasing with time? Explain.

A small solid conductor with radius \(a\) is supported by insulating, nonmagnetic disks on the axis of a thin-walled tube with inner radius \(b\). The inner and outer conductors carry equal currents \(i\) in opposite directions. (a) Use Ampere's law to find the magnetic field at any point in the volume between the conductors. (b) Write the expression for the flux \(d \Phi_{B}\) through a narrow strip of length \(l\) parallel to the axis, of width \(d r\), at a distance \(r\) from the axis of the cable and lying in a plane containing the axis. (c) Integrate your expression from part (b) over the volume between the two conductors to find the total flux produced by a current \(i\) in the central conductor. (d) Show that the inductance of a length \(l\) of the cable is \(L=l \frac{\mu_{0}}{2 \pi} \ln \left(\frac{b}{a}\right)\) (e) Use Eq. (10.9) to calculate the energy stored in the magnetic field for a length \(l\) of the cable.

An inductor \(L\) and resistor \(R\) are connected in a single loop. The current reduces to zero from its maximum value. At time \(t=t_{0}\), the energy converted to heat equal the energy stored in the inductor at the time. Find the value of \(t_{0}\).

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