/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 A neutron lives 900 s when at re... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A neutron lives 900 s when at rest relative to an observer. How fast is the neutron moving relative to an observer who measures its life span to be 2065 s?

Short Answer

Expert verified
The neutron's velocity relative to the observer who measures its life span to be 2065 seconds is approximately \(2.548 \times 10^8\text{ m/s}\).

Step by step solution

01

Write down the time dilation equation

The time dilation equation is given by: \(t' = \frac{t}{\sqrt{1 - \frac{v^2}{c^2}}}\) Where: \(t'\) = dilated time observed by the moving observer \(t\) = proper time observed by the stationary observer \(v\) = relative velocity of the moving observer \(c\) = speed of light In this exercise, we are given \(t' = 2065\text{ s}\) and \(t = 900\text{ s}\). We will solve this equation for the unknown \(v\).
02

Rearrange the equation to isolate \(v^2\)

First, we need to isolate the term \(\frac{v^2}{c^2}\) from the time dilation equation. To do this, we will multiply both sides by \(\sqrt{1 - \frac{v^2}{c^2}}\) and then square both sides of the equation. Rearranging, we get: \(\frac{v^2}{c^2} = 1 - \frac{t^2}{t'^2}\)
03

Substitute given values and solve for \(v^2\)

Now, substitute the given values of \(t = 900\text{ s}\) and \(t' = 2065\text{ s}\) into the equation and solve for \(v^2\): \(\frac{v^2}{c^2} =1 - \frac{(900\text{ s})^2}{(2065\text{ s})^2}\) Calculating the right side, we have: \(\frac{v^2}{c^2} = 0.8792885\)
04

Solve for v

Now, solve for \(v\) by multiplying both sides by \(c^2\) and taking the square root of both sides: \(v = c\sqrt{0.8792885}\) Since \(c\) is the speed of light, \(c = 3\times10^8\text{ m/s}\). Substitute this value for \(c\) and calculate the value of \(v\): \(v = (3\times10^8\text{ m/s})\sqrt{0.8792885}\) After the calculation, we find that the neutron's velocity relative to the observer who measures its life span to be 2065 seconds is approximately \(2.548 \times 10^8\text{ m/s}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
In the realm of physics, special relativity stands as a monument of 20th-century scientific breakthroughs. Devised by Albert Einstein in 1905, this groundbreaking theory reshaped our understanding of time, space, and motion. It asserts that the laws of physics are the same for all non-accelerating observers, and it describes the relationship between time and space. As a result, we find that observers in different inertial frames can disagree on the measurements of time intervals and distances.

Crucial to special relativity is the idea that nothing can travel faster than the speed of light in a vacuum, often represented by the symbol 'c' and valued at approximately 299,792,458 meters per second. This speed limit leads to fascinating phenomena such as time dilation and length contraction, where moving clocks tick slower, and objects appear shorter along their direction of motion to an observer compared to those at rest.

Practical Implications of Special Relativity

GPS satellites are a practical example, where tiny adjustments due to relativistic effects are crucial for accurate location data. Without accounting for time dilation, the system would accrue significant errors each day. Thus, comprehending special relativity is not just academically stimulating but also has real-world applications.
Neutron Decay
One of the classic experiments that exhibit principles from special relativity is the observation of neutron decay. Neutrons are subatomic particles present in the nucleus of an atom along with protons. Unlike protons, which are positively charged, neutrons hold no electrical charge and are referred to as neutral.

Neutron decay is a type of radioactive decay in which a neutron transforms into a proton, an electron, and an antineutrino, a process called beta decay. The lifespan of a free neutron — a neutron outside an atomic nucleus — is about 14 minutes and 39 seconds (or 879 seconds) when measured at rest. However, due to the effects of time dilation, the observed neutron decay time changes when measured from different reference frames, especially those moving at high velocities relative to the neutron.

Experiments with Moving Neutrons

Particle accelerators and cosmic ray observations indirectly demonstrate this effect by showing longer decay times for fast-moving neutrons compared to those at rest, a classic verification of time dilation.
Lorentz Factor
A key mathematical component of special relativity is the Lorentz factor, often symbolized by the Greek letter gamma \( \gamma \). It quantifies how much time, length, and relativistic mass change for an object while in motion compared to the object's rest state. The formula for the Lorentz factor is \( \gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} \), where \( v \) is the velocity of the object, and \( c \) is the speed of light.

The Lorentz factor grows larger as an object's speed increases relative to the speed of light. As \( v \) approaches \( c \), the Lorentz factor approaches infinity, which implies that the effects of time dilation become profoundly significant. In simpler terms, as you move faster, time slows down more compared to someone who is stationary.

Use in Time Dilation Equation

In our initial exercise, the Lorentz factor explains why the neutron's decay can be observed as longer than its rest lifespan. It helps us calculate the exact speed at which time dilation effects become noticeable and match the observed elongated lifespan. Without the Lorentz factor, we would not be able to understand or predict how time and space are influenced by the velocity of objects.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

There is approximately \(10^{34} \mathrm{J}\) of energy available from fusion of hydrogen in the world's oceans. (a) If \(10^{33} \mathrm{J}\) of this energy were utilized, what would be the decrease in mass of the oceans? (b) How great a volume of water does this correspond to? (c) Comment on whether this is a significant fraction of the total mass of the oceans.

Show that for any relative velocity \(v\) between two observers, a beam of light projected by one directly away from the other will move away at the speed of light (provided that \(v\) is less than \(c,\) of course).

Describe the shape of the world line on a spacetime diagram of (a) an object that remains at rest at a specific position along the \(x\) -axis; (b) an object that moves at constant velocity \(u\) in the \(x\) -direction; \((c)\) an object that begins at rest and accelerates at a constant rate of in the positive \(x\) -direction.

(a) How fast would an athlete need to be running for a \(100-\mathrm{m}\) race to look 100 yd long? (b) Is the answer consistent with the fact that relativistic effects are difficult to observe in ordinary circumstances? Explain.

A spaceship is heading 35. Unreasonable directly toward Earth at a velocity of \(0.800 c .\) The astronaut on board claims that he can send a canister toward the Earth at \(1.20 c\) relative to Earth. (a) Calculate the velocity the canister must have relative to the spaceship. (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.