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On a certain crystal, a first-order X-ray diffraction maximum is observed at an angle of \(27.1^{\circ}\) relative to its surface, using an X-ray source of unknown wavelength. Additionally, when illuminated with a different, this time of known wavelength \(0.137 \mathrm{nm},\) a second-order maximum is detected at \(37.3^{\circ} .\) Determine (a) the spacing between the reflecting planes, and (b) the unknown wavelength.

Short Answer

Expert verified
The spacing between the reflecting planes is approximately 0.235 nm, and the unknown wavelength is approximately 0.207 nm.

Step by step solution

01

Use Bragg's Law with the second-order maximum data

Using Bragg's Law and the given angle and wavelength for the second-order maximum, we can find the spacing between the reflecting planes (d). \(n \lambda = 2d \sin{\theta}\) We are given n = 2, λ = 0.137 nm, and θ = 37.3°. Plug in the values and solve for d: \(2 \times 0.137 \mathrm{nm} = 2d \sin{37.3^{\circ}}\)
02

Solve for the spacing between the reflecting planes (d)

Now, we solve the equation for d by dividing both sides by 2sin(37.3°): \(d = \frac{2 \times 0.137 \mathrm{nm}}{2\sin{37.3^{\circ}}}\) \(d = 0.137 \mathrm{nm} \div \sin{37.3^{\circ}}\) \(d \approx 0.235 \mathrm{nm}\) Thus, we find that the spacing between the reflecting planes is approximately 0.235 nm.
03

Use Bragg's Law with the first-order maximum data

Now, we will use Bragg's Law with the given angle for the first-order maximum and the calculated value of d to find the unknown wavelength (λ). \(n \lambda = 2d \sin{\theta}\) We have n = 1, d = 0.235 nm, and θ = 27.1°. Plug in the values and solve for λ: \(1 \times \lambda = 2 \times 0.235 \mathrm{nm} \sin{27.1^{\circ}}\)
04

Solve for the unknown wavelength (λ)

Now, we solve the equation for λ by dividing both sides by sin(27.1°): \(\lambda = 2 \times 0.235 \mathrm{nm} \div \sin{27.1^{\circ}}\) \(\lambda \approx 0.207 \mathrm{nm}\) Thus, we find that the unknown wavelength is approximately 0.207 nm. In conclusion, the spacing between the reflecting planes is approximately 0.235 nm, and the unknown wavelength is approximately 0.207 nm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

X-ray diffraction
X-ray diffraction is a technique used to study the structure of materials at the atomic or molecular level. It involves the scattering of X-rays by the atoms within a crystal, creating a diffraction pattern. This pattern can be analyzed to reveal information about the crystal's structure and the arrangement of atoms within it. When X-rays strike a crystal, they can be diffracted in various directions, and the angles and intensities of these diffracted beams are measured to gather structural data.

The concept of X-ray diffraction is rooted in the interaction between the electromagnetic waves (X-rays) and the periodic array of atoms or ions in the material. The constructive interference of the diffracted waves, as described by Bragg's Law, is key to interpreting these patterns. This is why X-ray diffraction is a fundamental technique in fields such as chemistry, physics, and biology for the analysis of crystalline structures.
reflecting planes spacing
The spacing between reflecting planes, often denoted as \(d\), is an essential parameter in the analysis of crystalline materials. In a crystal, atoms are arranged in a highly ordered, repeating pattern, and this regularity forms a series of parallel planes that can reflect X-rays. The distance between these planes is crucial for understanding how X-rays are scattered when they strike the crystal.

According to Bragg's Law: \(n \lambda = 2d \sin \theta\), where \(n\) is the order of the maximum, \(\lambda\) is the X-ray wavelength, and \(\theta\) is the angle of incidence, the plane spacing \(d\) can be determined if \(\lambda\), \(\theta\), and \(n\) are known. By experimenting with different angles and wavelengths, scientists can measure the spacing between these reflective planes, thus gaining insight into the crystal structure and size.
unknown wavelength determination
Determining an unknown wavelength involves using the known parameters of X-ray diffraction and the principles outlined in Bragg's Law. For instance, if a first-order maximum is observed at a specific angle using a crystal with a known plane spacing, the unknown wavelength of the X-rays can be calculated.

After calculating or knowing the plane spacing \(d\) from a separate measurement involving a known wavelength, you can rearrange Bragg's Law to solve for \(\lambda\): \(\lambda = \frac{2d \sin \theta}{n}\). By inserting the observed angle and the calculated plane spacing into this formula, you can accurately deduce the wavelength of the incident X-rays. This process underscores the interconnectedness of the variables in X-ray diffraction experiments and highlights how knowledge of some parameters enables the determination of others.
first-order and second-order maxima
In the context of Bragg's Law, the term "order" refers to the sequence and conditions under which diffraction occurs most strongly. Bragg's Law dictates that intensity peaks, or "maxima," occur at specific angles. The first-order maximum ( = 1) happens at the lowest angle where constructive interference occurs.

Similarly, higher order maxima like the second-order maximum (n = 2) occur at larger angles. Each order corresponds to reflections where the path difference between waves reflected from successive planes equals an integer multiple of the wavelength. Thus, higher-order maxima provide redundant information about the structural characteristics of the crystal but at different angles, which can help improve measurement accuracy and precision. Using multiple maxima can be quite useful when verifying calculated crystal parameters or determining unknown wavelengths with more certainty.

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Most popular questions from this chapter

The characters of a stadium scoreboard are formed with closely spaced lightbulbs that radiate primarily yellow light. (Use \(\lambda=600 \mathrm{nm}\).) How closely must the bulbs be spaced so that an observer \(80 \mathrm{m}\) away sees a display of continuous lines rather than the individual bulbs? Assume that the pupil of the observer's eye has a diameter of 5.0 \(\mathrm{mm}\)

Find the angle for the third-order maximum for 580-nm-wavelength yellow light falling on a difraction grating having 1500 lines per centimeter.

Consider a spectrometer based on a diffraction grating. Construct a problem in which you calculate the distance between two wavelengths of electromagnetic radiation in your spectrometer. Among the things to be considered are the wavelengths you wish to be able to distinguish, the number of lines per meter on the diffraction grating, and the distance from the grating to the screen or detector. Discuss the practicality of the device in terms of being able to discem between wavelengths of interest.

A double slit produces a diffraction pattern that is a combination of single- and double-slit interference. Find the ratio of the width of the slits to the separation between them, if the first minimum of the single-slit pattern falls on the fifth maximum of the double-slit pattern. (This will greatly reduce the intensity of the fifth maximum.)

For white light \((400 \mathrm{nm}<\lambda<700 \mathrm{nm})\) falling normally on a diffraction grating, show that the second and third-order spectra overlap no matter what the grating constant \(d\) is.

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