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(a) Sodium vapor light averaging \(589 \mathrm{nm}\) in wavelength falls on a single slit of width \(7.50 \mu \mathrm{m}\). At what angle does it produces its second minimum? (b) What is the highest-order minimum produced?

Short Answer

Expert verified
The angle at which the second minimum occurs for sodium vapor light falling on a single slit of width 7.50 μm is approximately \(9.03^{\circ}\). The highest-order minimum produced is the 12th order minimum.

Step by step solution

01

Recall single-slit diffraction formula

We can use single-slit diffraction formula to find the angle at which the minimum occurs. \[\sin{\theta} = \frac{m \lambda}{a}\] where m is the order of the minimum, λ is the wavelength of light, a is the slit width, and θ is the angle.
02

Plug in known values for part (a)

For part (a), we need to find the angle of the second minimum, which means m=2. The wavelength λ = 589 nm and the slit width a = 7.50 μm. Convert the units to same: either convert nm to μm or μm to nm. \(1\,nm = 0.001\,\mu m\) So, λ = 589 nm = 0.589 μm. Now, we can plug in these values into the formula. \[\sin{\theta} = \frac{2 \times 0.589}{7.50}\]
03

Solve for θ in part (a)

Calculate \(\sin{\theta}\) and then find \(\theta\). \[\sin{\theta} = \frac{2 \times 0.589}{7.50} \approx 0.1568\] Now find θ: \[\theta =\sin^{-1}(0.1568) \approx 9.03^{\circ}\] So, the angle at which the second minimum occurs is approximately 9.03°.
04

Determine the maximum value of m for part (b)

For part (b), we need to find the highest-order minimum produced. As per the single-slit diffraction formula, we know that \(\sin{\theta}\leq1\). We can set up the following inequality and find the maximum value of m that satisfies it. \[\frac{m \lambda}{a} \leq1\] Now plug in the values of λ and a. \[\frac{m \times 0.589}{7.50} \leq1\]
05

Solve for the highest order m in part (b)

Rearrange the inequality to find the highest possible value for m: \[m \leq \frac{7.50}{0.589}\] Calculate the maximum m: \[m \leq 12.733\] Since m must be an integer, the highest possible order for a minimum is m = 12. The highest-order minimum produced is the 12th order minimum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Single-Slit Diffraction Formula
Diffraction is a fascinating phenomenon, and the single-slit diffraction formula is a crucial tool in understanding how light behaves when it encounters a narrow opening. The formula is given by: \[\sin{\theta} = \frac{m \lambda}{a}\] This equation helps us calculate the angle \( \theta \) at which minimum intensity, or dark bands, occur in the diffraction pattern. Note the variables involved:
  • \( m \) is the order of the minimum (an integer like 1, 2, 3, etc.).
  • \( \lambda \) is the wavelength of the light.
  • \( a \) is the width of the slit through which the light passes.
Understanding the single-slit diffraction formula is essential for calculating where and at what angles these dark spots appear when light is diffracted. Each minimum corresponds to one such angle, and the order \( m \) indicates its position.
Sodium Vapor Light
Sodium vapor light is commonly used in street lighting due to its efficiency and distinctive yellow-orange hue. The light emitted has an average wavelength of around \(589 \text{ nm}\), lying within the visible spectrum of light. The distinctive color of sodium vapor light primarily arises from emissions involving sodium atoms, which transition between energy levels. This wavelength is significant when applied to phenomena like diffraction, as we see from the formula mentioned earlier. Different wavelengths can affect the pattern produced in a diffraction experiment, making it important to recognize and understand the specific properties of the light being used.
Wavelength
In the context of light and diffraction, the wavelength \(\lambda\) plays a critical role. Wavelength is the distance between consecutive points of a wave that are in phase—typically peak to peak or trough to trough. Light waves travel at incredible speeds, and their wavelengths determine their color in the visible spectrum, ranging from about 400 nm (violet) to 700 nm (red). In diffraction studies, the wavelength helps define patterns of intensity, with longer wavelengths deviating more when passing through a slit or around an obstacle. This is evident in our formula where \(\lambda\) directly affects the angle \(\theta\) for minima in the pattern: increasing the wavelength increases the angle for minima.
Slit Width
The slit width \(a\) is another pivotal concept in diffraction. It indicates the physical width of the opening through which light passes. When light is diffracted through a slit, the width of that slit influences the diffraction pattern. Narrower slits tend to spread light over a wider range of angles, while wider slits restrict the spread. In the single-slit diffraction formula \(\sin{\theta} = \frac{m \lambda}{a}\), the slit width is inversely proportional to the sine of the angle for diffraction minima. Therefore, wider slits produce narrower diffraction patterns since the angle \(\theta\) decreases with increasing \(a\). Conversely, narrow slits result in wider diffraction patterns due to larger angles for minima.

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Most popular questions from this chapter

Monochromatic light of wavelength 530 nm passes through a horizontal single slit of width \(1.5 \mu \mathrm{m}\) in an opaque plate. A screen of dimensions \(2.0 \mathrm{m} \times 2.0 \mathrm{m}\) is \(1.2 \mathrm{m}\) away from the slit. (a) Which way is the diffraction pattern spread out on the screen? (b) What are the angles of the minima with respect to the center? (c) What are the angles of the maxima? (d) How wide is the central bright fringe on the screen? (e) How wide is the next bright fringe on the screen?

A double slit produces a diffraction pattern that is a combination of single- and double-slit interference. Find the ratio of the width of the slits to the separation between them, if the first minimum of the single-slit pattern falls on the fifth maximum of the double-slit pattern. (This will greatly reduce the intensity of the fifth maximum.)

(a) Calculate the angle at which a \(2.00-\mu \mathrm{m}\) -wide slit produces its first minimum for 410 -nm violet light. (b) Where is the first minimum for 700 -nm red light?

When a monochromatic light of wavelength 430 nm incident on a double slit of slit separation \(5 \mu \mathrm{m}\), there are 11 interference fringes in its central maximum. How many interference fringes will be in the central maximum of a light of wavelength \(632.8 \mathrm{nm}\) for the same double slit?

A spy satellite orbits Earth at a height of \(180 \mathrm{km}\). What is the minimum diameter of the objective lens in a telescope that must be used to resolve columns of troops marching \(2.0 \mathrm{m}\) apart? Assume \(\lambda=550 \mathrm{nm}\)

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