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The \(\beta^{-}\) particles emitted in the decay of \(^{3} \mathrm{H}\) (tritium) interact with matter to create light in a glowin-the-dark exit sign. At the time of manufacture, such a sign contains \(15.0 \mathrm{Ci}\) of \(^{3} \mathrm{H}\). (a) What is the mass of the tritium? (b) What is its activity 5.00 y after manufacture?

Short Answer

Expert verified
The initial mass of tritium in the sign is 4.92 x 10鈦宦孤 g, and the activity of tritium in the sign 5 years after manufacture is 3.75 x 10鹿鹿 disintegrations per second.

Step by step solution

01

Gather given information

In this problem, we are given: 1. Initial activity, A鈧 = 15.0 Ci (Curie) 2. Half-life of tritium, t鈧/鈧 = 12.33 years 3. Time elapsed, t = 5.00 years We will also need to use: 1. Avogadro's number, N鈧 = 6.022 x 10虏鲁 atoms/mol 2. Decay constant, 位 (which we will calculate) 3. Activity formula: A = A鈧e^(-位t) 4. The molar mass of tritium: 3.00 g/mol
02

Convert activity from Curie to atoms per second

We know that 1 Ci corresponds to 3.7 x 10鹿鈦 disintegrations per second (dps). So, we can convert the initial activity (15.0 Ci) to disintegrations per second. Initial activity (A鈧) = 15.0 Ci x (3.7 x 10鹿鈦 dps/Ci) = 5.55 x 10鹿鹿 dps
03

Calculate decay constant 位

The decay constant 位 is related to half-life by: 位 = ln(2) / t鈧/鈧 Plug in values: 位 = ln(2) / 12.33 = 0.05627 yr鈦宦
04

Find the initial number of tritium atoms

Using the initial activity and decay constant, we can find the initial number of tritium atoms (N鈧) in the sign as follows: A鈧 = 位N鈧 鈬 N鈧 = A鈧 / 位 N鈧 = (5.55 x 10鹿鹿 dps) / (0.05627 yr鈦宦) = 9.86 x 10鹿虏 atoms
05

Calculate the initial mass of tritium

To find the mass of tritium, we will first determine the initial number of moles, n: n = N鈧 / N鈧 n = (9.86 x 10鹿虏 atoms) / (6.022 x 10虏鲁 atoms/mol) = 1.64 x 10鈦宦孤 mol From the molar mass of tritium (3.00 g/mol), we can find the mass: m = n x Molar mass m = (1.64 x 10鈦宦孤 mol) x (3.00 g/mol) = 4.92 x 10鈦宦孤 g So, the initial mass of tritium (m) in the sign is 4.92 x 10鈦宦孤 g.
06

Compute the activity after 5 years

To find the activity of tritium after 5 years, we can use the activity formula: A = A鈧e^(-位t) Plug in the values: A = (5.55 x 10鹿鹿 dps)e^(-0.05627 x 5) = 3.75 x 10鹿鹿 dps After 5 years, the activity (A) of tritium in the sign is 3.75 x 10鹿鹿 disintegrations per second. In conclusion: a) The mass of tritium in the sign at the time of manufacture is 4.92 x 10鈦宦孤 g. b) The activity of tritium in the sign 5 years after manufacture is 3.75 x 10鹿鹿 disintegrations per second.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
Radioactive decay is a natural process where unstable atomic nuclei lose energy by emitting radiation. This process can occur in several forms, such as alpha, beta, and gamma decay. In the case of tritium (\(^{3} \mathrm{H}\)), beta decay occurs, emitting beta particles (electrons). As a result, tritium transforms into helium-3.
Understanding radioactive decay is essential not only in physics but also in practical applications, like how tritium is used in glowing exit signs. In these signs, the energy from beta decay excites a phosphor, which then emits light.
When substances undergo radioactive decay, they eventually achieve a stable state, either forming a different element or a different isotope of the same element. The rate at which this decay happens is measured through decay constants and half-life.
Half-life
The half-life of a radioactive isotope is the time required for half of the radioactive nuclei in a sample to undergo decay. It is a constant that helps predict how quickly a particular isotope will decay, and it's a vital concept in nuclear physics.
For tritium, the half-life is 12.33 years. This means every 12.33 years, the amount of tritium in a sample will reduce by half, due to its beta decay process.
Half-life helps us understand the longevity and the fading intensity of radioactivity from a material. It has practical applications, such as estimating the age of archaeological finds (radiocarbon dating) or managing nuclear waste.
When calculating the activity of a radioactive material at different times, the half-life is used to find the decay constant (\( 位 \)), using the formula \( 位 = \ln(2) / t_{1/2} \). This constant is crucial to predict how the quantity of the substance changes over time.
Activity Measurement
Activity in nuclear physics refers to how many atoms in a radioactive sample decay per second. It's a measure of the number of disintegrations happening in a unit time and provides an indication of the radioactivity level of a substance.
The unit of activity used most commonly is the Curie (Ci), where 1 Ci is equivalent to \(3.7 \times 10^{10}\) disintegrations per second.
In practical applications, activity helps in judging the effectiveness and safety of radioactive materials. For instance, knowing the activity in a glow-in-the-dark sign helps manufacturers understand how bright the sign will be and for how long it can remain effective.
To find the activity at any particular time, we use the formula: \( A = A鈧e^{(-位t)} \), where \( A鈧 \) is the initial activity, \( 位 \) is the decay constant, and \( t \) is the elapsed time.
Tritium
Tritium is a radioactive isotope of hydrogen known as \( \beta^{-} \) emitter due to its decay process where a neutron converts into a proton, emitting an electron (or beta particle) and an antineutrino. Tritium is represented as \(^{3} \mathrm{H} \), where the number 3 denotes its atomic mass.
It significantly contributes to applications like self-luminous devices. For example, they are commonly used in glow-in-the-dark items such as wristwatch dials and emergency exit signs because they emit light without needing an external power source or sunlight.
Handling tritium requires safety precautions, as it is radioactive. Despite this, its low energy emission makes it safer than many other radioactive substances, posing little risk in small quantities.
Tritium's half-life of 12.33 years defines its long-lasting usability without frequent maintenance or replacement in devices where it's utilized. Its relatively simple chemical nature keeps it in demand for practical use.

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Most popular questions from this chapter

The Galileo space probe was launched on its long journey past Venus and Earth in \(1989,\) with an ultimate goal of Jupiter. Its power source is \(11.0 \mathrm{kg}\) of \(^{238} \mathrm{Pu}\) a by-product of nuclear weapons plutonium production. Electrical energy is generated thermoelectrically from the heat produced when the \(5.59-\mathrm{MeV} \quad \alpha\) particles emitted in each decay crash to a halt inside the plutonium and its shielding. The half-life of \(^{238} \mathrm{Pu}\) is 87.7 years. (a) What was the original activity of the \(^{238} \mathrm{Pu}\) in becquerels? (b) What power was emitted in kilowatts? (c) What power was emitted 12.0 y after launch? You may neglect any extra energy from daughter nuclides and any losses from escaping \(\gamma\) rays.

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