Chapter 9: Problem 29
The current of an electron beam has a measured current of \(I=50.00 \mu \mathrm{A}\) with a radius of \(1.00 \mathrm{mm}^{2}\) What is the magnitude of the current density of the beam?
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 9: Problem 29
The current of an electron beam has a measured current of \(I=50.00 \mu \mathrm{A}\) with a radius of \(1.00 \mathrm{mm}^{2}\) What is the magnitude of the current density of the beam?
All the tools & learning materials you need for study success - in one app.
Get started for free
Car batteries are rated in ampere-hours \((\mathrm{A} \cdot \mathrm{h}) .\) To what physical quantity do ampere-hours correspond (voltage, current, charge, energy, power, \(\dots\) )?
Of what material is a resistor made if its resistance is \(40.0 \%\) greater at \(100.0^{\circ} \mathrm{C}\) than at \(20.0^{\circ} \mathrm{C} ?\)
Consider a resistor made from a hollow cylinder of carbon as shown below. The inner radius of the cylinder is \(R_{i}=0.20 \mathrm{mm}\) and the outer radius is \(R_{0}=0.30 \mathrm{mm}\) The length of the resistor is \(L=0.90 \mathrm{mm}\). The resistivity of the carbon is \(\rho=3.5 \times 10^{-5} \Omega \cdot \mathrm{m} \cdot\) (a) Prove that the resistance perpendicular from the axis is \(R=\frac{\rho}{2 \pi L} \ln \left(\frac{R_{0}}{R_{i}}\right)\) (b) What is the resistance?
What is the resistivity of a wire of 5 -gauge wire \(\left(A=16.8 \times 10^{-6} \mathrm{m}^{2}\right), 5.00 \mathrm{m}\) length, and \(5.10 \mathrm{m} \Omega\) resistance?
The diameter of 0-gauge copper wire is \(8.252 \mathrm{mm}\). Find the resistance of a \(1.00-\mathrm{km}\) length of such wire used for power transmission.
What do you think about this solution?
We value your feedback to improve our textbook solutions.