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The current of an electron beam has a measured current of \(I=50.00 \mu \mathrm{A}\) with a radius of \(1.00 \mathrm{mm}^{2}\) What is the magnitude of the current density of the beam?

Short Answer

Expert verified
The magnitude of the current density of the electron beam is \(50.00 \, \mathrm{A/m^2}\).

Step by step solution

01

Convert the given values to base SI units

Current (I): 50.00 渭A = 50.00 脳 10鈦烩伓 A Area (A): 1.00 mm虏 = 1.00 脳 10鈦烩伓 m虏
02

Calculate the current density

Use the formula J = I / A to find the current density. J = (50.00 脳 10鈦烩伓 A) / (1.00 脳 10鈦烩伓 m虏)
03

Simplify the expression

Cancel out the common factor 10鈦烩伓 in both the numerator and the denominator. J = 50.00 A/m虏 The magnitude of the current density of the electron beam is 50.00 A/m虏.

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