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How much energy is stored in the electrical field of a metal sphere of radius \(2.0 \mathrm{m}\) that is kept at a \(10.0-\mathrm{V}\) potential?

Short Answer

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The detailed steps and calculations give the final answer for the amount of stored energy.

Step by step solution

01

Calculate the charge on the sphere

The charge (Q) on the sphere can be obtained by rearranging the formula \(V = k*Q/R\) to solve for Q. So that Q = V*R/k. Substitute the given values; \(V = 10.0V\), \(R = 2.0m\) and \(k = 9*10^{9}\) to get the Charge on the sphere.
02

Calculate the energy stored in the sphere

Once the charge (Q) on the sphere is obtained, it can be substituted in the formula \(W = 0.5*Q*V\), where \(W\) is the energy, to calculate the energy stored in the sphere. The value of \(V\) provided is \(10.0V\). Substitute these values into the formula to get the amount of energy stored.
03

Write the final answer

Ensure to define the computed energy in the correct units. This should be the final answer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metal Sphere
A metal sphere is a perfectly symmetrical three-dimensional object made of metal. In many physics problems, we consider a metal sphere as a conductor. This means it can freely allow electrons to move across its surface until it's uniformly charged.

This is due to the nature of metals, which contain free electrons that allow them to conduct electricity. When a metal sphere is isolated, any excess charge distributes evenly along its surface. This uniform charge distribution is a characteristic feature of conductive spheres.
  • Metal spheres are often used in physics problems because they simplify calculations.
  • Their geometry allows for assumptions like constant electric field outside the sphere.
  • They help in modeling real-world objects, like charged balls.
Overall, the spherical shape and conductive properties make metal spheres ideal for teaching fundamental concepts in electrostatics.
Electric Potential
Electric potential, or voltage, is the potential energy per unit charge. It represents how much potential energy a charge would have at a certain point in space if there were no other forces at play. In the context of a sphere, the electric potential is dependent on several factors such as the radius of the sphere and the total charge it holds.

For a sphere, the electric potential is given by the formula: \[ V = \frac{k \cdot Q}{R} \]Where:
  • \(V\) is the electric potential, typically in volts (V)
  • \(k\) is Coulomb's constant, approximately \(9 \times 10^9 \text{Nm}^2/ ext{C}^2\)
  • \(Q\) is the charge, in coulombs (C)
  • \(R\) is the radius of the sphere, in meters (m)
When solving these problems, understanding the relationship between voltage, charge, and distance is crucial.

This relationship allows us to determine the charge on a sphere if we know its potential and radius. Thus, electric potential is a cornerstone concept for exploring energy in electric fields.
Capacitance
Capacitance is a measure of how much charge a conductor can store per unit of electric potential. For a sphere, capacitance is particularly simple due to its symmetrical shape. It depends only on its radius, which allows for straightforward calculations based on the geometry of the sphere.

The formula for capacitance \(C\) of an isolated sphere is:\[ C = 4\pi\varepsilon_0 R \]Where:
  • \(C\) is capacitance, usually in farads (F)
  • \(\varepsilon_0\) is the vacuum permittivity, approximately \(8.85 \times 10^{-12} \text{F/m}\)
  • \(R\) is the radius of the sphere, in meters (m)
The ability of a sphere to store charge is determined by both its size and its environment. Larger spheres tend to have higher capacitance, as they can hold more charge for the same potential.

Understanding capacitance helps us analyze how energy is stored in electric fields, especially in terms of practical applications like capacitors in electronic circuits.
Electrostatics
Electrostatics is the branch of physics that studies forces, fields, and potentials arising from static electric charges. It encompasses various phenomena, such as the interactions between charged objects and how they distribute charges in materials.

One key concept in electrostatics is the relationship between electric fields and potentials. An electric field represents the force experienced by a unit positive charge placed in the vicinity of another charge.
  • An electric field is directly related to electric potential by the gradient, or rate of change, of the potential in space.
  • Electrostatic forces between charges are described by Coulomb’s law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
  • The concept of electric field lines visually represents the direction and strength of fields.
In the example of a metal sphere, understanding electrostatic principles helps analyze problems such as energy storage, charge distribution, and potential. Overall, electrostatics is foundational for understanding how forces and fields interact in charged systems.

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Most popular questions from this chapter

Suppose that the capacitance of a variable capacitor can be manually changed from 100 to 800 pF by turning a dial connected to one set of plates by a shaft, from \(0^{\circ}\) to \(180^{\circ}\). With the dial set at \(180^{\circ}\) (corresponding to \(C=800 \mathrm{pF}),\) the capacitor is connected to a \(500-\mathrm{V}\) source. After charging, the capacitor is disconnected from the source, and the dial is turned to \(0^{\circ} .\) (a) What is the charge on the capacitor? (b) What is the voltage across the capacitor when the dial is set to \(0^{\circ} ?\)

An air-filled (empty) parallel-plate capacitor is made from two square plates that are \(25 \mathrm{cm}\) on each side and 1.0 mm apart. The capacitor is connected to a 50 -V battery and fully charged. It is then disconnected from the battery and its plates are pulled apart to a separation of \(2.00 \mathrm{mm}\). (a) What is the capacitance of this new capacitor? (b) What is the charge on each plate? (c) What is the electrical field between the plates?

Some cell walls in the human body have a layer of negative charge on the inside surface. Suppose that the surface charge densities are \(\pm 0.50 \times 10^{-3} \mathrm{C} / \mathrm{m}^{2},\) the cell wall is \(5.0 \times 10^{-9} \mathrm{m}\) thick, and the cell wall material has a dielectric constant of \(\kappa=5.4 .\) (a) Find the magnitude of the electric field in the wall between two charge layers. (b) Find the potential difference between the inside and the outside of the cell. Which is at higher potential? (c) A typical cell in the human body has volume \(10^{-16} \mathrm{m}^{3}\) Estimate the total electrical field energy stored in the wall of a cell of this size when assuming that the cell is spherical. (Hint: Calculate the volume of the cell wall.)

A capacitor is made from two concentric spheres, one with radius \(5.00 \mathrm{cm},\) the other with radius \(8.00 \mathrm{cm} .\) (a) What is the capacitance of this set of conductors? (b) If the region between the conductors is filled with a material whose dielectric constant is \(6.00,\) what is the capacitance of the system?

An empty parallel-plate capacitor has a capacitance of 20 \(\mu\) F. How much charge must leak off its plates before the voltage across them is reduced by \(100 \mathrm{V}\) ?

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