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(a) An infinitesimal amount of heat is added reversibly to a system. By combining the first and second laws, show that \(d U=T d S-d W\). (b) When heat is added to an ideal gas, its temperature and volume change from \(T_{1}\) and \(V_{1}\) to \(T_{2}\) and \(V_{2}\) Show that the entropy change of \(n\) moles of the gas is given by \(\Delta S=n C_{v} \ln \frac{T_{2}}{T_{1}}+n R \ln \frac{V_{2}}{V_{1}}\)

Short Answer

Expert verified
To combine the first and second laws of thermodynamics, we start with the first law: \(dU = dQ - dW\), and replace \(dQ\) with the expression from the second law: \(dQ = TdS\). This yields the desired equation: \(dU = TdS - dW\). For the entropy change of n moles of an ideal gas, we consider changes in temperature and volume separately and sum the respective entropy changes: \(\Delta S = n C_v \ln \frac{T_2}{T_1} + n R \ln \frac{V_2}{V_1}\).

Step by step solution

01

Write down the first law of thermodynamics

The first law of thermodynamics is given by: \(dU = dQ - dW\), where \(dU\) is the change in internal energy, \(dQ\) is the heat added to the system, and \(dW\) is the work done by the system.
02

Write down the second law of thermodynamics

The second law of thermodynamics, expressed in terms of entropy (\(S\)), is given by: \(dQ = TdS\), where \(T\) is the temperature of the system.
03

Combine the two laws

We can substitute the expression for \(dQ\) from the second law into the first law: \(dU = TdS - dW\). Thus, we have combined the first and second laws of thermodynamics and derived the desired equation. #b) Entropy change for an ideal gas#
04

Write down the expressions for heat capacities

For an ideal gas, heat capacity at constant volume (\(C_v\)) and at constant pressure (\(C_p\)) are related by: \(C_p = C_v + R\), where \(R\) is the gas constant.
05

Write down the expressions for the change in entropy

The change in entropy (\(\Delta S\)) can be expressed in terms of heat capacities as follows: (1) For a temperature change at constant volume: \(\Delta S_v = n C_v \ln \frac{T_2}{T_1}\) (2) For a volume change at constant temperature: \(\Delta S_p = n R \ln \frac{V_2}{V_1}\)
06

Find the total entropy change

To find the total entropy change, we simply add the entropy changes from steps (1) and (2): \(\Delta S = \Delta S_v + \Delta S_p = n C_v \ln \frac{T_2}{T_1} + n R \ln \frac{V_2}{V_1}\) Now, we have derived the equation for the entropy change of n moles of an ideal gas given the initial and final temperatures and volumes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Law of Thermodynamics
The First Law of Thermodynamics is a principle that connects heat, work, and internal energy in a system. It emphasizes that energy cannot be created or destroyed, only transformed.
In a mathematical form, this can be written as:
  • \(dU = dQ - dW\)
Here, \(dU\) represents the change in internal energy of the system, \(dQ\) is the heat added to the system, and \(dW\) is the work done by the system.
When heat is added to a system, it increases the internal energy unless some of it is used to perform work. This concept helps us understand energy conservation within thermodynamic processes. When combined with the second law, this equation can also express the reversible addition of heat, linking it deeply with concepts of entropy and irreversibility.
Second Law of Thermodynamics
The Second Law of Thermodynamics introduces the concept of entropy, which is a measure of disorder or randomness in a system. It informs us that entropy in an isolated system always tends to increase or remain the same, indicating the natural direction of processes.
  • The mathematical form is \(dQ = TdS\), where \(T\) is the temperature and \(dS\) is the change in entropy.
This expression helps in understanding that when heat transfer occurs, it results in entropy changes, showing a directionality to thermal interactions.
In practice, this means that not all heat in a system can do work, as some energy is unavailable due to entropy. This ties directly into understanding inefficiencies in processes like engines, and establishes that spontaneous processes occur naturally to increase total entropy. Combined, these laws beautifully explain how heat and work interplay within physical systems.
Entropy Change
Entropy change is an essential concept for predicting the spontaneity of a process and the extent of energy dispersion in a system.
For an ideal gas, we can quantify the change in entropy during transitions between different states of temperature and volume. Considering \(n\) moles of an ideal gas, the equation for entropy change, derived from its principles, is:
  • \(\Delta S = n C_v \ln \frac{T_2}{T_1} + n R \ln \frac{V_2}{V_1}\)
  • \(n C_v \ln \frac{T_2}{T_1}\): Accounts for entropy change due to temperature change at constant volume.
  • \(n R \ln \frac{V_2}{V_1}\): Accounts for entropy change due to volume change at constant temperature.
It highlights how both temperature and volume affect the distribution of energy within the gas, thereby affecting entropy. Understanding entropy change allows us to predict how different substances react to energy exchange, making it fundamental in thermodynamic analysis and systems engineering.

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Most popular questions from this chapter

A Carnot engine performs \(100 \mathrm{J}\) of work while discharging \(200 \mathrm{J}\) of heat each cycle. After the temperature of the hot reservoir only is adjusted, it is found that the engine now does \(130 \mathrm{J}\) of work while discarding the same quantity of heat. (a) What are the initial and final efficiencies of the engine? (b) What is the fractional change in the temperature of the hot reservoir?

A Carnot engine operates between reservoirs at 600 and 300 K. If the engine absorbs 100 J per cycle at the hot reservoir, what is its work output per cycle?

An engineer must design a refrigerator that does 300 J of work per cycle to extract \(2100 \mathrm{J}\) of heat per cycle from a freezer whose temperature is \(-10^{\circ} \mathrm{C}\). What is the maximum air temperature for which this condition can be met? Is this a reasonable condition to impose on the design?

Are the entropy changes of the systems in the following processes positive or negative? (a) water vapor that condenses on a cold surface; (b) gas in a container that leaks into the surrounding atmosphere; (c) an ice cube that melts in a glass of lukewarm water; (d) the lukewarm water of part (c); (e) a real heat engine performing a cycle; (f) food cooled in a refrigerator.

An ideal gas at temperature \(T\) is stored in the left half of an insulating container of volume \(V\) using a partition of negligible volume (see below). What is the entropy change per mole of the gas in each of the following cases? (a) The partition is suddenly removed and the gas quickly fills the entire container. (b) A tiny hole is punctured in the partition and after a long period, the gas reaches an equilibrium state such that there is no net flow through the hole. (c) The partition is moved very slowly and adiabatically all the way to the right wall so that the gas finally fills the entire container.

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