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Most materials expand when heated. One notable exception is water between \(0^{\circ} \mathrm{C}\) and \(4^{\circ} \mathrm{C},\) which actually decreases in volume with the increase in temperature. Which is greater for water in this temperature region, \(C_{p}\) or \(C_{V} ?\)

Short Answer

Expert verified
For water between \(0^{\circ} \mathrm{C}\) and \(4^{\circ} \mathrm{C}\), \(C_{V}\) (heat capacity at constant volume) is greater than \(C_{p}\) (heat capacity at constant pressure). This is concluded from the relation \(C_{p} - C_{V} = T \left(\frac{\partial V}{\partial T}\right)_{p}\left(\frac{\partial P}{\partial T}\right)_{V}\), and the fact that water contracts instead of expanding in this temperature range.

Step by step solution

01

Calculate volume change with temperature

Please note that we will assume thermal expansion in the case of water between \(0^{\circ} \mathrm{C}\) and \(4^{\circ} \mathrm{C}\) behaves oppositely. In this case, we can say that the partial derivative of volume with respect to temperature is negative, as given by \(\left(\frac{\partial V}{\partial T}\right)_{p} < 0\).
02

Identify pressure change against temperature

For most materials, we have a positive partial derivative of pressure with respect to temperature at a constant volume, i.e. \(\left(\frac{\partial P}{\partial T}\right)_{V} > 0\).
03

Calculate the difference between specific heat capacities at constant volume and constant pressure

To compare \(C_{p}\) and \(C_{V}\), compute the difference using the formula: \(C_{p} - C_{V} = T \left(\frac{\partial V}{\partial T}\right)_{p}\left(\frac{\partial P}{\partial T}\right)_{V}\) Since we have concluded that both \(\left(\frac{\partial V}{\partial T}\right)_{p} < 0\) (Step 1) and \(\left(\frac{\partial P}{\partial T}\right)_{V} > 0\) (Step 2), their product will be negative: \(C_{p} - C_{V} < 0\)
04

Conclusion

From the calculation in Step 3, we have \(C_{p} - C_{V} < 0\), which means that \(C_{V}\) is greater for water between \(0^{\circ} \mathrm{C}\) and \(4^{\circ} \mathrm{C}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Expansion
Thermal expansion refers to the tendency of matter to change its shape, area, and volume in response to a change in temperature. When a material is heated, its particles move more rapidly and tend to occupy a larger volume due to increased kinetic energy. This phenomenon is observed in solids, liquids, and gases and is usually quantified by the thermal expansion coefficient, specific to each material.

Different materials have different expansion coefficients, and interestingly, water behaves unusually between 0°C and 4°C—it contracts upon heating within this temperature range. This unique behavior is crucial for aquatic life in cold climates as it causes ice to float on water, forming an insulating layer that protects the aquatic ecosystem underneath. Understanding thermal expansion is not only significant for scientific purposes but also has practical implications in various engineering applications where temperature changes can affect the structural integrity of materials.
Partial Derivative
The partial derivative is a concept from calculus that describes the rate at which a function changes as one of its variables is varied while keeping the other variables constant. It's like looking at the incline of a hill from either the north or east side, ignoring the other dimension.

For instance, when analyzing the behavior of water from 0°C to 4°C, the partial derivative of volume with respect to temperature, represented as \(\left(\frac{\partial V}{\partial T}\right)_{p}\), is considered. If we keep the pressure constant (that’s what the 'p' indicates), this derivative tells us how the volume is expected to change solely due to temperature changes. Partial derivatives play an essential role in thermodynamics and other fields of physics and engineering because they help describe complex systems with multiple variables.
Temperature-Volume Relationship
The temperature-volume relationship is an aspect of the broader field of thermal physics, which specifically looks at how the volume of a material changes in response to changes in temperature, holding other factors like pressure constant. It is governed by Charles's law in the gas phase, which states that volume and temperature are directly proportional to each other under constant pressure conditions.

However, water's behavior between 0°C and 4°C deviates from this simple relationship. Instead of expanding with heat, it contracts, which is reflected by a negative value when we calculate the partial derivative of volume with respect to temperature at constant pressure. This anomaly is essential in understanding the peculiar properties of water and affects various fields such as climatology, oceanography, and even the functioning of household appliances.
Pressure-Temperature Relationship
The pressure-temperature relationship, often represented as Gay-Lussac’s law in the context of ideal gases, illustrates how a gas's pressure tends to increase as its temperature increases, provided the volume is held constant. This relationship is expressed with the partial derivative of pressure with respect to temperature at constant volume \(\left(\frac{\partial P}{\partial T}\right)_{V}\). It is a fundamental concept for understanding how energy transfers occur and affect the state of matter.

In most cases, this partial derivative is positive because as the temperature rises, the particles within the substance move more energetically, colliding more frequently and vigorously against container walls, which translates into higher pressure. Nevertheless, every material has its specific idiosyncrasies, making the study of these relationships crucial for designing systems that can withstand thermal stresses, such as pressurized containers, heating systems, and engines.

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Most popular questions from this chapter

A monatomic ideal gas undergoes a quasi-static process that is described by the function \(p(V)=p_{1}+3\left(V-V_{1}\right),\) where the starting state is \(\left(p_{1}, V_{1}\right)\) and the final state \(\left(p_{2}, V_{2}\right) .\) Assume the system consists of \(\mathrm{n}\) moles of the gas in a container that can exchange heat with the environment and whose volume can change freely. (a) Evaluate the work done by the gas during the change in the state. (b) Find the change in internal energy of the gas. (c) Find the heat input to the gas during the change. (d) What are initial and final temperatures?

Consider a transformation from point \(A\) to \(B\) in a two-step process. First, the pressure is lowered from 3 MPa at point \(A\) to a pressure of \(1 \mathrm{MPa}\), while keeping the volume at 2 L by cooling the system. The state reached is labeled C. Then the system is heated at a constant pressure to reach a volume of \(6 \mathrm{L}\) in the state \(B\). (a) Find the amount of work done on the \(A C B\) path. (b) Find the amount of heat exchanged by the system when it goes from \(A\) to \(B\) on the \(A C B\) path. (c) Compare the change in the internal energy when the \(A B\) process occurs adiabatically with the AB change through the two-step process on the \(A C B\) path.

An ideal gas expands quasi-statically and isothermally from a state with pressure \(p\) and volume \(V\) to a state with volume \(4 \mathrm{V}\). Show that the work done by the gas in the expansion is \(\mathrm{pV}(\ln 4)\).

It is unlikely that a process can be isothermal unless it is a very slow process. Explain why. Is the same true for isobaric and isochoric processes? Explain your answer.

Why does a bicycle pump feel warm as you inflate your tire?

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