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(a) How much heat must be added to raise the temperature of 1.5 mol of air from \(25.0^{\circ} \mathrm{C}\) to \(33.0^{\circ} \mathrm{C}\) at constant volume? Assume air is completely diatomic. (b) Repeat the problem for the same number of moles of xenon, Xe.

Short Answer

Expert verified
(a) The heat required to raise the temperature of 1.5 mol of diatomic air from 25°C to 33°C is \( 249.39 \, J \). (b) The heat required to raise the temperature of 1.5 mol of xenon from 25°C to 33°C is \( 149.64 \, J \).

Step by step solution

01

Determine the specific heat capacity of diatomic air and xenon

For diatomic air, we use the specific heat capacity at constant volume (Cv) formula for diatomic gas: \( Cv = \frac{5}{2} R \), where R is the universal gas constant, R = 8.314 J/molK. For xenon, which is a monoatomic gas, we use the specific heat capacity at constant volume (Cv) formula for monoatomic gas: \( Cv = \frac{3}{2} R \).
02

Calculate the heat required for diatomic air

Using the heat capacity formula \( q = mcΔT \), where m is the number of moles (1.5 mol), c is the specific heat capacity and ΔT is the change in temperature (33 - 25 = 8°C or 8K), we can find the heat required to raise the temperature of diatomic air: \( q_{air} = (1.5 \, mol) \times \left(\frac{5}{2} \times 8.314 \, \frac{J}{mol \cdot K}\right) \times (8 \, K) \) Calculate the value of \(q_{air}\): \( q_{air} = 1.5 \times 20.785 \times 8 \) \( q_{air} = 249.39 \, J \)
03

Calculate the heat required for xenon

Now, we can find the heat required to raise the temperature of xenon using the same heat capacity formula: \( q_{Xe} = (1.5 \, mol) \times \left(\frac{3}{2} \times 8.314 \, \frac{J}{mol \cdot K}\right) \times (8 \, K) \) Calculate the value of \(q_{Xe}\): \( q_{Xe} = 1.5 \times 12.471 \times 8 \) \( q_{Xe} = 149.64 \, J \) (a) The heat required to raise the temperature of 1.5 mol of diatomic air from 25°C to 33°C is 249.39 J. (b) The heat required to raise the temperature of 1.5 mol of xenon from 25°C to 33°C is 149.64 J.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Heat Capacity
Understanding how much energy is required to change the temperature of a substance is key in thermodynamics. Specific heat capacity is the quantity of heat required to change the temperature of one mole of a substance by one degree Kelvin. Each substance has its own specific heat capacity, influenced by its structure and bonding.
The heat capacity at constant volume for a substance is denoted as \( C_v \). The formula \( q = mc\Delta T \) allows us to calculate the energy needed to change temperature, where \( q \) is the heat added, \( m \) is the number of moles, \( c \) is the specific heat capacity, and \( \Delta T \) is the change in temperature.
In our exercise, this formula helps calculate the energy for both diatomic air and xenon, illustrating differences based on their molecular nature.
Diatomic Gas
Diatomic gases, like oxygen and nitrogen in air, consist of two atoms per molecule. These gases exhibit specific heat capacities that differ from monoatomic gases.
Under constant volume conditions, the specific heat capacity \( C_v \) for a diatomic gas is given by \( C_v = \frac{5}{2} R \). This accounts for both translational and rotational movements of the molecules. Diatomic gases have more degrees of freedom compared to monoatomic gases, allowing them to store more heat energy, hence a larger \( C_v \).
In our calculation, we used this value for air, considering it as a diatomic gas, to determine that 249.39 Joules of heat is needed to increase its temperature.
Monoatomic Gas
Monoatomic gases, like xenon, are composed of single atoms. These gases have a simplified structure, influencing their specific heat capacity.
The heat capacity at constant volume for a monoatomic gas is \( C_v = \frac{3}{2} R \). This lower value arises due to fewer degrees of freedom; monoatomic gases only possess translational motion as opposed to rotational or vibrational.
For xenon, this principle demonstrated why it requires less energy—149.64 Joules—to achieve the same temperature increase as diatomic air, reflecting its simpler atomic nature.
Universal Gas Constant
The universal gas constant \( R \) is a crucial element in thermodynamic equations. It represents the molar energy scale for gases and connects the microscopic world of molecules to macroscopic properties like volume and pressure. In energy units, \( R \) is valued at 8.314 Joules per mole per Kelvin.
This constant is integrated into various gas equations, including those for specific heat calculations \( C_v = \frac{f}{2} R \), where \( f \) is the degrees of freedom.
By using \( R \) in our heat calculations, we ensure accuracy when determining how much energy is needed to change the temperature of different gases. The uniformity offered by \( R \) allows us to compare different gas behaviors under similar conditions.

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Most popular questions from this chapter

The escape velocity from the Moon is much smaller than that from the Earth, only \(2.38 \mathrm{km} / \mathrm{s}\). At what temperature would hydrogen molecules (molar mass is equal to \(2.016 \mathrm{g} / \mathrm{mol}\) ) have a root-mean-square velocity \(v_{\mathrm{rms}}\) equal to the Moon's escape velocity?

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Heliox, a mixture of helium and oxygen, is sometimes given to hospital patients who have trouble breathing, because the low mass of helium makes it easier to breathe than air. Suppose helium at \(25^{\circ} \mathrm{C}\) is mixed with oxygen at \(35^{\circ} \mathrm{C}\) to make a mixture that is \(70 \%\) helium by mole. What is the final temperature? Ignore any heat flow to or from the surroundings, and assume the final volume is the sum of the initial volumes.

(a) Use the ideal gas equation to estimate the temperature at which \(1.00 \mathrm{kg}\) of steam (molar mass \(M=18.0 \mathrm{g} / \mathrm{mol})\) at a pressure of \(1.50 \times 10^{6} \mathrm{Pa}\) occupies a volume of \(0.220 \mathrm{m}^{3} .\) (b) The van der Waals constants for water are \(a=0.5537 \mathrm{Pa} \cdot \mathrm{m}^{6} / \mathrm{mol}^{2}\) and \(b=3.049 \times 10^{-5} \mathrm{m}^{3} / \mathrm{mol} .\) Use the Van der Waals equation of state to estimate the temperature under the same conditions. (c) The actual temperature is 779 K. Which estimate is better?

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