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What is the gauge pressure inside a tank of the \(4.86 \times 10^{4}\) mol of compressed nitrogen with a volume of \(6.56 \mathrm{m}^{3}\) if the rms speed is \(514 \mathrm{m} / \mathrm{s} ?\)

Short Answer

Expert verified
The gauge pressure inside the tank of compressed nitrogen is approximately \(5.67 \times 10^6\, Pa\).

Step by step solution

01

Write down the Ideal Gas Law equation and convert volume to liters

The Ideal Gas Law is given by the equation: \(PV = nRT\), where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. First, we need to convert the volume from \(m^3\) to liters (1 \(m^3\) = 1000 L) for easier calculations. V (in L) = \(6.56m^3 × 1000 L/m^3\) = 6560 L
02

Write down the RMS speed equation and find the temperature

The RMS speed equation is defined as \(\bar{v} = \sqrt{\frac{3RT}{M}}\), where \(\bar{v}\) is the RMS speed, R is the ideal gas constant, T is the temperature, and M is the molar mass. We know that nitrogen gas (Nâ‚‚) has a molar mass M = 28.02 g/mol, and the given RMS speed is 514 m/s. Rearranging the RMS speed equation to find T, we get: \(T = \frac{M \cdot \bar{v}^2}{3R}\) Plugging in the values for M, \(\bar{v}\), and R, we can calculate the temperature: \(T = \frac{28.02 g/mol \cdot (514 m/s)^2}{3 * 8.314 m^2 kg s^{-2} K^{-1}mol^{-1}}\)
03

Calculate the temperature

Now, we can calculate the temperature: \(T = \frac{28.02 g/mol \cdot (514 m/s)^2}{3 * 8.314 m^2 kg s^{-2} K^{-1}mol^{-1}} = 95541.10 K\)
04

Plug temperature into the Ideal Gas Law and solve for pressure

Now that we have the temperature, we can plug it into the Ideal Gas Law equation to find the pressure: \(PV = nRT\) \(P = \frac{nRT}{V}\) Plugging in the values, we get: \(P = \frac{4.86 \times 10^{4}\, mol \cdot 8.314 m^2 kg s^{-2} K^{-1}mol^{-1} \cdot 95541.10 K}{6.56 \times 10^3 L}\)
05

Calculate the pressure and convert it to gauge pressure

Now, we can calculate the absolute pressure in pascals (Pa): \(P = 5.77 \times 10^6\, Pa\) Gauge pressure is the pressure relative to atmospheric pressure. We can calculate the gauge pressure by subtracting the atmospheric pressure (assumed to be 101325 Pa) from the absolute pressure: Gauge pressure = Absolute pressure - Atmospheric pressure Gauge pressure = \(5.77 \times 10^6\, Pa - 101325\, Pa = 5.67 \times 10^6\, Pa\) The gauge pressure inside the tank of compressed nitrogen is approximately \(5.67 \times 10^6\, Pa\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Gauge Pressure
Gauge pressure is a critical concept in understanding how gases behave in confined spaces, such as tanks. It represents the pressure of a gas or liquid that is above and beyond the ambient atmospheric pressure, which at sea level is typically 101,325 Pascals (Pa), or 1 atmosphere (atm). In other words, it's the extra pressure exerted by a gas confined in a space.

When dealing with gauge pressure, one must first calculate the absolute pressure using the Ideal Gas Law, which relates pressure, volume, temperature, and the amount of gas present. After finding the absolute pressure, the atmospheric pressure is subtracted to find the gauge pressure. This differentiation is crucial in many practical applications, including tire pressure measurements and pressurized tanks, where safety depends on correct pressure readings.
The RMS Speed Equation and Its Significance
The Root Mean Square (RMS) speed equation is vital in thermodynamics and gas theory, offering insight into the energy and speed of gas molecules.

How to Calculate the RMS Speed

The RMS speed equation is defined as \(\bar{v} = \sqrt{\frac{3RT}{M}}\), where \( \bar{v} \) stands for the RMS speed, \( R \) is the ideal gas constant, \( T \) is the temperature in Kelvin, and \( M \) represents the molar mass of the gas in kilograms per mole (kg/mol).

This equation allows us to understand the molecular movement within a gas. Given the RMS speed, one can back-calculate to find the temperature of the gas, assuming the molar mass and the gas constant are known. High RMS speeds correlate with higher temperatures and vice versa, playing a fundamental role in temperature kinetics.
Molar Mass in Gas Calculations
Molar mass is the mass of one mole of a substance, commonly expressed in grams per mole (g/mol). For gases, the molar mass becomes a cornerstone in computations, particularly when applying the Ideal Gas Law or determining RMS speed.

In the context of the RMS speed equation, knowing the molar mass of the gas in question permits us to calculate the average speed of molecules within a sample at a certain temperature. Molar mass impacts the speed at which gas particles move; heavier particles (with greater molar mass) will generally move slower than lighter particles given the same amount of thermal energy.
Temperature Calculation from Kinetic Theory
Temperature plays an integral role in determining the behavior of gases, and it is intimately connected with pressure through the Ideal Gas Law.

Deciphering Temperature Through Speed

When the RMS speed is known, temperature can be calculated using the rearranged RMS speed equation. This method is rooted in kinetic theory, which correlates the motion of particles with the thermal energy in a system.

The equation \(T = \frac{M \cdot \bar{v}^2}{3R}\) allows us to deduce the temperature of a gas when we know its RMS speed and molar mass—essentially translating kinetic energy of molecules into temperature. This temperature must then be plugged back into the Ideal Gas Law to complete the calculation for other unknowns like pressure.

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Most popular questions from this chapter

People buying food in sealed bags at high elevations often notice that the bags are puffed up because the air inside has expanded. A bag of pretzels was packed at a pressure of 1.00 atm and a temperature of \(22.0^{\circ} \mathrm{C}\). When opened at a summer picnic in Santa Fe, New Mexico, at a temperature of \(32.0^{\circ} \mathrm{C},\) the volume of the air in the bag is 1.38 times its original volume. What is the pressure of the air?

Under what circumstances would you expect a gas to behave significantly differently than predicted by the ideal gas law?

(a) What is the gauge pressure in a \(25.0^{\circ} \mathrm{C}\) car tire containing 3.60 mol of gas in a 30.0 -L volume? (b) What will its gauge pressure be if you add 1.00 L of gas originally at atmospheric pressure and \(25.0^{\circ} \mathrm{C}\) ? Assume the temperature remains at \(25.0^{\circ} \mathrm{C}\) and the volume remains constant.

Eight bumper cars, each with a mass of \(322 \mathrm{kg}\), are running in a room \(21.0 \mathrm{m}\) long and \(13.0 \mathrm{m}\) wide. They have no drivers, so they just bounce around on their own. The ms speed of the cars is \(2.50 \mathrm{m} / \mathrm{s}\). Repeating the arguments of Pressure, Temperature, and RMS Speed, find the average force per unit length (analogous to pressure) that the cars exert on the walls.

The gauge pressure in your car tires is 18. The gase \(2.50 \times 10^{5} \mathrm{N} / \mathrm{m}^{2}\) at a temperature of \(35.0^{\circ} \mathrm{C}\) when you drive it onto a ship in Los Angeles to be sent to Alaska. What is their gauge pressure on a night in Alaska when their temperature has dropped to \(-40.0^{\circ} \mathrm{C}\) ? Assume the tires have not gained or lost any air. 18. The gauge pressure in your car tires is 18. The gase \(2.50 \times 10^{5} \mathrm{N} / \mathrm{m}^{2}\) at a temperature of \(35.0^{\circ} \mathrm{C}\) when you drive it onto a ship in Los Angeles to be sent to Alaska. What is their gauge pressure on a night in Alaska when their temperature has dropped to \(-40.0^{\circ} \mathrm{C}\) ? Assume the tires have not gained or lost any air.

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