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Find the number of moles in \(2.00 \mathrm{L}\) of gas at \(35.0^{\circ} \mathrm{C}\) and under \(7.41 \times 10^{7} \mathrm{N} / \mathrm{m}^{2}\) of pressure.

Short Answer

Expert verified
The number of moles in \(2.00\, \mathrm{L}\) of gas at \(35.0^{\circ}\mathrm{C}\) and under \(7.41 \times 10^{7}\, \mathrm{N/m^{2}}\) of pressure is approximately \(59.80\) moles.

Step by step solution

01

Convert the temperature to Kelvin

Since the formula for the Ideal Gas Law requires the temperature in Kelvin, we need to convert the given temperature from Celsius to Kelvin. To do this, we simply add 273.15 to the given temperature in Celsius: \(T_{K} = T_{C} + 273.15\) \(T_{K} = 35.0 + 273.15 = 308.15\,K\) The temperature in Kelvin is 308.15 K.
02

Convert the volume to cubic meters

The pressure is given in N/m² which is equal to Pascals. The formula for Ideal Gas Law uses SI units, so we need the same kind of value for the volume. We will convert the given volume from L to m³. Use the following conversion factor: \(1\, \mathrm{L} = 0.001\, \mathrm{m}^{3}\). \(V_{m3} = V_{L} × 0.001\) \(V_{m3} = 2.00 × 0.001 = 0.002\, \mathrm{m}^{3}\) The volume in cubic meters is 0.002 m³.
03

Rearrange the Ideal Gas Law equation to solve for n

We will rearrange the Ideal Gas Law formula to solve for \(n\): \(PV = nRT\) \(\frac{PV}{RT} = n\)
04

Plug in the values and calculate the number of moles

Now that we have the equation rearranged and the values converted to SI units, we can plug in the values and solve for \(n\): \(n = \frac{PV}{RT}\) \(n = \frac{(7.41 \times 10^{7}\, \mathrm{Pa})(0.002\, \mathrm{m^{3}})}{(8.314\, \mathrm{J/mol \cdot K})(308.15\, \mathrm{K})}\) \(n \approx 59.80\, \mathrm{moles}\) The number of moles in 2.00 L of gas at 35.0°C and under 7.41 × 10^7 N/m² of pressure is approximately 59.80 moles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molarity
Molarity is a way of expressing the concentration of a solution. It is calculated as the number of moles of solute per liter of solution. While in this exercise we are working with gases instead of solutions, the concept of molarity still helps us understand the amount of substance present.
For example, to calculate the molarity of a solution, you can use the formula:
  • \( M = \frac{n}{V} \)
Where \( M \) is molarity, \( n \) is the number of moles, and \( V \) is the volume of the solution in liters.
This concept, although not directly used in gas calculations, helps in visualizing the concentration of substances in various contexts.
Gas Laws
Gas laws are vital in understanding the behavior of gases under various conditions. The Ideal Gas Law is a central equation combining several gas laws into one. It is expressed as:
  • \( PV = nRT \)
This formula links pressure \( P \), volume \( V \), and temperature \( T \) to the number of moles \( n \), with \( R \) being the ideal gas constant.
The Ideal Gas Law assumes no interactions between gas molecules and that they occupy no volume, which simplifies calculations for many practical purposes. Understanding how variables like pressure and temperature influence gas volume through this law is essential in thermodynamics and other scientific fields.
Thermodynamics
Thermodynamics is the study of energy and its transformations. It helps us understand how energy is transferred between systems and its impact on matter. The Ideal Gas Law stems from thermodynamic principles, specifically under the assumption that the gas involved behaves ideally.
Within thermodynamics, temperature plays an essential role, affecting how energy is distributed among gas molecules. The gas laws, such as Boyle's and Charles's laws, which are components of the Ideal Gas Law, describe how gases respond to changes in temperature and pressure.
Thermodynamics not only helps predict how gases will behave but also forms the foundation for many other scientific concepts, emphasizing the importance of mastering this field.
SI Units
SI units, or the International System of Units, provide a standardized approach for scientific measurements. They are crucial for ensuring consistency and comparability across different experiments and industries. In gas law calculations, using SI units ensures that every part of the equation aligns properly.
  • For pressure, the SI unit is pascal (Pa).
  • For volume, it's cubic meters (m³).
  • Temperature must be in Kelvin (K), a unit based on the absolute thermodynamic scale.
This standardization is vital, as it removes ambiguity and allows for accurate scientific communication and computation across various disciplines.
Temperature Conversion
Temperature conversion is crucial in gas law problems because equations like the Ideal Gas Law require temperature in Kelvin. The Kelvin scale begins at absolute zero, unlike the Celsius scale, which is centered around the freezing point of water.
To convert Celsius to Kelvin, use the formula:
  • \( T_{K} = T_{C} + 273.15 \)
This conversion ensures that the calculations are in line with the requirements of thermodynamic equations, helping achieve accurate and meaningful results. Understanding this conversion is key in all areas of science that deal with temperature-dependent processes.

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Most popular questions from this chapter

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