/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 Radio station WWVB, operated by ... [FREE SOLUTION] | 91Ó°ÊÓ

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Radio station WWVB, operated by the National Institute of Standards and Technology (NIST) from Fort Collins, Colorado, at a low frequency of \(60 \mathrm{kHz}\), broadcasts a time synchronization signal whose range covers the entire continental US. The timing of the synchronization signal is controlled by a set of atomic clocks to an accuracy of \(1 \times 10^{-12} \mathrm{s}, \quad\) and repeats every 1 minute. The signal is used for devices, such as radio-controlled watches, that automatically synchronize with it at preset local times. WWVB's long wavelength signal tends to propagate close to the ground. (a) Calculate the wavelength of the radio waves from WWVB. (b) Estimate the error that the travel time of the signal causes in synchronizing a radio controlled watch in Norfolk, Virginia, which is 1570 mi ( \(2527 \mathrm{km}\) ) from Fort Collins, Colorado.

Short Answer

Expert verified
The wavelength of the radio waves from WWVB is \(5000 \mathrm{m}\), and the error caused by the travel time of the signal for a radio-controlled watch in Norfolk, Virginia is approximately \(0.008423 \mathrm{s}\).

Step by step solution

01

(a) Calculate the wavelength

We can find the wavelength of the radio waves (\(\lambda\)) using the formula \(c = f \lambda\), where \(c\) is the speed of light (approximately \(3 \times 10^8 \mathrm{m/s}\)) and \(f\) is the frequency of the radio waves. In our case, the frequency of the radio waves, \(f\), is \(60 \mathrm{kHz}\), which equals \(60 \times 10^3 \mathrm{Hz}\). To find the wavelength (\(\lambda\)), we rearrange the formula and plug in the given values: \[\lambda = \frac{c}{f} = \frac{3 \times 10^8 \mathrm{m/s}}{60 \times 10^3 \mathrm{Hz}}\]
02

(a.1) Calculate the value of the wavelength

Now we can calculate the value of the wavelength: \[\lambda = \frac{3 \times 10^8 \mathrm{m}}{60 \times 10^3} = 5 \times 10^3 \mathrm{m}\] So, the wavelength of the radio waves from WWVB is \(5000 \mathrm{m}\).
03

(b) Estimate the error caused by the travel time of the signal

To estimate the error caused by the travel time of the signal, we first need to determine the travel time of the signal. We can do this using the formula \(t = \frac{d}{c}\), where \(t\) is the travel time, \(d\) is the distance between the radio station and the watch, and \(c\) is the speed of light. In our case, the distance (\(d\)) is \(2527 \mathrm{km}\), which equals \(2527 \times 10^3 \mathrm{m}\). We will use the speed of light (\(c\)) as \(3 \times 10^8 \mathrm{m/s}\).
04

(b.1) Calculate the travel time of the signal

Now we can calculate the travel time of the signal: \[t = \frac{d}{c} = \frac{2527 \times 10^3 \mathrm{m}}{3 \times 10^8 \mathrm{m/s}}\]
05

(b.2) Find the value of the travel time of the signal

Let's find the value of the travel time of the signal: \[t \approx 8.423 \times 10^{-3} \mathrm{s}\] Now we know that the travel time of the signal is approximately \(0.008423 \mathrm{s}\).
06

(b.3) Compare the travel time with the accuracy of the atomic clocks and find the error

To find the error caused by the travel time of the signal, we need to compare the travel time with the accuracy of the atomic clocks, which is \(1 \times 10^{-12} \mathrm{s}\). The travel time (\(t\)) is much larger than the accuracy of the atomic clocks. The error caused by the travel time of the signal will be: \[\Delta t = t - (1 \times 10^{-12}) = 8.423 \times 10^{-3} \mathrm{s} - (1 \times 10^{-12}) \mathrm{s}\] The error caused by the travel time is approximately \(0.008423 \mathrm{s}\). In conclusion, the wavelength of the radio waves from WWVB is \(5000 \mathrm{m}\), and the error caused by the travel time of the signal for a radio-controlled watch in Norfolk, Virginia is approximately \(0.008423 \mathrm{s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radio Waves
Radio waves are a type of electromagnetic radiation. They are used to transmit signals over long distances. These waves are invisible and travel at the speed of light. A key characteristic of radio waves is their frequency, which determines their wavelength. Frequency is measured in Hertz (Hz), and it indicates how many cycles per second the wave completes.

In the context of the WWVB radio station, the radio waves have a frequency of 60 kHz, which translates to 60,000 cycles per second. By using the formula for wave speed, represented as \(c = f \lambda\), where \(c\) is the speed of light and \(\lambda\) is the wavelength, we can calculate that the wavelength of these radio waves is 5000 meters. This long wavelength helps the signal travel efficiently over vast distances across the continental United States.
Speed of Light
The speed of light is a constant and fundamental property of our universe. Light travels at approximately 300,000 kilometers per second (or \(3 \times 10^8\) meters per second) in a vacuum. This incredible speed allows for the near-instantaneous transmission of information across great distances, such as in radio communications.

When calculating the travel time of a signal, such as those broadcasted by the WWVB station, the speed of light plays a crucial role. For instance, a signal traveling from Fort Collins, Colorado to Norfolk, Virginia needs time to travel the 2527 kilometers. By using the formula \(t = \frac{d}{c}\), where \(t\) is the time, \(d\) is the distance, and \(c\) is the speed of light, we find that it takes approximately 0.008423 seconds for the signal to reach its destination.
Atomic Clocks
Atomic clocks are highly accurate timekeeping devices. They use the vibrations of atoms, typically cesium or rubidium, to measure time. The precision of an atomic clock is unmatched, reaching accuracies within a few billionths of a second. This remarkable accuracy is vital for time synchronization tasks.

The WWVB signal, controlled by atomic clocks, allows devices such as watches to synchronize with precise universal time. The accuracy of this synchronization is influenced by the precision of the atomic clock. In WWVB's case, the atomic clocks provide a synchronization accuracy of \(1 \times 10^{-12}\) seconds. This level of precision ensures that any time errors due to signal travel are minimized, although the actual travel time still introduces delay.
Signal Propagation
Signal propagation refers to how radio waves travel from one point to another. Different frequencies of radio waves can propagate in various ways. For the WWVB station, the low frequency of 60 kHz means that its radio waves have a long wavelength. This characteristic enables the waves to follow the curvature of the Earth, making them effective for long-distance ground propagation.

The efficiency of signal propagation is crucial for ensuring that the time synchronization signals can reach various locations with minimal loss. However, the travel time of the signal introduces errors, especially over large distances, as illustrated by the 0.008423 seconds delay from Fort Collins to Norfolk. Understanding signal propagation helps in designing systems that compensate for these delays, ensuring accurate synchronization. By combining the properties of radio waves with scientific principles, the WWVB signal remains a reliable source of accurate time information.

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