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Show that the SI unit for capacitive reactance is the ohm. Show that the SI unit for inductive reactance is also the ohm.

Short Answer

Expert verified
In conclusion, the SI unit for capacitive reactance (X_C) is derived from the formula \(X_C = \frac{1}{2\pi fC}\), resulting in the unit of ohm (\(\Omega\)). Similarly, the SI unit for inductive reactance (X_L) is derived from the formula \(X_L = 2\pi fL\), also resulting in the unit of ohm (\(\Omega\)). Hence, the SI units for both capacitive and inductive reactance are ohms.

Step by step solution

01

Derive the formula for capacitive reactance

Capacitive reactance (X_C) is the opposition that a capacitor offers to alternating current (AC) and is defined by the following formula: \[ X_C = \frac{1}{2\pi fC} \] Where: - X_C is the capacitive reactance - f is the frequency in hertz (Hz) - C is the capacitance in farads (F)
02

Find the units of capacitive reactance

To find the units of capacitive reactance, plug in the units for frequency and capacitance into the formula: \[ \frac{1}{\textit{(Hz)} \cdot \textit{(F)}} \] Now, express the units in terms of base SI units, i.e. hertz in terms of seconds (s), and farads in terms of coulombs (C) and volts (V): \[ \frac{1}{\frac{\textit{(s)}}{\textit{(s)}} \cdot \frac{\textit{(C)}}{\textit{(V)}}} = \frac{\textit{(V)}}{\textit{(C)}} \] Since the ratio of volt per coulomb is the definition of ohm (\(\Omega\)), the SI unit for capacitive reactance is the ohm: \[ X_C = \Omega \]
03

Derive the formula for inductive reactance

Inductive reactance (X_L) is the opposition that an inductor offers to alternating current (AC) and is defined by the following formula: \[ X_L = 2\pi fL \] Where: - X_L is the inductive reactance - f is the frequency in hertz (Hz) - L is the inductance in henrys (H)
04

Find the units of inductive reactance

To find the units of inductive reactance, we'll plug in the units for frequency and inductance into the formula: \[ (\textit{(Hz)}) \cdot \textit{(H)} \] Express the units in terms of base SI units, i.e. hertz in terms of seconds (s), and henrys in terms of webers (Wb), amperes (A), and seconds (s): \[ \frac{\textit{(s)}}{\textit{(s)}} \cdot \frac{\textit{(Wb) s}}{\textit{(A)}} = \frac{\textit{(Wb A)}}{\textit{(A)}} \] Webers per ampere is the definition of volt (V), so the SI unit of inductive reactance is also the ohm: \[ X_L = \Omega \] In conclusion, we have shown that the SI unit for both capacitive reactance and inductive reactance is the ohm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Capacitive Reactance
The capacitive reactance is a critical concept in understanding how capacitors behave in alternating current (AC) circuits. It represents the opposition a capacitor presents to the flow of AC, differing from the resistor's opposition in a direct current (DC) circuit. This opposition is not via energy dissipation like resistance but through energy storage and release.
To calculate the capacitive reactance (\( X_C \)), we use the formula:
  • \( X_C = \frac{1}{2\pi fC} \)
The variable \( f \) stands for the frequency of the AC in hertz (Hz), and \( C \) represents the capacitance in farads (F).
This formula shows that the reactance inversely relates to both frequency and capacitance. As the frequency increases, the reactance decreases, explaining why capacitors tend to "smooth out" rapid voltage changes by allowing increasing current flow at high frequencies. Understanding this provides a stepping stone to learning about filtering applications used in electronic circuits.
Inductive Reactance
Inductive reactance emerges when indoctroids are introduced into an AC circuit. Inductors, like capacitors, store energy. However, they store it in magnetic fields rather than electric fields. As the current fluctuates, inductors resist these changes by generating a voltage that opposes the change.
The formula for inductive reactance (\( X_L \)) is given by:
  • \( X_L = 2\pi fL \)
In this expression, \( L \) refers to the inductance measured in henrys (H), and \( f \) is the frequency in hertz (Hz).
This relationship implies that as the frequency increases, the inductive reactance also increases. Inductors effectively "block" high-frequency signals while allowing low-frequency signals to pass more easily. This principle aids in signal filtering and tuning applications.
SI Units in Electrical Engineering
SI units provide a globally consistent framework for understanding and applying electrical engineering concepts. The International System of Units ensures consistency and accuracy, essential in scientific investigations and engineering designs.
Key components in this framework include:
  • Frequency (Hertz, Hz): Describes how often the current alternates per second.
  • Capacitance (Farad, F): Measures a capacitor's ability to store charge.
  • Inductance (Henry, H): Indicates an inductor's ability to store energy in a magnetic field.
  • Voltage (Volt, V): The electrical potential difference or "pressure" that pushes the current.
  • Current (Ampere, A): The rate of charge flow in the electrical circuit.
Grasping these units enables engineers and students alike to ensure precise calculations and better communication within the professional community.
Alternating Current (AC)
Alternating Current, or AC, refers to the flow of electric charge that periodically reverses direction. This is unlike Direct Current (DC), which flows in only one direction. AC is the standard form of power supplied to homes and businesses across the globe.
One of the most significant characteristics of AC is its ability to easily transform voltage levels through devices like transformers. This ensures efficient long-distance power transmission by minimizing energy loss. Here are key elements:
  • AC frequency is measured in hertz (Hz), typically either 50 Hz or 60 Hz depending on the country.
  • The sinusoidal waveform characterizes AC, indicating smooth periodic oscillations.
Understanding AC is crucial, as it underpins the design and operation of numerous electronic devices and systems used in daily life.
Ohm as a Unit of Measure
The ohm (\(\Omega\)) is the unit of electrical resistance and is named after Georg Simon Ohm, a German physicist. In both capacitive and inductive reactance, the ohm is the equivalent opposing force to AC within the circuit.
Resistance itself is a direct measure of how difficult it is for current to pass through a conductor. Reactance, however, is related to that opposition but specifically in AC circuits involving capacitive or inductive components. Both reactance and resistance play vital roles in circuit behavior.This measurement unit simplifies complex circuit analysis and supports instruction about:
  • Ohm's Law: \( V = IR \), demonstrating the relationship between voltage, current, and resistance.
  • Power calculations: \( P = I^2R \), helping to evaluate power dissipation in circuits.
Clearly grasping the role of the ohm promotes a stronger understanding of how different components affect total impedance and functionality in electrical circuits.

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Most popular questions from this chapter

A transformer is used to supply a 12 -V model train with power from a 110 -V wall plug. The train operates at 50 W of power. (a) What is the rms current in the secondary coil of the transformer? (b) What is the rms current in the primary coil? (c) What is the ratio of the number of primary to secondary turns? (d) What is the resistance of the train? (e) What is the resistance seen by the 110 -V source?

The emf of an ac source is given by \(v(t)=V_{0} \sin \omega t, \quad\) where \(\quad V_{0}=100 \mathrm{V} \quad\) and \(\omega=200 \pi \mathrm{rad} / \mathrm{s} . \quad\) Find an expression that represents the output current of the source if it is connected across (a) a \(20-\mu \mathrm{F}\) capacitor, (b) a \(20-\mathrm{mH}\) inductor, and \((\mathrm{c})\) a \(50-\Omega\) resistor.

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The 335-kV ac electricity from a power transmission line is fed into the primary winding of a transformer. The ratio of the number of turns in the secondary winding to the number in the primary winding is \(N_{\mathrm{s}} / N_{\mathrm{p}}=1000.\) (a) What voltage is induced in the secondary winding? (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?

A 7.0-mH inductor is connected across a 60-Hz ac source whose voltage amplitude is \(50 \mathrm{V}\). (a) What is the maximum current through the inductor? (b) What is the phase relationship between the current through and the potential difference across the inductor?

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