/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 At \(1000 \mathrm{Hz}\), the rea... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

At \(1000 \mathrm{Hz}\), the reactance of a \(5.0-\mathrm{mH}\) inductor is equal to the reactance of a particular capacitor. What is the capacitance of the capacitor?

Short Answer

Expert verified
The capacitance of the capacitor is approximately \(1.59 × 10^{-8} F\).

Step by step solution

01

Write down the reactance formulas

For an inductor, the reactance (X_L) is given by the formula: \[X_L = 2\pi fL\] where \(f\) is the frequency, and \(L\) is the inductance. For a capacitor, the reactance (X_C) is given by the formula: \[X_C = \frac{1}{2\pi fC}\] where \(f\) is the frequency, and \(C\) is the capacitance. Since the problem states that the reactances are equal at 1000 Hz, we can set the two formulas equal to each other and solve for capacitance: \[2\pi fL = \frac{1}{2\pi fC}\]
02

Plug in known values

Now, plug in the given values for frequency (1000 Hz) and inductance (5.0 mH) into the formula: \[2\pi (1000)(0.005) = \frac{1}{2\pi (1000)C}\]
03

Solve for capacitance

Solve the equation for \(C\): \(2\pi (1000)(0.005) = \frac{1}{2\pi (1000)C}\) \[(2\pi (1000)(0.005))(2\pi (1000)C) = 1\] \[(2\pi)^2 (1000)^2 (0.005)C = 1\] Now, divide both sides by \((2\pi)^2 (1000)^2 (0.005)\) to isolate the capacitance \(C\): \[C = \frac{1}{(2\pi)^2 (1000)^2 (0.005)}\]
04

Calculate the capacitance

Now, use a calculator to find the value of \(C\): \[C ≈ 1.59 × 10^{-8} F\] The capacitance of the capacitor is approximately \(1.59 × 10^{-8} F\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inductance
Inductance is an essential concept in electronics that signifies the property of an electrical circuit, especially a coil or inductor, to oppose a change in current. It is measured in henries (H) and reflects how much electrical energy is stored in a magnetic field in response to a change in current. For an inductor, the reactance is determined by the formula:
- \(X_L = 2\pi fL\)
where:
  • \(X_L\) is the inductive reactance.
  • \(f\) is the frequency of the signal passing through the inductor.
  • \(L\) is the inductance of the coil.
Understanding inductance involves recognizing that it is all about the circuit's opposition to changes in current, thus playing a crucial role in AC circuits. The higher the frequency or the higher the inductance, the greater the reactance. This concept is utilized in various applications such as transformers, inductors, and even in radio frequency circuits.
Capacitance
Capacitance is the ability of a component or circuit to store an electrical charge. It is a fundamental property of capacitors, which are devices specifically designed to hold and release energy in electrical circuits. Capacitance is measured in farads (F), and the reactance of a capacitor is calculated as:
- \(X_C = \frac{1}{2\pi fC}\)
In this formula:
  • \(X_C\) is the capacitive reactance.
  • \(f\) is the frequency of the circuit.
  • \(C\) is the capacitance.
The formula explains that the reactance of a capacitor decreases with an increase in frequency or capacitance, indicating that capacitors conduct better at higher frequencies. This is opposite to inductance, showing how capacitors can effectively filter out noise in electrical signals. They are widely used in various technologies, from electronic devices to power supply systems, for their proficiency in smoothing out voltage fluctuations in circuits.
Frequency
Frequency refers to the number of times a wave repeats itself in a second, measured in hertz (Hz). In the realm of electricity, it's the cycles per second of a waveform, such as voltage or current.
The concept of frequency is pivotal in determining the reactance of both capacitors and inductors. In this context, higher frequencies lead to greater inductive reactance but lower capacitive reactance. These alternating trends in reactance due to frequency change are crucial in electronic design. They allow designers to control how signals are processed, such as filtering certain frequencies or ensuring stability in power delivery.
  • Increased frequency results in increased inductive reactance, suggesting more opposition to current changes.
  • Decreased capacitive reactance means capacitors allow more current through at higher frequencies.
By understanding and manipulating frequency, engineers can optimize devices for different applications such as audio processing, radio transmissions, and power management.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For an \(R L C\) series circuit, \(R=100 \Omega, L=150 \mathrm{mH}\) and \(C=0.25 \mu \mathrm{F} .\) (a) If an ac source of variable frequency is connected to the circuit, at what frequency is maximum power dissipated in the resistor? (b) What is the quality factor of the circuit?

Why are the primary and secondary coils of a transformer wrapped around the same closed loop of iron?

An ac source of voltage amplitude \(100 \mathrm{V}\) and variable frequency \(f\) drives an \(R L C\) series circuit with \(R=10 \Omega\) \(L=2.0 \mathrm{mH},\) and \(C=25 \mu \mathrm{F} .\) (a) Plot the current through the resistor as a function of the frequency \(f\). (b) Use the plot to determine the resonant frequency of the circuit.

Find the reactances of the following capacitors and inductors in ac circuits with the given frequencies in each case: (a) \(2-\mathrm{m} \mathrm{H}\) inductor with a frequency \(60-\mathrm{Hz}\) of the ac circuit; (b) 2-mH inductor with a frequency 600-Hz of the ac circuit; (c) 20-mH inductor with a frequency 6-Hz of the ac circuit; (d) 20-mH inductor with a frequency 60-Hz of the ac circuit; (e) 2-mF capacitor with a frequency \(60-\mathrm{Hz}\) of the ac circuit; and (f) 2 -mF capacitor with a frequency \(600-\mathrm{Hz}\) of the AC circuit.

A transformer is used to supply a 12 -V model train with power from a 110 -V wall plug. The train operates at 50 W of power. (a) What is the rms current in the secondary coil of the transformer? (b) What is the rms current in the primary coil? (c) What is the ratio of the number of primary to secondary turns? (d) What is the resistance of the train? (e) What is the resistance seen by the 110 -V source?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.