/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 (a) Does the induced emf in a ci... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) Does the induced emf in a circuit depend on the resistance of the circuit? (b) Does the induced current depend on the resistance of the circuit?

Short Answer

Expert verified
Answer (a): No, the induced emf in a circuit does not depend on the resistance of the circuit. Answer (b): Yes, the induced current depends on the resistance of the circuit.

Step by step solution

01

Recall Faraday's Law of Electromagnetic Induction

Faraday's Law of Electromagnetic Induction states that the induced emf (\(\varepsilon\)) in a closed loop is proportional to the time rate of change of the magnetic flux (\(\Phi\)) linking the loop. Mathematically, it can be written as: \[\varepsilon=-N\frac{d\Phi}{dt}\] Where, \(N\) = number of turns in the loop, \(\Phi\) = magnetic flux, \(\varepsilon\) = induced emf, and \(\frac{d\Phi}{dt}\) = the rate of change of magnetic flux.
02

Recall Ohm's Law

Ohm's Law states that the current (I) flowing through a conductor is directly proportional to the voltage (V) across it and inversely proportional to the resistance (R) of the conductor. Mathematically, it can be written as: \[I = \frac{V}{R}\] In the case of induced emf, the voltage across the conductor is equal to the induced emf (\(\varepsilon\)). Therefore, the equation becomes: \[I = \frac{\varepsilon}{R}\]
03

Analyze the dependence of induced emf on resistance

From Faraday's Law, we can see that the induced emf (\(\varepsilon\)) is calculated based on the rate of change of magnetic flux (\(\frac{d\Phi}{dt}\)) and the number of turns in the loop (N). There is no mention of resistance (R) in this equation. Thus, the induced emf (\(\varepsilon\)) does not depend on the resistance of the circuit. Answer (a): No, the induced emf in a circuit does not depend on the resistance of the circuit.
04

Analyze the dependence of induced current on resistance

Now, we can use the modified Ohm's Law equation, as discussed in Step 2, to analyze the relationship between induced current and resistance: \[I = \frac{\varepsilon}{R}\] In this equation, the induced current (I) depends on the induced emf (\(\varepsilon\)) and the resistance (R) of the circuit. If the resistance (R) increases, the induced current (I) will decrease and vice versa. Answer (b): Yes, the induced current depends on the resistance of the circuit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law
Ohm's Law is a fundamental principle in the field of electrical circuits. It describes the relationship between voltage, current, and resistance within a conductor. The equation for Ohm's Law is simple yet powerful:
  • Current (I) is directly proportional to Voltage (V).
  • Current (I) is inversely proportional to Resistance (R).
This means that if you increase the voltage across a conductor, the current will also increase, provided the resistance stays constant. Conversely, if you increase the resistance while keeping the voltage constant, the current will decrease.

In the context of the exercise, when an induced emf is present, Ohm's Law helps us determine the resulting current in the circuit. The current is given by the equation \(I = \frac{\varepsilon}{R}\), where \(\varepsilon\) is the induced electromotive force (emf), and \(R\) is the resistance of the circuit. Understanding this relationship is crucial for analyzing circuits with induced emf.
Induced EMF
Induced emf refers to the voltage generated in a circuit due to the change in magnetic flux over time. This phenomenon is at the heart of Faraday's Law of Electromagnetic Induction, which states that the induced emf in a loop is proportional to how fast the magnetic environment of that loop is changing. This can be summarised with the equation:
  • \(\varepsilon = -N \frac{d\Phi}{dt}\)
where:
  • \(N\) is the number of turns in the coil.
  • \(d\Phi/dt\) is the rate of change of the magnetic flux.
The negative sign shows that the induced emf creates a current and magnetic field that oppose the change in flux, which is a manifestation of Lenz's Law.

Crucially, induced emf does not depend on the resistance of the circuit. It is determined solely by the parameters relating to the magnetic flux and the loop's characteristics, such as the number of turns in the coil. This makes induced emf a pivotal concept in understanding electromagnetic processes like how generators and transformers work.
Induced Current
Induced current is the result of the induced emf acting upon a circuit. When emf is induced in a loop due to a changing magnetic field, it drives current through the circuit. The magnitude of this induced current can be calculated by applying Ohm’s Law to the induced emf situation:
  • \(I = \frac{\varepsilon}{R}\).
This equation indicates that induced current is directly influenced by both the induced emf (\(\varepsilon\)) and the resistance (\(R\)) of the circuit.

The relationship is straightforward:
  • An increase in resistance results in a decrease in current.
  • An increase in induced emf leads to an increase in current.
This dependency of current on resistance explains why, in practical circuits, variations in resistance alter the current flow, even if the induced emf remains constant.
Resistance in Circuits
Resistance in circuits quantifies how much a component or material opposes the flow of electric current. Measured in ohms (\(\Omega\)), resistance is a crucial factor in determining current flow within any circuit.
  • Higher resistance means less current can flow.
  • Conversely, lower resistance allows more current to flow.
In the context of electromagnetic induction, resistance plays a significant role in determining the magnitude of induced current based on the induced emf. According to Ohm’s Law and our context:
  • The equation \(I = \frac{\varepsilon}{R}\) shows that the current \(I\) is inversely proportional to resistance \(R\).
This means that if all other factors like induced emf remain the same, an increase in resistance will cause a decrease in the current flowing through the circuit. This phenomenon has practical implications in the design and function of various electrical devices and circuits, where controlling resistance allows for the desired current levels to be achieved.

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Most popular questions from this chapter

A metal bar of length 25 cm is placed perpendicular to a uniform magnetic field of strength 3 T. (a) Determine the induced emf between the ends of the rod when it is not moving. (b) Determine the emf when the rod is moving perpendicular to its length and magnetic field with a speed of \(50 \mathrm{cm} / \mathrm{s}\).

Design a current loop that, when rotated in a uniform magnetic field of strength 0.10 T, will produce an emf \(\varepsilon=\varepsilon_{0} \sin \omega t, \quad\) where \(\varepsilon_{0}=110 \mathrm{V}\) and \(\omega=120 \pi \mathrm{rad} / \mathrm{s}\).

A 25-cm rod moves at 5.0 m/s in a plane perpendicular to a magnetic field of strength 0.25 T. The rod, velocity vector, and magnetic field vector are mutually perpendicular, as indicated in the accompanying figure. Calculate (a) the magnetic force on an electron in the rod, (b) the electric field in the rod, and (c) the potential difference between the ends of the rod. (d) What is the speed of the rod if the potential difference is \(1.0 \mathrm{V}\) ?

Over a region of radius \(R\), there is a spatially uniform magnetic field \(\overrightarrow{\mathbf{B}}\). (See below.) At \(t=0, B=1.0 \mathrm{T}\) after which it decreases at a constant rate to zero in 30 s. (a) What is the electric field in the regions where \(r \leq R\) and \(r \geq R\) during that \(30-s\) interval? (b) Assume that \(R=10.0 \mathrm{cm} .\) How much work is done by the electric field on a proton that is carried once clock wise around a circular path of radius \(5.0 \mathrm{cm}\) ? (c) How much work is done by the electric field on a proton that is carried once counterclockwise around a circular path of any radius \(r \geq R ?\) (d) At the instant when \(B=0.50 \mathrm{T},\) a proton enters the magnetic field at \(A,\) moving a velocity \(\overrightarrow{\mathbf{v}}\) \(\left(v=5.0 \times 10^{6} \mathrm{m} / \mathrm{s}\right)\) as shown. What are the electric and magnetic forces on the proton at that instant?

A square bar of mass \(m\) and resistance \(R\) is sliding without friction down very long, parallel conducting rails of negligible resistance (see below). The two rails are a distance \(l\) apart and are connected to each other at the bottom of the incline by a zero-resistance wire. The rails are inclined at an angle \(\theta,\) and there is a uniform vertical magnetic field \(\overrightarrow{\mathbf{B}}\) throughout the region. (a) Show that the bar acquires a terminal velocity given by \(v=\frac{m g R \sin \theta}{B^{2} l^{2} \cos ^{2} \theta} .\) (b) Calculate the work per unit time done by the force of gravity. (c) Compare this with the power dissipated in the Joule heating of the bar. (d) What would happen if \(\overrightarrow{\mathbf{B}}\) were reversed?

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