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Show that the Hall voltage across wires made of the same material, carrying identical currents, and subjected to the same magnetic field is inversely proportional to their diameters. (Hint: Consider how drift velocity depends on wire diameter.)

Short Answer

Expert verified
The Hall voltage (V_H) can be expressed as: \(V_H = Bw\cdot\dfrac{4I}{\pi n D^2 e}\) where: - B is the strength of the magnetic field - w is the width of the wire - I is the current in the wire - n is the number of charge carriers per unit volume - D is the diameter of the wire - e is the elementary charge (1.6 x 10^-19 C) Since B, w, I, n, and e are constants, the Hall voltage is inversely proportional to the square of the diameter of the wire made of the same material, carrying identical currents, and subjected to the same magnetic field: \(V_H = \dfrac{K}{D^2}\) where K is a constant that depends on B, w, I, and n.

Step by step solution

01

Write down the formula for drift velocity

The drift velocity (v_d) of charge carriers in a wire can be expressed as: \(v_d = \dfrac{I}{n A e}\) where: - I is the current in the wire - n is the number of charge carriers per unit volume - A is the cross-sectional area of the wire - e is the elementary charge (1.6 x 10^-19 C)
02

Express cross-sectional area in terms of diameter

The cross-sectional area (A) of the wire can be expressed in terms of its diameter (D) as: \(A = \dfrac{\pi D^2}{4}\)
03

Substitute the expression for the cross-sectional area into the drift velocity equation

Now, let's substitute the expression for the cross-sectional area from step 2 into the drift velocity equation from step 1: \(v_d = \dfrac{I}{n \cdot \dfrac{\pi D^2}{4} \cdot e}\) Simplify the equation: \(v_d = \dfrac{4I}{\pi n D^2 e}\)
04

Write down the formula for the Hall voltage

The Hall voltage (V_H) can be expressed as: \(V_H = B w v_d\) where: - B is the strength of the magnetic field - w is the width of the wire
05

Substitute the expression for drift velocity into the Hall voltage equation

Now, let's substitute the expression for the drift velocity from step 3 into the Hall voltage equation from step 4: \(V_H = B w \cdot \dfrac{4I}{\pi n D^2 e}\)
06

Show that Hall voltage is inversely proportional to wire diameter

Since B, w, I, and n are constants for the given wire subjected to the same conditions, as well as e being a constant, the Hall voltage can be expressed as: \(V_H = \dfrac{K}{D^2}\) where K is a constant that depends on B, I, n, and w. This equation shows that the Hall voltage is inversely proportional to the square of the diameter of the wire made of the same material, carrying identical currents, and subjected to the same magnetic field.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Drift Velocity
Understanding the concept of drift velocity is essential in explaining the Hall effect and the resulting Hall voltage. Drift velocity, represented by the symbol \(v_d\), is the average velocity at which charge carriers, such as electrons, move through a material when an electric current flows.

In the context of a conducting wire, these charge carriers respond to an electric field, moving from the negative to the positive end. The drift velocity formula is \(v_d = \dfrac{I}{n A e}\) where \(I\) is the electric current, \(n\) represents the density of charge carriers, \(A\) is the cross-sectional area of the wire, and \(e\) is the elementary charge. It is important to note that a larger diameter wire has a greater cross-sectional area, affecting the drift velocity when the current is kept constant.

This relationship is pivotal when exploring the effects of changing the diameter in a Hall voltage scenario because as the wire diameter increases, the area for charge carriers to move through also increases, subsequently causing a decrease in drift velocity.
Wire Diameter
The diameter of a wire is a fundamental physical characteristic that influences its electrical properties. When evaluating the Hall voltage, the wire diameter plays a significant role. The cross-sectional area of the wire, which is directly related to its diameter, is calculated using the formula \(A = \dfrac{\pi D^2}{4}\) where \(D\) is the diameter of the wire.

Hence, for wires of different diameters carrying the same current, the drift velocity will differ because the area through which the charge carriers move affects their concentration. A thinner wire (smaller diameter) means a smaller cross-sectional area, leading to a higher concentration of charge carriers and, in turn, a higher drift velocity if the current is constant. This principle is central in understanding how the Hall voltage is affected by changes in wire diameter.
Magnetic Field
The magnetic field, denoted as \(B\), is an invisible field that exerts a force on moving electric charges, which can result in a potential difference across a conductor—this is known as the Hall voltage. In the Hall effect, a magnetic field applied perpendicular to the direction of current flow in a wire will act upon the charge carriers, causing them to accumulate on one side of the conductor.

The formula for Hall voltage includes the magnetic field: \(V_H = B w v_d\), where \(w\) is the width of the conductor, and \(v_d\) is the drift velocity. The strength and orientation of the magnetic field directly affect the magnitude of the Hall voltage, highlighting why it is a critical factor in the exercise.
Inverse Proportion
The concept of inverse proportionality is a relationship between two variables where as one variable increases, the other decreases at a rate that maintains a constant product. In the context of Hall voltage and wire diameter, we observe such an inverse proportional relationship.

The final expression derived in the solution, \(V_H = \dfrac{K}{D^2}\), where \(K\) is a constant encompassing \(B\), \(I\), \(n\), \(w\), and \(e\), shows that Hall voltage (\(V_H\)) varies inversely with the square of the diameter (\(D\)) of the wire. This means that as the diameter of the wire is increased, the Hall voltage decreases and vice versa. This inverse square relationship ensures that for wires of the same material and with identical currents in the same magnetic field, their Hall voltage is smaller for wires with larger diameters.

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Most popular questions from this chapter

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