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A circular coil of wire of radius 5.0 cm has 20 turns and carries a current of \(2.0 \mathrm{A}\). The coil lies in a magnetic field of magnitude \(0.50 \mathrm{T}\) that is directed parallel to the plane of the coil. (a) What is the magnetic dipole moment of the coil? (b) What is the torque on the coil?

Short Answer

Expert verified
The magnetic dipole moment of the coil is approximately \(0.314 \mathrm{A \cdot m^2}\) and the torque acting on the coil is approximately \(0.157 \mathrm{N \cdot m}\).

Step by step solution

01

Calculate the area of the coil

First, we need to find the area of the coil. Since it's a circular coil, we can use the formula for the area of a circle: A = πr^2, where r is the radius of the circle. The radius r = 5.0 cm or 0.05 m (since we need to convert to meters for SI units). Now, we can calculate the area (A): A = π(0.05 m)^2 A = π(0.0025 m^2) A ≈ 0.00785 m^2
02

Calculate the magnetic dipole moment

Now that we have the area of the coil, we can calculate the magnetic dipole moment (μ) using the formula: μ = N × I × A, where N is the number of turns, I is the current, and A is the area. N = 20 turns I = 2.0 A μ = 20 × 2.0 A × 0.00785 m^2 μ ≈ 0.314 A·m^2 Thus, the magnetic dipole moment of the coil is approximately 0.314 A·m^2.
03

Calculate the torque on the coil

Lastly, we must calculate the torque (τ) acting on the coil. The formula for torque is τ = μ × B × sin(θ), where μ is the magnetic dipole moment, B is the magnitude of the magnetic field, and θ is the angle between the magnetic field and the magnetic dipole moment. In this problem, the magnetic field B = 0.50 T and since the magnetic field is parallel to the plane of the coil, the angle θ = 90 degrees, so sin(θ) = 1. Using the formula and the given values, we can now calculate the torque: τ = 0.314 A·m^2 × 0.50 T × 1 τ ≈ 0.157 N·m The torque acting on the coil is approximately 0.157 N·m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
Imagine being surrounded by an invisible force that guides the needles of compasses and pulls on the iron in our blood – that's a magnetic field for you. A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the direction of the magnetic field.

This is described by the Lorentz force law and is the fundamental principle behind the workings of electromagnets, electric motors, and generators. Magnetic fields are measured in units of teslas (T) in the International System of Units (SI). Our planet Earth itself has a magnetic field, which is why compasses point north. In our textbook problem, a magnetic field of 0.50 T is acting on the coil, which interacts with the current flowing through the coil to exert a force – known as the Lorentz force.
Torque on a Coil
Torque is essentially a twist or turn that causes an object to rotate around an axis. When it comes to a coil in a magnetic field, torque arises from the magnetic forces acting at a distance from the coil's axis. A simple equation, \( \tau = \mu \times B \times \sin(\theta) \), where \( \mu \) is the magnetic dipole moment, \( B \) is the magnetic field, and \( \theta \) is the angle between \( \mu \) and \( B \) can calculate it.

In layman's terms, the greater the current and the number of loops in the coil, or the stronger the magnetic field, the bigger the twist. In our problem, the coil is placed parallel to the magnetic field, resulting in the maximum possible torque because \( \sin(90^\circ) = 1 \). This maximizes the product of the coil's magnetic dipole moment and the magnetic field strength, resulting in a torque that seeks to rotate the coil to align with the magnetic field.
Circular Coil
Our problem revolves around a circular coil, a simple yet fascinating component often found in electromagnets and electrical engines. The coil's shape is essential because it creates a uniform magnetic field inside it, making it extremely useful in technological applications. To understand a circular coil's properties, think of it as many tiny straight wires bent into a loop, with current running through them, creating magnetic fields that stack up and generate a larger, cohesive magnetic field through the loop's center.

The area of a circular coil is pivotal when calculating its magnetic dipole moment as shown in the step-by-step solution using the formula \( A = \pi r^2 \). The area, the number of turns in the coil, and the current running through it all come into play when determining how ‘potent’ the magnetic field generated by the coil will be.
SI Units
In science, having a universal language is crucial, and that's where SI units come into play. SI units, or the International System of Units, are the globally accepted standard for measurements. They serve as a reliable framework for all physical quantities. Whether we're measuring length (meters), mass (kilograms), time (seconds), or, in the case of our magnetic coil, magnetic field strength (teslas) and magnetic dipole moments (ampere meters squared, A·m²), SI units ensure that everyone, from America to Zimbabwe, is on the same page.

When solving physics problems, it's important to convert all your measurements to SI units before starting your calculations to avoid any mismatch or confusion – just as we converted the radius of the coil to meters from centimeters in the given solution.

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Most popular questions from this chapter

(a) What is the angle between a wire carrying an 8.00-A current and the 1.20-T field it is in if 50.0 cm of the wire experiences a magnetic force of \(2.40 \mathrm{N}\) ? (b) What is the force on the wire if it is rotated to make an angle of \(90^{\circ}\) with the field?

An electron moving along the \(+x \quad\) -axis at \(5.0 \times 10^{6} \mathrm{m} / \mathrm{s}\) enters a magnetic field that makes a \(75^{\circ}\) angle with the \(x\) -axis of magnitude 0.20 T. Calculate the (a) pitch and (b) radius of the trajectory.

A particle of charge \(q\) and mass \(m\) is accelerated from rest through a potential difference \(V\), after which it encounters a uniform magnetic field \(B\). If the particle moves in a plane perpendicular to \(B\), what is the radius of its circular orbit?

\(\mathrm{An}\) electron moving with a velocity and the $$\overrightarrow{\mathbf{v}}=(4.0 \hat{\mathbf{i}}+3.0 \hat{\mathbf{j}}+2.0 \hat{\mathbf{k}}) \times 10^{6} \mathrm{m} / \mathrm{s}$$ enters a region where there is a uniform electric field and a uniform magnetic field. The magnetic field is given by $$\vec{B}=(1.0 \hat{\mathbf{i}}-2.0 \hat{\mathbf{j}}+4.0 \hat{\mathbf{k}}) \times 10^{-2} \mathrm{T}$$. If the electron travels through a region without being deflected, what is the electric field?

The Hall effect is to be used to find the sign of charge carriers in a semiconductor sample. The probe is placed between the poles of a magnet so that magnetic field is pointed up. A current is passed through a rectangular sample placed horizontally. As current is passed through the sample in the east direction, the north side of the sample is found to be at a higher potential than the south side. Decide if the number density of charge carriers is positively or negatively charged.

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