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(a) What is the maximum torque on a 150 -turn square loop of wire \(18.0 \mathrm{cm}\) on a side that carries a 50.0 - \(\mathrm{A}\) current in a 1.60 -T field? (b) What is the torque when \(\theta\) is \(10.9^{\circ} ?\)

Short Answer

Expert verified
The maximum torque on the 150-turn square loop of wire is approximately \(1176\,\mathrm{N \cdot m}\), and the torque when \(\theta\) is \(10.9^{\circ}\) is approximately \(221.69\,\mathrm{N \cdot m}\).

Step by step solution

01

Find the area of the loop

Since the loop has a side length of 18.0 cm (0.18 meters), calculate the area with the following equation: \[A = s^2\] Where A is the area and s is the side length. \[A = (0.18)^2 = 0.0324 \mathrm{m}^2\]
02

Calculate the maximum torque

The sine function is at its maximum when \(\theta = 90^{\circ}\). In this case, the sine function would be equal to 1. Using the torque formula, calculate the maximum torque: \[\tau_{max} = NIAB \sin \theta = (150)(50.0\,\mathrm{A})(0.0324\,\mathrm{m}^2)(1.60\,\mathrm{T})(1)\] \[\tau_{max} = 1176\,\mathrm{N \cdot m}\]
03

Calculate the torque when \(\theta\) is \(10.9^{\circ}\)

Now we must calculate the torque for the angle of \(10.9^{\circ}\). Use the formula for torque: \[\tau = NIAB \sin \theta = (150)(50.0\,\mathrm{A})(0.0324\,\mathrm{m}^2)(1.60\,\mathrm{T})\sin 10.9^{\circ}\] \[\tau = 1176\,\mathrm{N \cdot m} (\sin 10.9^{\circ})\] \[\tau \approx 221.69\,\mathrm{N \cdot m}\] The maximum torque on the square loop of wire is approximately 1176 Nâ‹…m, and the torque when the angle is 10.9 degrees is approximately 221.69 Nâ‹…m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Moment
The magnetic moment is a fundamental concept when dealing with magnetic fields and current loops. It measures the strength and orientation of a magnetic source. Think of it as a tiny magnet with its own north and south pole. In physics, for a current loop, the magnetic moment (\( \mu \)) is calculated using the formula:
\[ \mu = NIA \]
Where:
  • \( N \) is the number of turns in the loop,
  • \( I \) represents the current flowing through the loop,
  • \( A \) is the area of the loop.
The direction of the magnetic moment is perpendicular to the current loop. It is determined by the right-hand rule: if your fingers follow the direction of the current, your thumb points in the direction of the magnetic moment.
The greater the product of these factors, the stronger the magnetic moment, and consequently the greater its potential interaction with external magnetic fields.
Current Loop
When we talk about a current loop, we refer to a closed path where electricity flows. In our scenario, it is a square loop of wire. Current loops are important because they can create magnetic fields similar to a bar magnet.
The loop's dimensions impact the behavior of the magnetic field and the forces acting on the loop. For a square loop, we calculate the area (\( A \)) using:
\[ A = s^2 \]
This concept is crucial, as the area helps determine the magnetic moment. A wire looping back on itself allows the current's effects to be cumulative over multiple turns, amplifying the magnetic field produced.
The geometry and number of turns (150 in our case) help determine the loop's efficiency in interacting with magnetic fields. This directly affects the torque experienced by the loop when placed in an external magnetic field.
Torque Calculation
Torque in a magnetic field refers to the rotational force experienced by a current loop when placed in a magnetic field. This is especially true when the loop is oriented at an angle to the field. The torque (\( \tau \)) experienced by a current loop can be calculated using:
\[ \tau = NIAB \sin \theta \]
The formula shows that torque depends on:
  • \( N \), the number of turns,
  • \( I \), the current through the loop,
  • \( A \), the loop area,
  • \( B \), the magnetic field strength, and
  • \( \theta \), the angle between the magnetic moment and the magnetic field.
The torque is at maximum when \( \theta \) is 90°, meaning the magnetic moment is perpendicular to the field lines. This results in the sine of the angle being 1. When \( \theta \) is small, as in our example with 10.9°, the sine of the angle reduces the effective torque. Understanding this concept helps narrate how angles between the loop’s moment and field affect its rotational tendency.
Physics Problem Solving
Physics problem-solving involves breaking down complex scenarios into simpler, manageable parts. This is particularly useful in calculating torque in magnetic fields:
  • Firstly, identify all given values (such as current, number of turns, side length, and magnetic field strength).
  • Next, calculate intermediary values like the area of the loop.
  • Use relevant formulas, such as the one for torque, to find the desired unknowns.
Strategic problem-solving often involves keeping track of units, making sure calculations are precise, and checking your work against expected physical behavior (e.g., torque values should make physical sense regarding force exerted). Learning to visualize the problem and apply systematic logic can greatly enhance your physics competence, helping to demystify complex topics like torque in magnetic fields.

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Most popular questions from this chapter

A 5.0-m section of a long, straight wire carries a current of 10 A while in a uniform magnetic field of magnitude \(8.0 \times 10^{-3} \mathrm{T}\). Calculate the magnitude of the force on the section if the angle between the field and the direction of the current is (a) \(45^{\circ} ;\) (b) \(90^{\circ} ;\) (c) \(0^{\circ} ;\) or \((\mathrm{d})\) \(180^{\circ}\).

Calculate the magnetic field strength needed on a 200-turn square loop 20.0 cm on a side to create a maximum torque of \(300 \mathrm{N} \cdot \mathrm{m}\) if the loop is carrying 25.0 A.

The mass and charge of a water droplet are \(1.0 \times 10^{-4} \mathrm{g}\) and \(2.0 \times 10^{-8} \mathrm{C}, \quad\) respectively. If the droplet is given an initial horizontal velocity of \(5.0 \times 10^{5} \hat{\mathbf{i}} \mathrm{m} / \mathrm{s}, \quad\) what magnetic field will keep it moving in this direction? Why must gravity be considered here?

A circular loop of wire of area \(10 \mathrm{cm}^{2}\) carries a current of 25 A. At a particular instant, the loop lies in the \(x y\) -plane and is subjected to a magnetic field $$\overrightarrow{\mathbf{B}}=(2.0 \hat{\mathbf{i}}+6.0 \hat{\mathbf{j}}+8.0 \hat{\mathbf{k}}) \times 10^{-3} \mathrm{T} . \quad \text { As } \quad \text { viewed }$$ from above the \(x y\) -plane, the current is circulating clockwise. (a) What is the magnetic dipole moment of the current loop? (b) At this instant, what is the magnetic torque on the loop?

The density of charge carriers for copper is \(8.47 \times 10^{28}\) electrons per cubic meter. What will be the Hall voltage reading from a probe made up of \(3 \mathrm{cm} \times 2 \mathrm{cm} \times 1 \mathrm{cm}(\mathrm{L} \times \mathrm{W} \times \mathrm{T})\) copper plate when a current of \(1.5 \mathrm{A}\) is passed through it in a magnetic field of \(2.5 \mathrm{T}\) perpendicular to the \(3 \mathrm{cm} \times 2 \mathrm{cm}\).

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