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Stars \(A\) and \(B\) are both equally bright as seen from Earth, but \(A\) is \(120 \mathrm{pc}\) away while \(B\) is \(24 \mathrm{pc}\) away. Which star has the greater luminosity? How many times greater is it?

Short Answer

Expert verified
Star A has a greater luminosity which is 25 times greater than that of Star B.

Step by step solution

01

Understanding the problem and the equation

We know that, from the inverse square law, the luminosity \(L\) of a star is directly proportional to the square of its distance \(d\) from the observer, the equation can be written as: \(L \propto d^2\). Here 'pc' denotes 'parsecs', a unit of distance in astronomy.
02

Calculating the luminosity of star A relative to B

Let's assume the luminosity of star A is \(L_A\) and of star B is \(L_B\). The ratio of luminosity of A to B can be described as the ratio of squares of their distances: \(\frac{L_A}{L_B} = \frac{d_A^2}{d_B^2}\)
03

Inputting the given values into the equation

By substituting the distance of star A \(d_A = 120pc\) and the distance of star B \(d_B = 24pc\) in the equation we get: \(\frac{L_A}{L_B} = \frac{(120)^2}{(24)^2}\)
04

Solving the equation

Solving the equation, we get \(\frac{L_A}{L_B} = 25\). This means the luminosity of star A is 25 times greater than that of star B.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Square Law
The inverse square law is a fundamental principle in astrophysics, which states that the intensity of a physical quantity decreases with the square of the distance from the source. This concept is particularly important when dealing with stellar luminosity. The luminosity, which is the total amount of energy a star emits per second, diminishes as the distance from the star increases. This relationship can be expressed mathematically as \[ I \propto \frac{1}{d^2} \]where \(I\) is the intensity, and \(d\) is the distance.
This equation helps us understand that if the distance from the star is doubled, the observed brightness or intensity will be one-fourth of its original value. Similarly, if a star is three times farther away, the brightness we perceive will be one-ninth. In our original exercise, by using the inverse square law, we determine the relative brightness of stars at different distances. This principle is essential in comparing stars' luminosities seen from Earth.
Distance in Astronomy
In astronomy, measuring distance is crucial for understanding the universe's size and structure. However, given the immense distances involved in space, we need specialized units to make these measurements comprehensible. One commonly used unit is the light-year, but in observational astronomy, we often use another unit called the parsec (pc).
A parsec is a distance that corresponds to a parallax angle of one arcsecond. It equates approximately to 3.26 light-years. This unit helps astronomers express stellar distances succinctly and effectively. Utilizing parsecs allows for a more straightforward comparison of distances when calculating luminosity. For example, when considering stars at 120 pc and 24 pc, this unit simplifies the understanding of relative luminosities. Understanding the distances between stars is vital when analyzing their intrinsic properties, such as luminosity and size.
Parsecs
The parsec is an astronomical unit of distance that provides an easy way to measure extremely large distances between celestial bodies. Its name derives from the technique of parallax measurement and is defined as the distance at which one astronomical unit subtends an angle of one arcsecond.
While its exact conversion is 3.26 light-years, it remains one of the more practical ways for astronomers to gauge distances within the Milky Way and other nearby galaxies. When using parsecs, it simplifies calculations related to the brightness of stars and galaxies due to its alignment with astronomical observations. Having star distances in parsecs is particularly beneficial when we need to calculate stellar luminosity using the inverse square law, as observed in our problem with stars A and B.
Luminosity Comparison
Comparing the luminosities of stars is not just about observing their brightness from Earth, as seemingly bright stars can appear dim merely due to their distance. Therefore, we need to rely on formulas like the inverse square law to determine their true luminosity, unaffected by distance.
In our exercise, we see that Star A, although further from Earth, has greater intrinsic luminosity than Star B. By using the inverse square law, we calculate that Star A's luminosity is 25 times greater than that of Star B despite appearing equally bright. The equation \[ \frac{L_A}{L_B} = \frac{d_A^2}{d_B^2} \]plays a crucial role here. Calculations like these are key to unraveling the true nature of stars and comprehending the vast array of stellar characteristics observed throughout the universe.

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Most popular questions from this chapter

It is desirable to be able to measure the radial velocity of stars (using the Doppler effect) to an accuracy of \(1 \mathrm{~km} / \mathrm{s}\) or better. One complication is that radial velocities refer to the motion of the star relative to the Sun, while the observations are made using a telescope on the Earth. Is it important to take into account the motion of the Earth around the Sun? Is it important to take into account the Earth's rotational motion? To answer this question, you will have to calculate the Earth's orbital speed and the speed of a point on the Earth's equator (the part of the Earth's surface that moves at the greatest speed because of the planet's rotation). If one or both of these effects are of importance, how do you suppose astronomers compensate for them?

78\. Use the Stamy Night Enthusiast \({ }^{\mathrm{TM}}\) program to investigate the brightest stars. Click on Home to show the sky as seen from your location. Set the date to today's date and the time to midnight (12:00:00 A.M.). Open the Options pane, expand the Constellations layer and click the Boundaries and Labels options to turn these displays on. You will now see the boundaries of the constellations. Open the Info pane and expand the Position in Space and Other Data lists. (a) Scroll around the sky and identify at least five of the brighter stars (shown as larger dots) and click on them to reveal relevant data in the Info pane. Make a list of these stars and record Luminosity and Distance from Sun from the Info pane. Which stars did you select? In which constellation does each of these stars lie? Which of these stars are listed in Appendix 5 ? Of these, which is the most luminous? Which is the most distant? (b) Set the date to six months from today, and again set the time to 12:00:00 A.M. Which of the stars that you selected in part (a) are visible? (You can use the Find pane to attempt to locate your selected stars.) Which are not? Explain why the passage of six months should make a difference.

The solar constant, equal to \(1370 \mathrm{~W} / \mathrm{m}^{2}\), is the amount of light energy from the Sun that falls on 1 square meter of the Earth's surface in 1 second (see Section 17-2). What would the distance between the Earth and the Sun have to be in order for the solar constant to be 1 watt per square meter \(\left(1 \mathrm{~W} / \mathrm{m}^{2}\right)\) ?

Explain why the color ratios of a star are related to the star's surface temperature.

Give two reasons why a visual binary star is unlikely to also be a spectroscopic binary star.

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