Chapter 20: Problem 4
An electric bulb of volume \(250 \mathrm{~cm}^{3}\) was sealed off during manufacture at a pressure of \(10^{-3} \mathrm{~mm}\) of mercury at \(27^{\circ} \mathrm{C}\). Compute the number of air molecules contained in the bulb. Given that \(R=8.31 \mathrm{~J} / \mathrm{mol}-\mathrm{K}\) and \(N_{A}=6.02 \times 10^{23}\) per mol.
Short Answer
Step by step solution
Understanding Given Values
Convert Units
Applying Ideal Gas Law
Solve for Number of Moles
Calculate Number of Molecules
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Unit Conversion
- Pressure from millimeters of mercury (mm Hg) to Pascals (Pa), using the factor that 1 mm Hg = 133.32 Pa. This gives us 0.13332 Pa from the original pressure of 0.001 mm Hg.
- Volume from cubic centimeters to cubic meters (m鲁), with 1 cm鲁 = 10鈦烩伓 m鲁, resulting in 0.00025 m鲁 for the bulb's volume of 250 cm鲁.
- Temperature from Celsius to Kelvin, achieved by adding 273.15 to the reported Celsius temperature. Thus, a temperature of 27掳C converts to 300.15 K.
Number of Moles
Avogadro's Number
Pressure Conversion
- 1 mm Hg = 133.32 Pa