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Two Pulleys and a Canister In Fig. \(9-28\), a cord runs around two massless, frictionless pulleys; a canister with mass \(m=20 \mathrm{~kg}\) hangs from one pulley; and you exert a force \(\vec{F}\) on the free end of the cord. (a) What must be the magnitude of \(\vec{F}\) if you are to lift the canister at a constant speed? (b) To lift the canister by \(2.0 \mathrm{~cm}\), how far must you pull the free end of the cord? During that lift, what is the work done on the canister by (c) your force (via the cord) and (d) the gravitational force on the canister? (Hint: When a cord loops around a pulley as shown, it pulls on the pulley with a net force that is twice the tension in the cord.)

Short Answer

Expert verified
To lift the canister at a constant speed, exert 98 N. Pull the cord by 4.0 cm to lift the canister by 2.0 cm. The work done by your force is 3.92 J, and the gravitational force is -3.92 J.

Step by step solution

01

Determine the tension in the cord

Since the canister must be lifted at a constant speed, the net force on it is zero. Therefore, the upward force (tension) in the cord must equal the downward gravitational force on the canister. The gravitational force is given by the weight of the canister: the force of gravity, \[ F_g = mg = 20 \times 9.8 = 196 \text{ N} \]
02

Relate the tension to the force you exert

The tension in the cord, which we’ll call T, must balance the force of gravity on the canister, but the pulley system modifies this relationship. Given that the cord loops around the pulley, it creates a net force of twice the tension in the cord. Hence: \[2T = 196 \text{ N} \]Thus, solving for T, \[T = 98 \text{ N} \]
03

Determine the force required to lift the canister

To maintain this tension throughout the cord, the force you exert must equal the tension.Thus, \[ F = T = 98 \text{ N} \]
04

Calculate the distance you must pull the cord to lift the canister

Since the cord goes around the pulley, lifting the canister by 2.0 cm requires pulling twice that length of cord. Therefore, \[ d = 2 \times 2.0 \text{ cm} = 4.0 \text{ cm} \] or, in meters, \[ d = 0.04 \text{ m} \]
05

Calculate the work done by your force

Work is given by the formula: \[ W = F \times d \] Given the values, \[ W = 98 \text{ N} \times 0.04 \text{ m} = 3.92 \text{ J} \]
06

Calculate the work done by gravitational force

The work done by gravitational force is given by: \[ W = F_g \times h \] where h is the height, \[ W = 196 \text{ N} \times 0.02 \text{ m} = 3.92 \text{ J} \] Notice that this work is negative since gravity acts in the opposite direction of the displacement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

tension in physics
Tension is a force exerted by a cord, rope, or similar object under pulling stress. In the context of pulleys, the tension in the cord is crucial to analyze. When lifting a canister at a constant speed using pulleys, tension is balanced by the force of gravity. For instance, the gravitational force on a 20 kg canister is determined by \(F_g = 196 \text{ N}\). When the cord loops around a pulley, the net force is twice the tension, implying \(2T = 196 \text{ N}\). Solving for tension, we get \(T = 98 \text{ N}\). This tension must be maintained by the force you exert. So, the force \(F\) needed to lift the canister at a constant speed is precisely equal to the tension in the cord, \(F = 98 \text{ N}\).
Understanding tension helps explain why certain forces are required to maintain equilibrium in pulley systems and similar setups.
work and energy
Work and energy principles are vital for understanding how forces cause displacement and how energy is transferred. Work is calculated with the formula \(W = F \times d\). Here, \(F\) is the force applied (98 N) and \(d\) is the displacement (0.04 m). Thus, work done by your force in raising the canister by 2.0 cm is \[W = 98 \text{ N} \times 0.04 \text{ m} = 3.92 \text{ J}\].
This shows energy is transferred from you to the canister, elevating it against gravity. The work-energy theorem states that the work done on an object results in a change in its energy. In this case, your applied work exactly counteracts the gravitational potential energy change, ensuring a smooth and constant lift.
gravitational force
Gravitational force is the attractive force between two masses. It plays a significant role in the example of lifting a canister. The force due to gravity on the canister is \(F_g = mg\), calculated as \((20 \text{ kg} \times 9.8 \text{ m/s}^2 = 196 \text{ N})\).
This force resists your pulling effort. When raising the canister by 2.0 cm (0.02 m), the gravitational force acts downward. The work done by gravity is therefore: \[W = F_g \times h = 196 \text{ N} \times 0.02 \text{ m} = 3.92 \text{ J}\].
Since gravity acts in the opposite direction of motion, the work done by the gravitational force is negative. Essentially, you're doing positive work to lift the canister, while gravity does negative work, maintaining energy balance. This illustrates how understanding gravitational force is essential for predicting and calculating work and energy in physical systems.

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