/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 What is the magnitude of the acc... [FREE SOLUTION] | 91Ó°ÊÓ

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What is the magnitude of the acceleration of a sprinter running at \(10 \mathrm{~m} / \mathrm{s}\) when rounding a turn with a radius of \(25 \mathrm{~m}\) ?

Short Answer

Expert verified
The magnitude of the acceleration is \( 4 \, m/s^2 \).

Step by step solution

01

- Understand the Problem

Identify the given values from the problem. The sprinter's speed is given as \(10 \, m/s\) and the radius of the turn is \(25 \, m\).
02

- Recall the Formula

The magnitude of the centripetal acceleration can be calculated using the formula: \( a = \frac{v^2}{r} \) where \(v\) is the speed and \(r\) is the radius of the turn.
03

- Substitute the Given Values

Substitute the given values into the formula: \( a = \frac{(10 \, m/s)^2}{25 \, m} \)
04

- Perform the Calculation

Calculate the expression: \( a = \frac{100 \, m^2/s^2}{25 \, m} = 4 \, m/s^2 \)
05

- State the Final Answer

The magnitude of the acceleration is \( 4 \, m/s^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Calculation
Acceleration is a measure of how quickly an object's velocity changes with time. In circular motion, the acceleration of an object moving at a constant speed in a circle is directed towards the center of the circle. This type of acceleration is called centripetal acceleration.

Centripetal acceleration can be calculated using the formula: \( a = \frac{v^2}{r} \), where \(v\) is the speed of the object, and \(r\) is the radius of the circle.
To solve the exercise given, we used the provided values

  • Speed of the sprinter, \(v = 10 \, m/s\)
  • Radius of the turn, \(r = 25 \, m\)

We substituted these values into the centripetal acceleration formula:
\( a = \frac{(10 \, m/s)^2}{25 \, m} \)
Performing the calculation, we get:
\( a = \frac{100 \, m^2/s^2}{25 \, m} = 4 \, m/s^2 \)

Thus, the magnitude of the acceleration is \( 4 \, m/s^2 \).
Kinematic Equations
Kinematic equations describe the motion of objects without considering the forces causing the motion. In the case of circular motion, these equations are slightly modified to account for the constant change in direction.

Some of the key kinematic equations in linear motion are:

  • \( v = u + at \)
  • \( s = ut + \frac{1}{2}at^2 \)
  • \( v^2 = u^2 + 2as \)

Here, \(u\) represents initial velocity, \(v\) is final velocity, \(a\) is acceleration, \(t\) is time, and \(s\) is displacement.

For circular motion, the equations incorporate angular parameters. One main equation related to the exercise is the one for centripetal acceleration, which is derived from transforming linear acceleration concepts to circular pathways. This is crucial in understanding how objects move in a curved path.
Circular Motion
Circular motion refers to the movement of an object along the perimeter of a circle or a circular path. It can be uniform, where the velocity remains constant, or non-uniform, where the velocity changes. The type of motion described in the exercise is uniform circular motion since the sprinter is moving at a constant speed.

Key concepts in circular motion include:
  • Centripetal Force: The force directed towards the center of the circle keeping the object in motion along the circular path.
  • Centripetal Acceleration: As discussed, it is the acceleration directed towards the center of the circle, calculated using \( a = \frac{v^2}{r} \).
  • Period and Frequency: The time taken to complete one full circle (period) and the number of circles completed per unit time (frequency).
Understanding these concepts helps us to grasp how the sprinter maintains their trajectory while rounding the turn, providing a clear connection between speed, radius, and the required centripetal acceleration.

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Most popular questions from this chapter

A particle moves horizontally in uniform circular motion, over a horizontal \(x y\) plane. At one instant, it moves through the point at coordinates \((4.00 \mathrm{~m}, 4.00 \mathrm{~m})\) with a velocity of \((-5.00 \mathrm{~m} / \mathrm{s}) \hat{\mathrm{i}}\) and an acceleration of \(\left(12.5 \mathrm{~m} / \mathrm{s}^{2}\right) \hat{\mathrm{j}}\). What are the coordinates of the center of the circular path?

Mike Powell In the 1991 World Track and Field Championships in Tokyo, Mike Powell (Fig. 5-30) jumped \(8.95 \mathrm{~m}\), breaking the 23 -year long-jump record set by Bob Beamon by a full \(5 \mathrm{~cm}\). Assume that Powell's speed on takeoff was \(9.5 \mathrm{~m} / \mathrm{s}\) (about equal to that of a sprinter) and that \(g=9.80 \mathrm{~m} / \mathrm{s}^{2}\) in Tokyo. How much less was Powell's horizontal range than the maximum possible horizontal range (neglecting the effects of air) for a particle launched at the same speed of \(9.5 \mathrm{~m} / \mathrm{s}\) ?

The fast French train known as the TGV (Train à Grande Vitesse) has a scheduled average speed of \(216 \mathrm{~km} / \mathrm{h} .\) (a) If the train goes around a curve at that speed and the magnitude of the acceleration experienced by the passengers is to be limited to \(0.050 \mathrm{~g}\), what is the smallest radius of curvature for the track that can be tolerated? (b) At what speed must the train go around a curve with a \(1.00 \mathrm{~km}\) radius to be at the acceleration limit?

A Small Ball A small ball rolls horizontally off the edge of a tabletop that is \(1.20 \mathrm{~m}\) high. It strikes the floor at a point \(1.52 \mathrm{~m}\) horizontally away from the edge of the table. (a) How long is the ball in the air? (b) What is its speed at the instant it leaves the table?

Two Seconds Later Two seconds after being projected from ground level, a projectile is displaced \(40 \mathrm{~m}\) horizontally and \(53 \mathrm{~m}\) vertically above its point of projection. What are the (a) horizontal and (b) vertical components of the initial velocity of the projectile? (c) At the instant the projectile achieves its maximum height above ground level, how far is it displaced horizontally from its point of projection?

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