/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 The famous twin paradox is often... [FREE SOLUTION] | 91Ó°ÊÓ

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The famous twin paradox is often introduced as follows: Two identical twins grow up together on Earth. When they reach adulthood, one twin zooms to a distant star and returns to find her stay-at-home sister much older than she is. Thus far no paradox. But Alexis Allen formulates the Twin Paradox for us: "The theory of special relativity tells us that all motion is relative. With respect to the traveling twin, the Earth-bound twin moves away and then returns. Therefore it is the Earthbound twin who should be younger than the 'traveling' twin. But when they meet again at the same place, it cannot possibly be that each twin is younger than the other twin. This Twin Paradox disproves relativity." The paradox is usually resolved by realizing that the traveling twin turns around. Everyone agrees which twin turns around, since the reversal of direction slams the poor traveler against the bulkhead of the decelerating starship, breaking her collarbone. The turnaround, evidenced by the broken collarbone, destroys the symmetry required for the paradox to hold. Good-bye Twin Paradox! Still, Alexis's father Cyril Allen has his doubts about this resolution of the paradox. "Your solution is extremely unsatisfying. It forces me to ask: What if the retro-rockets malfunction and will not fire at all to slow me down as I approach a distant star a thousand light-years from Earth? Then I cannot even stop at that star, much less turn around and head back to Earth. Instead, I continue moving away from Earth forever at the original constant speed. Does this mean that as I pass the distant star, one thousand light-years from Earth, it is no longer possible to say that I have aged less than my Earth-bound twin? But if not, then I would never have even gotten to the distant star at all during my hundred-year lifetime! Your resolution of the Twin Paradox is insufficient and unsatisfying." Write a half-page response to Cyril Allen, answering his objections politely but decisively.

Short Answer

Expert verified
Time dilation causes the traveling twin to age less even if she never returns, maintaining the differential aging as predicted by special relativity.

Step by step solution

01

Introduce Relativity

Explain the principle of special relativity, which states that the laws of physics are the same in all inertial frames of reference and that the speed of light is constant in a vacuum.
02

Define Time Dilation

Describe time dilation, the phenomenon in special relativity where a clock moving relative to an observer will be measured to tick slower than a clock at rest with respect to that observer.
03

Apply Time Dilation to the Traveling Twin

Explain how the traveling twin experiences time more slowly during her journey compared to the Earth-bound twin due to her high velocity, using the time dilation formula: \[ \tau = \frac{t}{\text{Lorentz factor}} = \frac{t}{\frac{1}{\beta}\text{arccosh}(\beta L)} = t \times \text{cosh} (v/c) \ \beta = v/c = \text{velocity of traveler/ speed of light} \]
04

Address Asymmetry and Turnaround

Clarify that the asymmetry in the situation is due to the turnaround or acceleration phase experienced by the traveling twin. While the Earth-bound twin remains in an inertial frame, the traveling twin does not, as she must accelerate to turn around. This phase of acceleration is what breaks the symmetry.
05

Discuss Constant Velocity Without Turnaround

Answer Cyril's hypothetical scenario by explaining that if the twin continues travelling at a constant velocity and never turns around (i.e., never decelerates/accelerates to come back), the comparison relies solely on time dilation effects due to their constant velocity relative to Earth. The traveling twin will always experience less passage of time compared to the Earth-bound twin due to this constant high speed.
06

Conclusion

Conclude that as long as the relative velocity remains the same, time dilation continues to apply. Hence, even if the traveling twin continues moving away, she ages less compared to the Earth-bound twin. The turnaround is not necessary to show differential aging; continuous high-speed travel is sufficient.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
Special relativity is a theory proposed by Albert Einstein in 1905. It revolutionized our understanding of physics by introducing two key principles: the laws of physics are the same in all inertial frames of reference, and the speed of light in a vacuum is constant for all observers, regardless of their motion.
The importance of this theory cannot be overstated. It challenged classical mechanics and introduced concepts like time dilation and length contraction. In the context of the twin paradox, special relativity helps us understand why the traveling twin ages more slowly than the Earth-bound twin. Their experiences of time differ due to their relative motion, as described by the laws of relativity.
Time Dilation
Time dilation is a fascinating phenomenon predicted by special relativity. It states that a clock moving relative to an observer will be measured to tick slower than a clock at rest with respect to that observer.
Think of it this way: if you watch a fast-moving spaceship with a clock on board, you would see its clock ticking more slowly than your own. This effect becomes significant at speeds approaching the speed of light. The formula used to describe time dilation is: \[\tau = \frac{t}{\text{Lorentz factor}} = \frac{t}{\frac{1}{\beta}\text{arccosh}(\beta L)} = t \times \text{cosh}(\frac{v}{c})\] where \(\beta = \frac{v}{c}\) is the velocity of the traveler divided by the speed of light.
In the twin paradox, the traveling twin experiences time dilation because she is moving at a high speed relative to her Earth-bound sister, making her age more slowly.
Inertial Frame of Reference
An inertial frame of reference is a perspective where an object is either at rest or moving at a constant velocity. No acceleration is involved. According to special relativity, the laws of physics hold true in all inertial frames.
This concept is crucial for understanding the twin paradox. The Earth-bound twin remains in an inertial frame throughout, experiencing no acceleration. In contrast, the traveling twin experiences a change in motion when she turns around to return to Earth. This shift means she is no longer in a purely inertial frame, which contributes to the differences in aging between the twins.
Asymmetry in Relativity
The key to resolving the twin paradox lies in the asymmetry between the twins' experiences. The traveling twin undergoes acceleration and deceleration when she changes direction, unlike her Earth-bound sibling.
This asymmetry breaks the otherwise symmetrical situation posited by Alexis Allen. The Earth-bound twin's timeline remains purely inertial, while the traveling twin's involves complex phases of acceleration. This difference is crucial for understanding why the traveling twin ages more slowly. The acceleration phase introduces a non-inertial component to her journey, disrupting the supposed symmetry. Therefore, the paradox is resolved once we recognize this asymmetrical aspect of their experiences.
Lorentz Factor
The Lorentz factor is a mathematical expression used in special relativity. It describes how much time, length, and relativistic mass change for an object moving at a significant fraction of the speed of light.
The factor is defined as: \[\text{Lorentz factor} = \frac{1}{\text{arccosh}(\beta L)} = \text{cosh}(\frac{v}{c})\]\br>where \(\beta = \frac{v}{c}\).
In simpler terms, the Lorentz factor quantifies the effects of time dilation and length contraction. For the twin paradox, it helps calculate the difference in aging between the twins based on their relative velocities. The higher the velocity of the traveling twin, the greater the Lorentz factor, and therefore, the more pronounced the time dilation effect.

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Most popular questions from this chapter

The half-life of stationary muons is measured to be \(1.6\) microseconds. Half of any initial number of stationary muons decays in one half-life. Cosmic rays colliding with atoms in the upper atmosphere of the Earth create muons, some of which move downward toward the Earth's surface. The mean lifetime of high- speed muons in one such burst is measured to be 16 microseconds. (a) Find the speed of these muons relative to the Earth. (b) Moving at this speed, how far will the muons move in one half-life? (c) How far would this pulse move in one half-life if there were no relativistic time stretching? (d) In the relativistic case, how far will the pulse move in 10 half-lives? (e) An initial pulse consisting of \(10^{8}\) muons is created at a distance above the Earth's surface given in part (d). How many will remain at the Earth's surface? Assume that the pulse moves vertically downward and none are lost to collisions. (Ninety-nine percent of the Earth's atmosphere lies below \(40 \mathrm{~km}\) altitude.)

Review Problem 40 , in which we concluded that a limo of proper length \(30 \mathrm{~m}\) can fit into a garage of proper length \(6 \mathrm{~m}\) with room to spare. This result is possible because the speeding limo is observed by Garageman to be Lorentz -contracted. Carman protests that in the rest frame of the limo (in which the limo is its full proper length) it is the garage that is Lorentz-contracted. As a result, he claims, there is no possibility whatever that the limo can fit into the garage. What could be the possible basis for resolving this paradox? (Hint: Think about the space and time locations of two events: event A, front garage door closes and event \(\mathrm{B}\), rear garage door opens.)

A meter stick lies at rest in the rocket frame and makes an angle \(\phi^{\prime}\) with the \(x^{\prime}\) axis as measured by the rocket observer. The laboratory observer measures the \(x\) - and \(y\) -components of the meter stick as it streaks past. From these components the laboratory observer computes the angle \(\phi\) that the stick makes with his \(x\) axis. (a) Find an expression for the angle \(\phi\) in terms of the angle \(\phi^{\prime}\) and the relative speed \(v^{\text {rel }}\) between rocket and laboratory frames. (b) What is the length of the "meter" stick measured by the laboratory observer? (c) Optional: Why is your expression in part (a) different from equations derived in Problems 34 and \(35 ?\)

An aspirin tablet contains 5 grains of aspirin (medicinal unit), which is equal to \(325 \mathrm{mg}\). For how many kilometers would the energy equivalent of this mass power an automobile? Assume \(12.75 \mathrm{~km} / \mathrm{L}\) and a heat of combustion of \(3.65 \times 10^{7} \mathrm{~J} / \mathrm{L}\) for the gasoline used in the automobile.

Quite apart from effects due to the Earth's rotational and orbital motion, a laboratory reference frame on the Earth is not an inertial frame, as required by a strict interpretation of special relativity. It is not inertial because a particle released from rest at the Earth's surface does not remain at rest; it falls! Often, however, the events in an experiment for which one needs special relativity happen so quickly that we can ignore effects duc to gravitational accclcration. Considcr, for cxamplc, a proton moving horizontally at speed \(v=0.992 c\) through a 10 -m-wide detector in a laboratory test chamber. (a) How long will the transit through that detector take? (b) How far does the proton fall vertically during this time lapse? (c) What do you conclude about the suitability of the laboratory as an inertial frame in this case?

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