/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 A pulse of protons arrives at de... [FREE SOLUTION] | 91Ó°ÊÓ

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A pulse of protons arrives at detector \(\mathrm{D}\), where you are standing. Prior to this, the pulse passed through detector C, which lies 60 meters upstream. Detector C sent a light flash in your direction at the same instant that the pulse passed through it. At detector D you receive the light flash and the proton pulse separated by a time of 2 nanoseconds \(\left(2 \times 10^{-9} \mathrm{~s}\right)\). What is the speed of the proton pulse?

Short Answer

Expert verified
The speed of the proton pulse is approximately \(2.97 \times 10^8 \) meters per second.

Step by step solution

01

Understand the Problem

Two events are being observed: the proton pulse passing through detector D and the light flash reaching you from detector C. The time difference between these two events is 2 nanoseconds. The task is to find the speed of the proton pulse.
02

Recognize the Speed of Light

Light travels at a speed approximately equal to \( c = 3 \times 10^8 \) meters per second. The detectors are separated by 60 meters, so the light flash travels this distance.
03

Calculate the Time for Light to Travel 60 Meters

The time \( t_{light} \) it takes for the light flash to travel 60 meters can be found using the formula \( t = \frac{d}{v} \). \[ t_{light} = \frac{60 \, \text{meters}}{3 \times 10^8 \, \text{meters per second}} = 2 \times 10^{-7} \, \text{seconds} \].
04

Determine the Time for Proton Pulse to Travel 60 Meters

Given that the light flash arrives 2 nanoseconds before the proton pulse, the total time \( t_{proton} \) taken by the proton pulse can be found by adding this additional time to the light travel time. \[ t_{proton} = t_{light} + 2 \times 10^{-9} \, \text{seconds} = 2 \times 10^{-7} \, \text{seconds} + 2 \times 10^{-9} \, \text{seconds} = 2.02 \times 10^{-7} \, \text{seconds} \].
05

Calculate the Speed of the Proton Pulse

Using the formula \( v = \frac{d}{t} \) to calculate the speed of the proton pulse: \[ v_{proton} = \frac{60 \, \text{meters}}{2.02 \times 10^{-7} \, \text{seconds}} \approx 2.97 \times 10^8 \text{meters per second} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

light speed
Light speed is a fundamental constant in physics. It's the rate at which light travels through a vacuum, approximately equal to 299,792,458 meters per second. For simplicity, this value is often approximated to \(c = 3 \times 10^8 \text{ meters per second}\). Understanding light speed is crucial because many physics problems assume light travels instantaneously due to its very high speed, but this is not always the case. The immense speed of light allows us to measure and compare the speed of other particles, such as a proton pulse in this exercise. To fully grasp the concept of light speed, remember that it represents the upper limit for how fast information or matter can travel in the universe.
time calculation
Time calculation in physics often involves determining how long an event takes to occur. In our problem, we calculated the time taken by light and the proton pulse to travel a specific distance. The formula \(t = \frac{d}{v}\), where \(t\) is time, \(d\) is distance, and \(v\) is velocity, is fundamental for such calculations. For instance, to find how long it takes light to travel 60 meters, we used the formula: \[ t_{\text{light}} = \frac{60 \text{ meters}}{3 \times 10^8 \text{ meters per second}} = 2 \times 10^{-7} \text{ seconds} \]. Calculating time precisely helps in understanding events' sequence and velocity relations in physics problems.
distance and velocity relation
The relation between distance and velocity is a cornerstone in physics problem-solving. Velocity (or speed) is defined as the distance traveled over time, expressed mathematically as \(v = \frac{d}{t}\). This relation helps us solve problems where either distance or time is known, and the other needs to be found. In our exercise, the proton pulse's speed was calculated using the formula: \[v_{\text{proton}} = \frac{60 \text{ meters}}{2.02 \times 10^{-7} \text{ seconds}} \approx 2.97 \times 10^8 \text{ meters per second} \]. Understanding this relationship allows you to switch easily between different variables to find unknowns and verify the consistency of your results.
physics problems
Physics problems often require understanding and applying basic principles to real-world scenarios. Breaking down these problems into simpler steps can help. For example, in calculating the speed of a proton pulse, we first identified the given data and what we needed to find. Next, knowing the speed of light (\(c = 3 \times 10^8 \text{ meters per second}\)), helped us determine the time light travels 60 meters and then the additional time difference to find the proton pulse's time. Finally, using \(v = \frac{d}{t}\) helped calculate the proton pulse's speed. Such organized problem-solving approaches are essential in tackling more complex physics problems systematically and accurately.

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Most popular questions from this chapter

You wish to make \(a\) round trip from Earth in a spaceship, traveling at constant speed in a straight line for 6 months on your watch and then returning at the same constant speed. You wish, further, to find Earth to be 1000 years older on your return. (a) What is the value of your constant speed with respect to Earth? (b) How much do you age during the trip? (c) Does it matter whether or not you travel in a straight line? For example, could you travel in a huge circle that loops back to Earth?

A spaceship moving away from Earth at a speed \(0.900 c\) radios its reports back to Earth using a frequency of 100 MHz measured in the spaceship frame. To what frequency must Earth's receivers be tuned in order to receive the reports?

A spaceship of rest length \(100 \mathrm{~m}\) passes a laboratory timing station in \(0.2\) microseconds measured on the timing station clock. (a) What is the speed of the spaceship in the laboratory frame? (b) What is the Lorentz-contracted length of the spaceship in the laboratory frame?

You and a group of female and male friends stand outdoors at dusk watching the Sun set and noticing the planet Venus in the same direction as the Sun. An alien ship lands beside you at the same instant that you see the Sun explode. The aliens admit that earlier they shot a laser flash at the Sun, which caused the explosion. They warn that the Sun's explosion emitted an immense pulse of particles that will blow away Earth's atmosphere. In confirmation, a short time after the aliens land you notice Venus suddenly change color. You and your friends plead with the aliens to take your group away from Earth in order to establish the human gene pool elsewhere. They agree. Describe the conditions under which your escape plan will succeed. Be specific and use numbers. Assume that the Sun is 8 light-minutes from Earth and Venus is 2 light-minutes from Earth.

Identical experiments are carried out (1) in a high-speed train moving at constant speed along a horizontal track with the shades drawn and \((2)\) in a closed freight container on the platform as the train passes. Copy the following list and mark with a "yes" quantities that will necessarily be the same as measured in the two frames. Mark with a "no" quantities that are not necessarily the same as measured in the two frames. (a) The time it takes for light to travel one meter in a vacuum; (b) the kinetic energy of an electron accelerated from rest through a voltage difference of one million volts; (c) the time for half the number of radioactive particles at rest to decay; (d) the mass of a proton; (e) the structure of DNA for an amoeba; (f) Newton's Second Law of Motion: \(F=m a ;(\mathrm{g})\) the value of the downward acceleration of gravity \(g\).

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