/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Astrophysicists describe the red... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Astrophysicists describe the redshift of receding astronomical objects using the redshift factor \(z\), defined implicitly in the following equation: $$ \lambda_{\text {observed }} \equiv(1+z) \lambda_{\text {emitted }} $$ Here \(\lambda_{\text {observed }}\) is the wavelength of light observed from Earth, while \(\lambda_{\text {emitted }}\) is the wavelength of the light emitted from the source as measured in the rest frame of the source. The emitted wavelength is known if one knows the emitting atom, identified from the pattern of different wavelengths characteristic of that atom. Astrophysicists measuring the redshifts of light from extremely remote quasars calculate a \(z\) -factor in the neighborhood of \(z \approx 6 .\) Use the Dopplershift equations of special relativity to determine how fast such quasars are moving away from Earth. Note: Actually, for such distant objects the unmodified Doppler shift formula of special relativity does not apply. Instead, one thinks of the space between Earth and the source expanding as the universe expands; the wavelength of the light expands with this expansion of the universe as it travels from the source quasar to us.

Short Answer

Expert verified
The quasar is moving away from Earth at 0.96 times the speed of light.

Step by step solution

01

Understand Redshift and its Equation

The redshift factor, denoted by \(z\), can be expressed as \(\lambda_{\text{observed}} = (1+z)\lambda_{\text{emitted}}\). For a quasar with a redshift factor of \(z \approx 6\), this implies that the observed wavelength is 7 times the emitted wavelength.
02

Relate Redshift to Velocity

For determining the velocity of the quasar relative to Earth, use the relativistic Doppler shift formula: \[1 + z = \sqrt{\frac{1 + \frac{v}{c}}{1 - \frac{v}{c}}}\]where \(v\) is the velocity of the quasar moving away from Earth, and \(c\) is the speed of light.
03

Substitute Redshift Value

Given \(z = 6\), substitute this value into the Doppler shift equation:\[1 + 6 = \sqrt{\frac{1 + \frac{v}{c}}{1 - \frac{v}{c}}}\]\[7 = \sqrt{\frac{1 + \frac{v}{c}}{1 - \frac{v}{c}}}\]
04

Square Both Sides

Square both sides to eliminate the square root:\[49 = \frac{1 + \frac{v}{c}}{1 - \frac{v}{c}}\]
05

Isolate \(\frac{v}{c}\)

Rearrange to isolate \(\frac{v}{c}\):\[49(1 - \frac{v}{c}) = 1 + \frac{v}{c}\]\[49 - 49\frac{v}{c} = 1 + \frac{v}{c}\]
06

Combine Like Terms

Combine like terms to solve for \(\frac{v}{c}\):\[49 - 1 = 49\frac{v}{c} + \frac{v}{c}\]\[48 = 50\frac{v}{c}\]\[\frac{v}{c} = \frac{48}{50} = 0.96\]
07

Calculate the Velocity

Multiply both sides by \(c\) to find the velocity \(v\):\[v = 0.96c\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

relativistic Doppler shift
The relativistic Doppler shift comes into play when objects moving at speeds close to the speed of light emit or reflect light. When we observe such objects, like quasars, their light appears shifted to different wavelengths due to their high velocities. The shift can be towards the blue end (blueshift) if the object is moving closer to us or towards the red end (redshift) if it is moving away from us.
quasars
Quasars are incredibly luminous objects powered by supermassive black holes at the centers of distant galaxies. They emit immense amounts of energy, often outshining their entire host galaxies. Because of their brightness and distance, studying quasars allows astrophysicists to understand the universe's early stages and the behavior of matter under extreme conditions. The light we observe from quasars has often traveled billions of years to reach us.
speed of light
The speed of light, denoted by the symbol \(c\), is a fundamental constant in physics. It is the speed at which light and all other electromagnetic waves travel in a vacuum, approximately 299,792 kilometers per second (km/s). This speed forms the basis for many equations in relativity, including the Doppler shift formulas used to determine the velocities of distant astronomical objects.
expansion of the universe
The universe has been expanding since the Big Bang. This expansion means that galaxies and other distant objects are moving away from us. The more distant an object is, the faster it seems to move away. This phenomenon is captured in Hubble's Law, which states that the velocity at which a galaxy recedes is proportional to its distance from us. The expanding universe also stretches the light traveling through it, causing redshift as the wavelength of the light increases over time.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Quite apart from effects due to the Earth's rotational and orbital motion, a laboratory reference frame on the Earth is not an inertial frame, as required by a strict interpretation of special relativity. It is not inertial because a particle released from rest at the Earth's surface does not remain at rest; it falls! Often, however, the events in an experiment for which one needs special relativity happen so quickly that we can ignore effects duc to gravitational accclcration. Considcr, for cxamplc, a proton moving horizontally at speed \(v=0.992 c\) through a 10 -m-wide detector in a laboratory test chamber. (a) How long will the transit through that detector take? (b) How far does the proton fall vertically during this time lapse? (c) What do you conclude about the suitability of the laboratory as an inertial frame in this case?

One kilogram of hydrogen combines chemically with 8 kilograms of oxygen to form water; about \(10^{8} \mathrm{~J}\) of energy is released. Ten metric tons \(\left(10^{4} \mathrm{~kg}\right)\) of hydrogen combines with oxygen to produce water. (a) Does the resulting water have a greater or less mass than the original hydrogen plus oxygen? (b) What is the numerical magnitude of this difference in mass? (c) A smaller amount of hydrogen and oxygen is weighed, then combined to form water, which is weighed again. A very good chemical balance is able to detect a fractional change in mass of 1 part in \(10^{8}\). By what factor is this sensitivity more than enough -or insufficient - to detect the fractional change in mass in this reaction?

(a) Find an equation for the unknown mass \(m\) of a particle if you know its momentum \(p\) and its kinetic energy \(K\). Show that this expression reduces to an expected result for nonrelativistic particle speeds. (b) Find the mass of a particle whose kinetic energy is \(K=55.0 \mathrm{MeV}\) and whose momentum is \(p=\) \(121 \mathrm{MeV} / \mathrm{c}\). Express your answer as a decimal fraction or multiple of the mass \(m_{\mathrm{e}}\) of the electron.

Galaxy A is measured to be receding from us on Earth with a speed of \(0.3 c .\) Galaxy \(\mathrm{B}\), located in precisely the opposite direction, is also receding from us at the same speed. What recessional velocity will an observer on galaxy A measure (a) for our galaxy, and (b) for galaxy B?

An unpowered rocket moves past you in the positive \(x\) direction at speed \(v^{\text {rel }}=0.9 c\). This rocket fires a bullet out the back that you measure to be moving at speed \(v_{\text {bullet }}=0.3 c\) in the positive \(x\) direction. With what speed relative to the rocket did the rocket observer fire the bullet out the back of her ship?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.