/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Find Sum Find the sum \(y\) of t... [FREE SOLUTION] | 91Ó°ÊÓ

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Find Sum Find the sum \(y\) of the following quantities: $$ y_{1}=0 \sin \omega t \text { and } y_{2}=8.0 \sin \left(\omega t+30^{\circ}\right) \text { . } $$

Short Answer

Expert verified
The sum \( y = 8.0 \sin (\omega t + 30^\circ) \).

Step by step solution

01

- Understanding the given quantities

Identify the given quantities: - The first quantity is given as: \( y_1 = 0 \sin \omega t \). - The second quantity is given as: \( y_2 = 8.0 \sin (\omega t + 30^\circ) \).
02

- Simplify the given quantities

Since \( y_1 = 0 \sin \omega t \), we can simplify this because any number multiplied by 0 is 0: \( y_1 = 0 \).
03

- Evaluate the sum

To find the sum \( y \) of the quantities: \[ y = y_1 + y_2 \] Substitute the simplified values: \[ y = 0 + 8.0 \sin (\omega t + 30^\circ) \] Thus: \[ y = 8.0 \sin (\omega t + 30^\circ) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sinusoidal functions
Sinusoidal functions are mathematical functions that describe smooth and periodic oscillations. The most common examples are the sine and cosine functions, which are fundamental in trigonometry. These functions are essential in physics because they can model wave-like phenomena, such as sound waves, light waves, and other harmonic oscillations.

For example, the function: \[ y(t) = A \sin(\omega t + \phi) \] represents a sinusoidal wave where:
  • \(A\) is the amplitude, which indicates the peak value of the wave.
  • \(\omega\) is the angular frequency, which determines how many oscillations occur in a unit of time.
  • \(\phi\) is the phase, which shifts the wave in time.
In our exercise, we looked at two sinusoidal functions: \[ y_1 = 0 \sin \omega t \text { and } y_2 = 8.0 \sin (\omega t + 30^\circ) \] Understanding how these functions work helps to solve problems involving waves and oscillations.
phase shift
A phase shift in a sinusoidal function refers to a horizontal shift of the wave along the time axis. It is represented by the term added to or subtracted from the angle in the sine or cosine function. In mathematical terms, if we have a function: \[ y(t) = A \sin(\omega t + \phi) \]
  • \(\phi\) denotes the phase shift.
This phase shift \((\phi)\) affects where the wave starts at \(t = 0\). For instance, if \(\phi = 30^\circ\), the entire sine wave shifts by 30 degrees to the left. In our given problem, the second quantity \[ y_2 = 8.0 \sin (\omega t + 30^\circ) \] has a phase shift of \(30^\circ\). Understanding phase shift is crucial in scenarios where timing and synchronization of waves are important, like in signal processing and alternating current circuits.
superposition principle
The superposition principle states that when two or more waves overlap in space, the resultant wave is the algebraic sum of the individual waves. This principle is essential in understanding wave phenomena such as interference, diffraction, and beats.

For example, if two sinusoidal waves are given by: \[ y_1 = A_1 \sin(\omega t + \phi_1) \text { and } y_2 = A_2 \sin( (\omega t + \phi_2)) \] the resultant wave \( y_\text {res}\) is: \[ y_\text {res} = y_1 + y_2 \]

In the exercise:

\[ y_1 = 0 \sin \omega t, \ y_2 = 8.0 \sin (\omega t + 30^\circ) \]
Consequently, the sum can be simplified as: \[ y = y_1 + y_2 = 0 + 8.0 \sin(\omega t + 30^\circ) = 8.0 \sin(\omega t + 30^\circ) \] This outcome illustrates the superposition principle, showing how the individual contributions of waves combine to form a resultant wave. Understanding this helps in various fields such as acoustics, optics, and electromagnetic theory.

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Most popular questions from this chapter

Mica Flake A thin flake of mica \((n=1.58)\) is used to cover one slit of a double-slit interference arrangement. The central point on the viewing screen is now occupied by what had been the seventh bright side fringe \((m=7)\) before the mica was used. If \(\lambda=550 \mathrm{~nm}\), what is the thickness of the mica? (Hint: Consider the wavelength of the light within the mica.)

Soap Film Two The reflection of perpendicularly incident white light by a soap film in air has an interference maximum at \(600 \mathrm{~nm}\) and a minimum at \(450 \mathrm{~nm}\), with no minimum in between. If \(n=\) \(1.33\) for the film, what is the film thickness, assumed uniform?

Coat Glass We wish to coat flat glass \((n=1.50)\) with a transparent material \((n=1.25)\) so that reflection of light at wavelength \(600 \mathrm{~nm}\) is eliminated by interference. What minimum thickness can the coating have to do this?

Radio Frequency Sources Two radio-frequency point sources separated by \(2.0 \mathrm{~m}\) are radiating in phase with \(\lambda=0.50 \mathrm{~m}\). A detector moves in a circular path around the two sources in a plane containing them. Without written calculation, find how many maxima it detects.

Newtons's Rings One In a Newton's rings experiment (see Problem 49), the radius of curvature \(R\) of the lens is \(5.0 \mathrm{~m}\) and the lens diameter is \(20 \mathrm{~mm}\). (a) How many bright rings are produced? Assume that \(\lambda=589 \mathrm{~nm}\). (b) How many bright rings would be produced if the arrangement were immersed in water \((n=1.33)\) ?

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