/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 The index of refraction of benze... [FREE SOLUTION] | 91Ó°ÊÓ

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The index of refraction of benzene is \(1.8\). What is the critical angle for a light ray traveling in benzene toward a plane layer of air above the benzene?

Short Answer

Expert verified
The critical angle is approximately 33.69°.

Step by step solution

01

- Understand the Concept of Critical Angle

The critical angle is the angle of incidence above which total internal reflection occurs. This can be calculated using the refractive index of the two media involved.
02

- Use Snell's Law

Apply Snell's Law which states: \[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \] Here, the light is moving from benzene to air, so \( n_1 = 1.8 \) (benzene) and \( n_2 = 1.0 \) (air).
03

- Set Up the Equation for Critical Angle

The critical angle \( \theta_c \) occurs when \( \theta_2 = 90^\text{°} \). Using Snell's Law, this becomes: \[ 1.8 \sin( \theta_c ) = 1.0 \sin(90^\text{°}) \] since \( \sin(90^\text{°}) = 1 \), the equation simplifies to: \[ 1.8 \sin( \theta_c ) = 1.0 \]
04

- Solve for the Critical Angle

Solving for \( \theta_c \): \[ \sin( \theta_c ) = \frac{1.0}{1.8} \] Then take the inverse sine (arcsin) of both sides: \[ \theta_c = \arcsin \left( \frac{1}{1.8} \right) \]
05

- Calculate the Value

Using a calculator, determine the arcsin value: \[ \theta_c \approx \arcsin(0.5556) \approx 33.69^\text{°} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Snell's Law
Snell's Law is a fundamental principle in optics. It explains how light rays change direction when passing through different media.
The law is expressed as: ewline $$ n_1 \, \sin(\theta_1) = n_2 \, \sin(\theta_2) $$ewline Here, ewline - \( n_1 \) and \( n_2 \) are the refractive indices of medium 1 and medium 2 respectively.
- \( \theta_1 \) and \( \theta_2 \) are the angles of incidence (incoming light) and refraction (bending light) respectively.
When light travels from a denser medium to a less dense medium (like from water to air), it bends away from the normal. For example, light moving from benzene (\( n_1 = 1.8 \)) to air (\( n_2 = 1.0 \)) will bend away.
This principle is crucial in understanding phenomena like total internal reflection, and is used to calculate critical angles.
Index of Refraction
The index of refraction (or refractive index) indicates how much a material can bend light. It's the ratio of the speed of light in a vacuum to its speed in the material.ewline It's given as: ewline $$ n = \frac{c}{v} $$ewline Where, ewline - \( c \) is the speed of light in a vacuum.ewline - \( v \) is the speed of light in the material.ewline A higher index means light travels slower in that material. For instance, benzene has an index of 1.8, showing light travels slower in benzene compared to air (index 1.0). This difference plays a key role in calculating critical angles and understanding light behavior in different substances.
Total Internal Reflection
Total internal reflection is an optical phenomenon where light fails to exit a medium and is entirely reflected back inside. This happens when light moves from a denser to a less dense medium at an angle greater than a specific 'critical angle'.
Beyond this angle, instead of refracting out, the light reflects internally.
This principle is used in fiber optics, allowing light to travel through cables without escaping. In our exercise, calculating the critical angle for benzene illustrates this concept by determining the threshold at which light stays within the benzene rather than passing into the air.
Arcsin Function
The arcsin function is the inverse of the sine function. It's used to find angles when the sine of the angle is known.\( \arcsin(x) \) finds the angle whose sine is \( x \).
In our calculation, ewline $$ \theta_c = \arcsin(0.5556) $$ewline Solves for the critical angle \( \theta_c \). Utilizing a calculator to find ewline $$ \arcsin(0.5556) \approx 33.69^\text{\°} $$ewline This gives us the critical angle for benzene moving into air. Understanding how to use the arcsin function allows you to solve for unknown angles in trigonometry and physics problems related to wave behaviors.
Angle of Incidence
The angle of incidence is the angle between the incoming light ray and a perpendicular line to the surface it hits (the normal).
This angle is pivotal in determining how light interacts with different materials.
In our exercise, the incidence angle is used in conjunction with the critical angle.
If this angle exceeds the critical angle, total internal reflection occurs, preventing light from passing into the less dense medium. Understanding and measuring the angle of incidence is essential in fields like optics, photography, and even astronomy, impacting how we design lenses and other optical devices.

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Most popular questions from this chapter

A movie camera with a (single) lens of focal length \(75 \mathrm{~mm}\) takes a picture of a \(180-\mathrm{cm}\) -high person standing \(27 \mathrm{~m}\) away. What is the height of the image of the person on the film?

In about A.D. 150 , Claudius Ptolemy gave the following measured values for the angle of incidence \(\theta_{1}\) and the angle of refraction \(\theta_{2}\) for a light beam passing from air to water: $$\begin{array}{cc|cc} \hline \boldsymbol{\theta}_{\mathbf{1}} & \boldsymbol{\theta}_{\mathbf{2}} & \boldsymbol{\theta}_{\mathbf{1}} & \boldsymbol{\theta}_{\mathbf{2}} \\ \hline 10^{\circ} & 8^{\circ} 00^{\prime} & 50^{\circ} & 35^{\circ} 00^{\prime} \\ 20^{\circ} & 15^{\circ} 30^{\prime} & 60^{\circ} & 45^{\circ} 30^{\prime} \\ 30^{\circ} & 22^{\circ} 30^{\prime} & 70^{\circ} & 45^{\circ} 30^{\prime} \\ 40^{\circ} & 29^{\circ} 00^{\prime} & 80^{\circ} & 50^{\circ} 00^{\prime} \\ \hline \end{array}$$ (a) Are these data consistent with the law of refraction? (b) If so, what index of refraction results? These data are interesting as perhaps the oldest recorded physical measurements.

Light in vacuum is incident on the surface of a glass slab. In the vacuum the beam makes an angle of \(32.0^{\circ}\) with the normal to the surface, while in the glass it makes an angle of \(21.0^{\circ}\) with the normal. What is the index of refraction of the glass?

Address each part of this question in two ways: (1) by drawing and interpreting appropriate geometrical diagrams and (2) by appealing to the lens equation and the expression for lateral magnification and demonstrating your result mathematically. If your two approaches do not agree, explain which one is correct and why the other is wrong. (a) Suppose you are using a camera and wish to have a larger image of a distant object than you are obtaining with the lens currently in use. Would you change to a lens with a longer or a shorter focal length? Explain your reasoning. (Hint: Note that the object distance is essentially fixed.) (b) Suppose you are using a slide projector and wish to obtain a larger image on the screen. You cannot achieve this by moving the screen farther from the projector because you are already using the entire length of the room. Would you change to a lens with a longer or a shorter focal length than the one you are using? Explain your reasoning. (Hint: Note that the image distance is essentially fixed.)

When a T. rex pursues a jeep in the movie Jurassic Park, we see a reflected image of the (very large) T. rex via a side-view mirror, on which is printed the (then darkly humorous) warning: "Objects in mirror are closer than they appear." Is the mirror flat, convex, or concave? Why do you think so?

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