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The magnetic component of an electromagnetic wave in vacuum has an amplitude of \(85.8 \mathrm{nT}\) and an angular wave number of \(4.00 \mathrm{~m}^{-1}\). What are (a) the frequency of the wave, (b) the rms value of the electric component, and (c) the intensity of the light?

Short Answer

Expert verified
(a) 1.91 × 10^8 Hz; (b) 18.2 V/m; (c) 8.74 W/m²

Step by step solution

01

- Find the frequency using the angular wave number

The angular wave number is given by \[ k = \frac{2 \pi}{\lambda} \]and is related to the velocity of the wave by\[ k = \frac{2 \pi f}{c} \]Where:\(k = 4.00 \mathrm{~m}^{-1}\)\(c = 3.00 \times 10^8 \mathrm{~m/s}\)Rearrange to solve for frequency \(f\):\[ f = \frac{k c}{2 \pi} \]Substitute the known values:\[ f = \frac{4.00 \times 3.00 \times 10^8}{2 \pi} \approx 1.91 \times 10^8 \text{ Hz} \]
02

- Calculate the RMS value of the electric component

The peak magnetic field is given by \(B_0 = 85.8 \text{ nT} = 85.8 \times 10^{-9} \text{ T}\).The peak electric field is related to the peak magnetic field by\[ E_0 = c B_0 \]Substituting the values:\[ E_0 = 3.00 \times 10^8 \times 85.8 \times 10^{-9} = 25.7 \text{ V/m} \]The RMS value of the electric field is given by\[ E_\text{rms} = \frac{E_0}{\sqrt{2}} \]Thus,\[ E_\text{rms} = \frac{25.7}{\sqrt{2}} \approx 18.2 \text{ V/m} \]
03

- Calculate the intensity of the light

The intensity of the electromagnetic wave can be calculated using the formula:\[ I = \frac{1}{2} c \epsilon_0 E_0^2 \]Where:\(c = 3.00 \times 10^8 \text{ m/s}\)\(\epsilon_0 = 8.85 \times 10^{-12} \text{ F/m}\)\(E_0 = 25.7 \text{ V/m}\)Substitute the values:\[ I = \frac{1}{2} \times 3.00 \times 10^8 \times 8.85 \times 10^{-12} \times (25.7)^2 \]Calculate the value:\[ I \approx 8.74 \text{ W/m}^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency Calculation
The frequency of an electromagnetic wave in vacuum is directly related to its angular wave number. The wave number, denoted as \( k \), is the spatial frequency of the wave and is calculated by dividing \( 2 \pi \) by the wavelength \( \lambda \). In this problem, the wave number \( k \) is given as \( 4.00 \text{ m}^{-1} \). By using the relationship \[ k = \frac{2 \pi f}{c} \], where \( c \) is the speed of light in a vacuum (\( 3.00 \times 10^8 \text{ m/s} \)), we can solve for the frequency \( f \).
Rearrange the equation to get:
\[ f = \frac{k c}{2 \pi} \]
Substituting the given values:
\[ f = \frac{4.00 \times 3.00 \times 10^8}{2 \pi} \approx 1.91 \times 10^8 \text{ Hz} \]
This frequency represents how many oscillations the wave completes per second.
Electric Field RMS
The root mean square (RMS) value of the electric field component of an electromagnetic wave is an important measure that reflects the field's effective value. First, we need to determine the peak electric field \( E_0 \) using the given peak magnetic field \( B_0 \). The given value is \( 85.8 \text{ nT} = 85.8 \times 10^{-9} \text{ T} \). The relationship between the peak electric and magnetic fields in vacuum is \[ E_0 = c B_0 \]
Substituting the known values:
\[ E_0 = 3.00 \times 10^8 \times 85.8 \times 10^{-9} = 25.7 \text{ V/m} \]
To find the RMS value, we use the formula:
\[ E_{\text{rms}} = \frac{E_0}{\sqrt{2}} \]
Substituting \( E_0 \):
\[ E_{\text{rms}} = \frac{25.7}{\sqrt{2}} \approx 18.2 \text{ V/m} \]
This RMS value is crucial for calculating other properties, such as the intensity of the light.
Intensity of Light
The intensity of an electromagnetic wave represents the energy per unit area per unit time that the wave carries. It can be calculated using the peak electric field \( E_0 \). The formula for the intensity \( I \) of light is:
\[ I = \frac{1}{2} c \epsilon_0 E_0^2 \]
where \( \epsilon_0 \) is the permittivity of free space \( 8.85 \times 10^{-12} \text{ F/m} \).
Using the given values:
\[ I = \frac{1}{2} \times 3.00 \times 10^8 \times 8.85 \times 10^{-12} \times (25.7)^2 \]
Compute the value to find:
\[ I \approx 8.74 \text{ W/m}^2 \]
This intensity value tells us the power of the wave spread over a specific area, which is fundamental in understanding the energy dynamics of electromagnetic waves.

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