/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Small Charged Sphere A small, ch... [FREE SOLUTION] | 91Ó°ÊÓ

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Small Charged Sphere A small, charged sphere of mass \(5.0 \mathrm{~g}\) is released \(32 \mathrm{~cm}\) away from a fixed point charge of \(+5.0 \times 10^{-9} \mathrm{C}\). Immediately after release, the sphere is observed to accelerate toward the charge at \(2.5 \mathrm{~m} / \mathrm{s}^{2}\). What is the charge on the sphere? Hint: The force of gravity can be ignored in your calculation.

Short Answer

Expert verified
2.84 × 10^{-12} C

Step by step solution

01

Identify Given Values

Identify all given values from the problem. The mass of the small charged sphere is given as 5.0 g (or 0.005 kg), the distance between the sphere and charge is 32 cm (or 0.32 m), the point charge is +5.0 × 10^{-9} C, and the acceleration is 2.5 m/s².
02

Use Newton's Second Law

According to Newton's Second Law, the force acting on the sphere is given by: \[ F = m \times a \] Substitute the given values for mass and acceleration: \[ F = 0.005 \text{ kg} \times 2.5 \text{ m/s}^2 \] Compute the force: \[ F = 0.0125 \text{ N} \]
03

Use Coulomb's Law

Coulomb's Law describes the force between two charges: \[ F = k \times \frac{|q_1 \times q_2|}{r^2} \] Here, \( k \) is Coulomb's constant (\(8.99 \times 10^9 \text{ N} \text{ m}^2/\text{C}^2 \)), \( q_1 = + 5.0 \times 10^{-9} \text{ C} \), and the distance \( r = 0.32 \text{ m} \).Rearrange to solve for \( q_2 \) (the charge on the sphere): \[ q_2 = \frac{F \times r^2}{k \times q_1} \]
04

Substitute Values into Coulomb's Law

Substitute the known values into the rearranged formula: \[ q_2 = \frac{0.0125 \text{ N} \times (0.32 \text{ m})^2}{8.99 \times 10^9 \text{ N} \text{ m}^2/\text{C}^2 \times 5.0 \times 10^{-9} \text{ C}} \]Compute the result step by step: (0.32 m)^2 = 0.1024 m² Multiply by force: 0.0125 N × 0.1024 m² = 1.28 × 10^{-3} N·m² Divide by product of \( k \) and \( q_1 \): \[ q_2 = \frac{1.28 \times 10^{-3} \text{ N·m²}}{8.99 \times 10^9 \text{ N·m²/C² } \times 5.0 \times 10^{-9} \text{ C}} = 2.84 \times 10^{-12} \text{ C} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law describes the electric force between two point charges. It's defined by the equation:
- \(F = k \times \frac{|q_1 \times q_2|}{r^2} \)
Here:
  • \(F\) is the force between the charges
  • \(k\) is Coulomb's constant, \(8.99 \times 10^9 \text{ N} \text{ m}^2/\text{C}^2\)
  • \(q_1\) and \(q_2\) are the magnitudes of the charges
  • \(r\) is the distance between the charges

This law shows that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In the problem, we used Coulomb's Law to find the unknown charge \(q_2\) by rearranging the formula:
\( q_2 = \frac{F \times r^2}{k \times q_1} \)
First, identify the values:
  • \(F = 0.0125 \text{ N}\)
  • \( r = 0.32 \text{ m}\)
  • \( q_1 = 5.0 \times 10^{-9} \text{ C}\)
Substituting these into the equation gives us \( q_2\), the charge on the small sphere.
Newton's Second Law
Newton's Second Law of Motion provides a critical relationship between force, mass, and acceleration. It states:
- \(F = m \times a\)
Where:
  • \(F\) is the force
  • \(m\) is the mass
  • \(a\) is the acceleration
In our exercise, we applied it to calculate the electric force acting on the charged sphere. We knew the mass \(5.0 \text{ g} \) (or \(0.005 \text{ kg}\)) and the acceleration \(2.5 \text{ m/s}^2\).
By plugging these values into Newton's Second Law:
\(F = 0.005 \text{ kg} \times 2.5 \text{ m/s}^2 = 0.0125 \text{ N}\)
This force is then used in conjunction with Coulomb's Law to find the unknown charge. Newton's Second Law is vital in relating everyday motion phenomena to basic principles, bridging classical mechanics and electromagnetism.
Electric Force
Electric force is a fundamental concept in physics that describes the force between two charges. Derived from Coulomb's Law, the electric force \(F\) depends on:
  • The magnitudes of both charges \(q_1\) and \(q_2\)
  • The distance between the charges \(r\)
  • Coulomb's constant \(k\)

For two charges:
- \(F = k \times \frac{|q_1 \times q_2|}{r^2} \)
In our problem, when the sphere is released and accelerates towards the fixed point charge, the driving force is the electric force. Ignoring gravity makes the calculation straightforward. The electric force causes the acceleration, and by measuring this, we use Coulomb's Law to derive the charge of the sphere.
Note that in the context of the problem, the electric force was essential in creating a measurable acceleration, which through Newton's Second Law, allowed us to back-calculate to find the unknown charge. This illustrates how interconnected and crucial these concepts are in solving physics problems.

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Most popular questions from this chapter

Water Drops Two tiny, spherical water drops, with identical charges of \(-1.00 \times 10^{-16} \mathrm{C}\), have a center-to-center separation of \(1.00 \mathrm{~cm} .\) (a) What is the magnitude of the electrostatic force acting between them? (b) How many excess electrons are on each drop, giving it its charge imbalance?

Cesium Chloride In the basic \(\mathrm{CsCl}\) (cesium chloride) crystal structure, \(\mathrm{Cs}^{+}\) ions form the corners of a cube and a \(\mathrm{Cl}^{-}\) ion is at the cube's center . The edge length of the cube is \(0.40 \mathrm{~nm}\). The \(\mathrm{Cs}^{+}\) ions are each deficient by one electron (and thus each has a charge of \(+e\) ), and the \(\mathrm{Cl}^{-}\) ion has one excess electron (and thus has a charge of \(-e\) ). (a) What is the magnitude of the net electrostatic force exerted on the \(\mathrm{Cl}^{-}\) ion by the eight \(\mathrm{Cs}^{+}\) ions at the corners of the cube? (b) If one of the \(\mathrm{Cs}^{+}\) ions is missing, the crystal is said to have a defect; what is the magnitude of the net electrostatic force exerted on the \(\mathrm{Cl}^{-}\) ion by the seven remaining \(\mathrm{Cs}^{+}\) ions?

A Certain Charge \(Q\) A certain charge \(Q\) is divided into two parts \(q\) and \(Q-q\), which are then separated by a certain distance. What must \(q\) be in terms of \(Q\) to maximize the electrostatic repulsion between the two charges?

Two Fixed Particles Two fixed particles, of charges \(q_{A}=+1.0 \mu \mathrm{C}\) and \(q_{B}=-3.0 \mu \mathrm{C}\), are \(10 \mathrm{~cm}\) apart. How far from each should a third charge be located so that no net electrostatic force acts on it?

Beta Decay In beta decay a massive fundamental particle changes to another massive particle, and either an electron of charge \(-e\) or a positron of charge \(+e\) (positive particle with the same amount of charge and mass as an electron) is emitted. (a) If a proton undergoes beta decay to become a neutron, which particle is emitted? (b) If a neutron undergoes beta decay to become a proton, which particle is emitted?

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