/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Show that when the temperature o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Show that when the temperature of a liquid in a barometer changes by \(\Delta T\) and the pressure is constant, the liquid's height \(h\) changes by \(\Delta h=\beta h \Delta T\), where \(\beta\) is the coefficient of volume expansion. Neglect the expansion of the glass tube.

Short Answer

Expert verified
When the temperature changes by \(\Delta T\), the height changes by \(\Delta h = h\beta \Delta T\).

Step by step solution

01

- Understand the relationship between temperature and volume

The coefficient of volume expansion \(\beta \) expresses how much a substance's volume changes with temperature. The volume change \(\Delta V\) is given by \(\Delta V = V\beta \Delta T.\)
02

- Relate volume change to height change in the barometer

The liquid in the barometer forms a column with height \(h\) and a constant cross-sectional area \(A\). Thus, the volume \(V\) is given by \(V = Ah.\) The change in volume can also be related to the change in height while keeping cross-sectional area constant: \(\Delta V = A \Delta h.\)
03

- Substitute and solve for \(\Delta h\)

Since \(\Delta V = V\beta \Delta T\) and \(\Delta V = A \Delta h,\) equate both expressions: \(A \Delta h = Ah\beta \Delta T \). Divide both sides by \(A\): \(\Delta h = h\beta \Delta T.\)
04

- Conclusion

This shows that when the temperature of the liquid in the barometer changes by \(\Delta T\), the height of the liquid column changes by \(\Delta h = h\beta \Delta T\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Volume Expansion
The coefficient of volume expansion (\beta) is a measure of how the volume of a substance changes as the temperature changes. It shows the sensitivity of the liquid's volume to temperature variations. In mathematical terms, if a liquid has an initial volume V, and the temperature changes by \Delta T, the corresponding change in volume (\Delta V) can be expressed as \( \Delta V = V \beta \Delta T \). This formula tells us that for every degree change in temperature, the volume changes by a fraction of its original volume, which is determined by \beta. For instance, if \beta = 0.001 per degree Celsius, and the temperature increases by 10 degrees, then the volume of the liquid will increase by 1% of its original volume.
Volume and Height Relationship
To grasp the volume-height relationship in a barometer, think of the liquid column as having a constant cross-sectional area A. In this scenario, the volume of the liquid V is given by the product of its height h and the cross-sectional area A, i.e., V = Ah. When the temperature changes, both volume and height change, but the cross-sectional area remains constant. Given that the volume changes with temperature as \( \Delta V = V \beta \Delta T \), we can express this volume change in terms of the corresponding height change \Delta h. Since \Delta V = A \Delta h, we can substitute the relationships into one another to find \Delta h. This results in the equation \( \ \Delta h = h\beta \Delta T \), illustrating how the height of the liquid column in a barometer relates directly to changes in temperature and the coefficient of volume expansion.
Temperature Effects on Liquid Columns
In a barometer, the height of the liquid column is sensitive to temperature changes, reflecting the physical principles of thermal expansion. When the temperature of the liquid increases, the liquid expands. The expansion can be quantified using the coefficient of volume expansion (\beta), governing how the liquid's height changes. For a constant pressure scenario assumed in the barometer, as the temperature goes up or down by \Delta T, the height change \Delta h of the liquid column is given by \( \Delta h = h\beta \Delta T \). This relationship underscores a direct link between the height variation of the liquid column and temperature shifts. In essence, a higher temperature results in a longer column, while a drop in temperature shortens it, assuming the pressure is constant. This principle helps in understanding and predicting how barometers, and similar liquid systems, behave under varying thermal conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

. Steam What mass of steam at \(100^{\circ} \mathrm{C}\) must be mixed with \(150 \mathrm{~g}\) of ice at its melting point, in a thermally insulated container, to produce liquid water at \(50^{\circ} \mathrm{C} ?\)

At \(20^{\circ} \mathrm{C}\), a rod is exactly \(20.05 \mathrm{~cm}\) long on a steel ruler. Both the rod and the ruler are placed in an oven at \(270^{\circ} \mathrm{C}\), where the rod now measures \(20.11 \mathrm{~cm}\) on the same ruler. What is the coefficient of thermal expansion for the material of which the rod is made?

what temperature do the following pairs of scales read the same, if ever: (a) Fahrenheit and Celsius (verify the listing in Table \(19-1\) ), (b) Fahrenheit and Kelvin, and (c) Celsius and Kelvin?

(a) What is the rate of thermal energy transfer in watts per square meter through a glass window \(3.0 \mathrm{~mm}\) thick if the outside temperature is \(-20^{\circ} \mathrm{F}\) and the inside temperature is \(+72^{\circ} \mathrm{F} ?\) (b) A storm window having the same thickness of glass is installed parallel to the first window, with an air gap of \(7.5 \mathrm{~cm}\) between the two windows. What now is the rate of energy loss if conduction is the only important energytransfer mechanism?

Consider that 200 J of work is done on a system and \(70.0\) cal of thermal energy is trans-ferred out of the system. In the sense of the first law of thermodynamics, what are the values (including algebraic signs) of (a) \(W,(\mathrm{~b})\) \(Q\), and \((\mathrm{c}) \Delta E^{\mathrm{int}} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.