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Identical Except for Phase Two sinusoidal waves, identical except for phase, travel in the same direction along a string and interfere to produce a resultant wave given by \(y^{\prime}(x, t)=(3.0 \mathrm{~mm})\) \(\sin [(20 \mathrm{rad} / \mathrm{m}) x-(4.0 \mathrm{rad} / \mathrm{s}) t+0.820 \mathrm{rad}]\), with \(x\) in meters and \(t\) in seconds. What are (a) the wavelength \(\lambda\) of the two waves, (b) the phase difference between them, and (c) their amplitude \(Y\) ?

Short Answer

Expert verified
λ = 0.314 m, φ = 0.820 rad, Y = 3.0 mm

Step by step solution

01

Identify the general sinusoidal wave equation

The general form of a sinusoidal wave is given by \[ y(x,t) = A \sin(kx - \omega t + \phi) \] where \(A\) is the amplitude, \(k\) is the wave number, \(\omega\) is the angular frequency, and \(\phi\) is the phase constant.
02

Compare the given equation with the general form

The given wave equation is \[ y^{\prime}(x, t) = (3.0 \text{ mm}) \sin [(20 \text{ rad/m}) x - (4.0 \text{ rad/s}) t + 0.820 \text{ rad}] \] From this, we can identify: A = 3.0 mm, k = 20 rad/m, ω = 4.0 rad/s, φ = 0.820 rad.
03

Determine the wavelength λ

The relationship between the wave number \(k\) and the wavelength \(\lambda\) is given by \[ k = \frac{2\pi}{\lambda} \] Therefore, solving for \(\lambda\): \[ \lambda = \frac{2\pi}{k} = \frac{2\pi}{20 \text{ rad/m}} = \frac{\pi}{10} \text{ m} \approx 0.314 \text{ m} \]
04

Identify the phase difference between the two waves

The given wave equation includes a phase constant of \(0.820 \text{ rad}\). This is directly the phase difference between the two waves since they are identical except for phase differences. Therefore: \[ \phi = 0.820 \text{ rad} \]
05

Determine the amplitude Y of the resultant wave

The amplitude of the resultant wave is given directly in the wave equation as \(3.0 \text{ mm}\): \[ Y = 3.0 \text{ mm} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sinusoidal Waves
Understanding sinusoidal waves is key to grasping the problem. A sinusoidal wave is a type of wave that oscillates according to the sine function. This type of wave is common in physics because it describes many natural phenomena, from sound waves to light waves. In general, a sinusoidal wave can be described by the equation: \(y(x,t) = A \sin(kx - \omega t + \phi)\)\.

Here, \(A\) is the amplitude, which indicates the maximum height of the wave. The term \(k\), known as the wave number, determines the number of wavelengths per unit distance. \(\omega\) is the angular frequency, which tells us how quickly the wave oscillates in time. Lastly, \(\phi\) is the phase constant, which shifts the wave along the \(x\) axis.

Whenever we talk about sinusoidal waves, remember this basic form. It will help in understanding more complex behaviors, such as wave interference and phase differences.
Wavelength Calculation
One important property of sinusoidal waves is the wavelength, denoted by \(\lambda\). The wavelength is the distance over which the wave's shape repeats. To find the wavelength, we can use the wave number \(k\) identified in the wave equation.

The relationship between the wave number and the wavelength is: \[k = \frac{2\pi}{\lambda}\]

By rearranging this formula, we can solve for \(\lambda\): \[\lambda = \frac{2\pi}{k}\]

For our specific problem, where \(k = 20 \text{ rad/m}\), the calculation proceeds as follows: \[\lambda = \frac{2\pi}{20 \text{ rad/m}} = \frac{\pi}{10} \text{ m} \approx 0.314 \text{ m}\]

Therefore, the wavelength of the waves is approximately 0.314 meters.
Phase Difference
In wave phenomena, the phase difference plays a critical role in interference patterns. The phase difference \(\phi\) tells us how much one wave is shifted relative to another. If two sinusoidal waves are identical except for this shift, they can still produce interesting results when they interfere.

For our exercise, the phase constant given in the wave equation is \(0.820 \text{ rad}\). This value represents the phase difference between the two waves.

Because the waves are otherwise identical, their phase difference remains \(0.820 \text{ rad}\). Phase differences can lead to either constructive or destructive interference, depending on how the peaks and troughs of the waves align. Constructive interference raises wave amplitude, whereas destructive interference can diminish or cancel it.

Recognizing the importance of phase difference helps in predicting how waves interact and in understanding more complex wave phenomena.

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Most popular questions from this chapter

Sinusoidal Wave Two A sinusoidal wave of frequency \(500 \mathrm{~Hz}\) has a speed of \(350 \mathrm{~m} / \mathrm{s}\). (a) How far apart are two points that differ in phase by \(\pi / 3 \mathrm{rad} ?(\mathrm{~b})\) What is the phase difference between two displacements at a certain point at times \(1.00 \mathrm{~ms}\) apart?

Aluminum Wire In Fig. 17-38, an aluminum wire, of length \(L_{1}=60.0\) \(\mathrm{cm}\), cross-sectional area \(1.00 \times 10^{-2} \mathrm{~cm}^{2}\), and den- sity \(2.60 \mathrm{~g} / \mathrm{cm}^{3}\), is joined to a steel wire, of density \(7.80 \mathrm{~g} / \mathrm{cm}^{3}\) and the same cross-sectional area. The compound wire, loaded with a block of mass \(m=10.0 \mathrm{~kg}\), is arranged so that the distance \(L_{2}\) from the joint to the supporting pulley is \(86.6 \mathrm{~cm} .\) Transverse waves are set up in the wire by using an external source of variable frequency; a node is located at the pulley. (a) Find the lowest frequency of excitation for which standing waves are observed such that the joint in the wire is one of the nodes. (b) How many nodes are observed at this frequency?

Show That Show that $$ \begin{array}{ll} y(x, t)=Y \sin k(x-v t), & y(x, t)=Y \sin 2 \pi\left(\frac{x}{\lambda}-f t\right) \\ y(x, t)=Y \sin \omega\left(\frac{x}{v}-t\right), & y(x, t)=Y \sin 2 \pi\left(\frac{x}{\lambda}-\frac{t}{T}\right) \end{array} $$ are all equivalent to \(y(x, t)=Y \sin (k x-\omega t)\).

Between Fixed Supports A \(125 \mathrm{~cm}\) length of string has a mass of \(2.00 \mathrm{~g}\). It is stretched with a tension of \(7.00 \mathrm{~N}\) between fixed supports. (a) What is the wave speed for this string? (b) What is the lowest resonant frequency of this string?

What Is the Speed What is the speed of a transverse wave in a rope of length \(2.00 \mathrm{~m}\) and mass \(60.0 \mathrm{~g}\) under a tension of \(500 \mathrm{~N}\) ?

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