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The Equation of The equation of a transverse wave on a string is $$ y(x, t)=(2.0 \mathrm{~mm}) \sin [(20 \mathrm{rad} / \mathrm{m}) x-(600 \mathrm{rad} / \mathrm{s}) t] $$ The tension in the string is \(15 \mathrm{~N}\). (a) What is the wave speed? (b) Find the linear density of the string in grams per meter.

Short Answer

Expert verified
Wave speed is 30 m/s. Linear density is 16.7 g/m.

Step by step solution

01

- Identify the Wave Speed Formula

The general form of a wave equation is given by: \[y(x, t) = A \sin(kx - \omega t),\] where \(A\) is the amplitude, \(k\) is the wave number, and \(\omega\) is the angular frequency. Wave speed \(v\) is given by \( v = \frac{\omega}{k} \).
02

- Extract Values from the Wave Equation

From the given equation \[ y(x, t) = (2.0 \text{ mm}) \sin [(20 \text{ rad/m}) x - (600 \text{ rad/s}) t], \] extract the values: \(k = 20 \text{ rad/m}\) and \( \omega = 600 \text{ rad/s} \).
03

- Calculate the Wave Speed

Use the formula \( v = \frac{\omega}{k} \): \[ v = \frac{600 \text{ rad/s}}{20 \text{ rad/m}} = 30 \text{ m/s}. \]
04

- Identify the Formula for Linear Density

The linear density \( \mu \) of a string is given by the formula: \[ \mu = \frac{T}{v^2}, \] where \( T \) is the tension in the string and \( v \) is the wave speed.
05

- Calculate the Linear Density

Given that the tension in the string \( T = 15 \text{ N} \) and wave speed \( v = 30 \text{ m/s} \): \[ \mu = \frac{15 \text{ N}}{(30 \text{ m/s})^2} = \frac{15}{900} \text{ kg/m} = 0.0167 \text{ kg/m} \].
06

- Convert Linear Density to Grams per Meter

Convert the linear density from kg/m to g/m: \[ 0.0167 \text{ kg/m} = 16.7 \text{ g/m}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

wave speed
Understanding the speed of a wave on a string is crucial in many physics problems. The wave speed, denoted by \( v \), is determined by the relationship between the wave's angular frequency \(\omega\) and wave number \(k\). Essentially, wave speed tells us how fast the wave is traveling along the string.

The formula to calculate wave speed is given by:
\[ v = \frac{\omega}{k} \]
From the wave equation \( y(x, t) = (2.0 \, \text{mm}) \sin [(20 \,\text{rad/m}) x - (600 \,\text{rad/s}) t] \), we can extract the values:
  • Wave number \( k = 20 \, \text{rad/m} \)
  • Angular frequency \( \omega = 600 \, \text{rad/s} \)
Plugging these values into our wave speed formula, we get:
\[ v = \frac{600 \, \text{rad/s}}{20 \, \text{rad/m}} = 30 \, \text{m/s} \] This tells us the wave on the string is traveling at a speed of 30 meters per second.
linear density
Linear density is another key concept in understanding waves on a string. It refers to the mass per unit length of the string, which affects how the wave propagates. The symbol for linear density is \( \mu \). Linear density can be found using the formula:
\[ \mu = \frac{T}{v^2} \] where \( T \) is the tension in the string and \( v \) is the wave speed.

Given in our problem, we have:
  • Tension \( T = 15 \, \text{N} \)
  • Wave speed \( v = 30 \, \text{m/s} \)
Using the formula, we calculate:
\[ \mu = \frac{15 \,\text{N}}{(30 \, \text{m/s})^2} = \frac{15}{900} \text{ kg/m} = 0.0167 \, \text{kg/m} \]
To convert this to grams per meter (g/m):
\[ 0.0167 \, \text{kg/m} = 16.7 \, \text{g/m} \] This means the string's linear density is 16.7 grams per meter.
wave equation
The wave equation is the fundamental mathematical description of how waves move on a string. Generally, a transverse wave on a string can be described by:
\[ y(x, t) = A \sin(kx - \omega t) \]
Here, \( y(x, t) \) is the displacement at any point \( x \) and time \( t \). The parameters in the equation include:
  • Amplitude \( A \): The maximum displacement from the rest position (2.0 mm in our problem).
  • Wave number \( k \): Describes the number of wave cycles per unit distance (20 rad/m in our problem).
  • Angular frequency \( \omega \): Describes how quickly the wave oscillates in time (600 rad/s in our problem).

Combining these parameters gives a complete description of the wave's behavior in space and time, allowing us to analyze and predict the movement of the wave as it propagates along the string.

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Most popular questions from this chapter

Displacement of Particles A sinusoidal wave is traveling on a string with speed \(40 \mathrm{~cm} / \mathrm{s}\). The displacement of the particles of the string at \(x=10 \mathrm{~cm}\) is found to vary with time according to the equation \(y(x, t)=(5.0 \mathrm{~cm}) \sin [1.0 \mathrm{rad} / \mathrm{cm}-(4.0 \mathrm{rad} / \mathrm{s}) t] .\) The linear density of the string is \(4.0 \mathrm{~g} / \mathrm{cm} .\) What are the (a) frequency and (b) wavelength of the wave? (c) Write the general equation giving the transverse displacement of the particles of the string as a function of position and time. (d) Calculate the tension in the string.

Three-Loop Standing Wave A string \(3.0 \mathrm{~m}\) long is oscillating as a three-loop standing wave with an amplitude of \(1.0 \mathrm{~cm}\). The wave speed is \(100 \mathrm{~m} / \mathrm{s}\). (a) What is the frequency? (b) Write equations for two waves that, when combined, will result in this standing wave.

A String Under Tension A string under tension \(F^{\text {tension }}\) oscillates in the third harmonic at frequency \(f_{3}\), and the waves on the string have wavelength \(\lambda_{3} .\) If the tension is increased to \(\tau_{f}=4 \tau_{i}\) and the string is again made to oscillate in the third harmonic, what then are (a) the frequency of oscillation in terms of \(f_{3}\) and (b) the wavelength of the waves in terms of \(\lambda_{3} ?\)

Moving a Nonsymmetric Triangular Pulse A long taut spring is started at a time \(t=0\) with a pulse moving in the \(+x\) direction in the shape given by the function \(f(x)\) with $$ f(x)=\left\\{\begin{array}{ll} \frac{1}{4} x+1 & -4

Three Lowest Frequencies What are the three lowest frequencies for standing waves on a wire \(10.0 \mathrm{~m}\) long having a mass of \(100 \mathrm{~g}\), which is stretched under a tension of \(250 \mathrm{~N} ?\)

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